九组交通规划课程设计

交通规划课程设计任务书第9条赵元：后面的风王凯薛曼宗一个使用以下不受约束的重力模型如果从两侧获取日志Y=、=、邮报二次方程是二进制线性回归方程，对于要校正的系数，通过表1所示的已知表获得25个样本数据。表1取样点Qij大分DjOiDjCijyX1X2I=1，j=112002530242057.15.1.I=1，j=260025303080106.15.2.I=1，j=335025302300185.15.2.I=1，j=425025301650205.15.2.I=1，j=513025301070304.14.3.I=2，j=150031902420126.15.2.I=2，j=217503190308047.16.1.I=2，j=360031902300106.15.2.I=2，j=414031901650254.15.3.I=2，j=520031901070205.15.2.I=3，j=142021602420156.15.2.I=3，j=240021603080105.15.2.I=3，j=39002160230086.15.2.I=3，j=436021601650155.15.2.I=3，j=58021601070354.14.3.I=4，j=120016402420205.15.2.I=4，j=219016403080255.15.3.I=4，j=337016402300155.15.2.I=4，j=480016401650106.14.2.I=4，j=58016401070304.14.3.I=5，j=110010002420354.14.3.I=5，j=214010003080254.14.3.I=5，j=38010002300354.14.3.I=5，j=410010001650354.14.3.I=5，j=558010001070126.13.2.使用最小二乘法校正了25个样例数据，结果=1.633，=0.244，=1.137获得了二进制线性回归方程。您可以透过=、使用、也就是说，修正后的重力模型是用标定重力模型解决分布交通量Oi*Dj(oi * DJ) 0.244Cij (-1.137)Qij45.0.1444.6301348.0.3369.44.0.6121.41.0.6363.37.0.9078.47.0.4136.3794350.0.1258.47.0.3320.43.0.8678.39.0.6058.43.0.4847.46.0.3242.43.0.2342.39.0.4414.35.0.10488.715540.0.6285.782843.0.8592.40.0.4476.37.0.2603.33.0.8167.36.0.10526.2027938.0.7615.35.0.10396.385132.0.9587.29.0.2553.od12345总计11444.6303369.6386121.8586363.7639078.902263378.79124136.3791258.0243320.4888678.8906058.723234522.50434847.1773242.1162342.5944414.72810488.71625255.33146285.7838592.1434476.2532603.1758167.58830114.942510526.2037615.17010396.3869587.0912553.96040678.81总计27240.17224077.09126657.57931647.647363667.889.378重新计算和5500263378.791480027240.1720.0.4800234522.504500024077.0910.0.350025255.331400026657.5790.0.300030114.942300031647.6470.0.240040678.812400363667.8890.0.通过无约束重力模型计算的OD表不满足移动分布的约束条件，因此必须使用平均增长系数法迭代。使用平均增长系数方法的第一次迭代计算OD表O D12345总计增长系数1277.883701.1661097.502965.0481246.8744288.4731.28252787.731259.364588.9221299.502820.4823756.0011.2283762.933561.293338.078515.1511065.6383243.0931.07924866.7961319.975558.718253.001676.9283675.4180.816251237.9291015.351086.682737.212159.8434237.0160.5664总计3933.2723857.1483669.9023769.9143969.76519200.001增长系数1.22041.29631.08990.79580.6046使用平均增长系数法的第二次迭代计算OD表55004288.47348003933.2721.1.48003756.00150003857.1481.1.35003243.09340003669.9021.1.30003675.41830003769.9140.0.24004237.01624003969.7650.0.O D12345总计增长系数1347.752904.0841301.8871002.8211176.4744733.0181.1622983.999333.834697.2551347.406772.2894134.7831.16093877.211666.679366.673482.952897.1533290.6681.06364882.6551394.242532.509203.92408.8913422.2170.876651105.962945.662899.981502.11993.5893547.3130.6766总计4197.5794244.5013798.3053539.2183348.39619127.999增长系数1.14351.1781.05310.84760.7167使用平均增长系数法的第三次迭代计算OD表55004733.01848004197.5791.1.48004134.78350004244.5011.1.35003290.66840003798.3051.1.30003422.21730003539.2180.0.24003547.31324003348.3960.0.O D12345总计增长系数1400.8831057.7981441.9381007.6821105.1865013.4871.09721133.763390.398771.856775.582725.0423796.6411.26433968.059747.217388.071461.523798.6343363.5041.04064891.5441432.318513.798175.807325.7613339.2280.898451006.472876.895778.335382.66865.23109.570.7718总计4400.7214504.6263893.9982803.2623019.82318622.43增长系数1.09071.111.02721.07010.7947使用平均增长系数法的第四个迭代计算OD表55005013.48748004400.7211.1.48003796.64150004504.6261.1.35003363.50440003893.9981.1.30003339.22830002803.2620.1.24003109.5724003019.8230.0.O D12345总计增长系数1438.521167.2861531.5281091.9361045.395274.661.042721335.009463.45884.353905.282746.4394334.5331.107431031.618803.464401.227487.023732.8783456.211.01274886.7041438.32494.693173.046275.7833268.5460.91785937.298825.062700.125352.43651.072865.9910.8374总计4629.1494697.5824011.9263009.7232851.5619199.94增长系数1.03691.06440.9970.99680.8416在第四次迭代后，收敛条件设置=10%满足停止迭代，在第四次迭代