C程序设计习题参考答案.pdf

C 程序设计程序设计 习题参考答案 真真印印良良品品 http www TrueM 第第 1 页页 P113 8 百分制成绩转换为等级制成绩百分制成绩转换为等级制成绩 程序 1 include int main float score char grade printf Please enter score scanf f while score 100 score 0 printf nError please reenter scanf f switch int score 10 case 10 case 9 grade A break case 8 grade B break case 7 grade C break case 6 grade D break case 5 case 4 case 3 case 2 case 1 case 0 grade E printf The score is 5 1f grade is c n score grade return 0 C 程序设计程序设计 习题参考答案 真真印印良良品品 http www TrueM 第第 2 页页 程序 2 include void main float score char grade printf Please input the score scanf f if score 100 printf Input data error n exit 0 if score 90 grade A else if score 80 grade B else if score 70 grade C else if score 60 grade D else grade E printf Grade is c n grade C 程序设计程序设计 习题参考答案 真真印印良良品品 http www TrueM 第第 3 页页 P113 9 不多于不多于 5 位的正整数输出位的正整数输出 程序程序 1 include include int main int num n1 n2 n3 n4 n5 place printf Please enter an integer 0 99999 scanf d if num 9999 place 5 else if num 999 place 4 else if num 99 place 3 else if num 9 place 2 else place 1 printf Number of digit is d n place printf Each digit is n5 num 10000 n4 int num n5 10000 1000 n3 int num n5 10000 n4 1000 100 n2 int num n5 10000 n4 1000 n3 100 10 n1 int num n5 10000 n4 1000 n3 100 n2 10 switch place case 5 printf d d d d d n5 n4 n3 n2 n1 printf nThe anti digit is printf d d d d d n n1 n2 n3 n4 n5 break case 4 printf d d d d n4 n3 n2 n1 printf nThe anti digit is printf d d d d n n1 n2 n3 n4 break case 3 printf d d d n3 n2 n1 printf nThe anti digit is printf d d d n n1 n2 n3 break case 2 printf d d n2 n1 printf nThe anti digit is printf d d n n1 n2 break case 1 printf d n1 printf nThe anti digit is printf d n n1 break C 程序设计程序设计 习题参考答案 真真印印良良品品 http www TrueM 第第 4 页页 return 0 程序 2 include void main long int number int ge shi bai qian wan count printf please input a number 0 99999 scanf ld if number 99999 printf number error n exit 0 if number 9999 count 5 else if number 999 count 4 else if number 99 count 3 else if number 9 count 2 else count 1 ge number 10 number 10 shi number 10 number 10 bai number 10 number 10 qian number 10 number 10 wan number 10 printf count d n count switch count case 1 printf number is d n ge printf inverse is d n ge break case 2 printf number is d d n shi ge printf inverse is d d n ge shi break case 3 printf number is d d d n bai shi ge printf inverse is d d d n ge shi bai break case 4 printf number is d d d d n qian bai shi ge printf inverse is d d d d n ge shi bai qian break case 5 printf number is d d d