英文原版教材班“材料科学基础”考试试题

英文原版教材班“材料科学基础”考试试题试卷一EXAMINATIONPROBLEMSOFTHECOURSEOF“FUNDAMENTOFMATERIALSSCIENCE”姓名班级记分1GLOSSARY2POINTSFOREACH1CRYSTALSTRUCTURE2BASISORMOTIF3PACKINGFRACTOR4SLIPSYSTEM5CRITICALSIZE6HOMOGENEOUSNUCLEATION7COHERENTPRECIPITATE8PRECIPITATIONHARDENING9DIFFUSIONCOEFFICIENT10UPHILLDIFFUSION2DETERMINETHEINDICESFORTHEPLANESINTHECUBICUNITCELLSHOWNINFIGURE15POINTSFIG13DETERMINETHECRYSTALSTRUCTUREFORTHEFOLLOWINGAAMETALWITHA049489,R175ANDONEATOMPERLATTICEPOINTBAMETALWITHA0042906NM,R01858NMANDONEATOMPERLATTICEPOINT10POINTS41WHATISTHECHARACTERISTICOFBRINELLHARDNESSTEST,ROCKWELLHARDNESSTESTANDVICKERSHARDNESSTESTWHATARETHEEFFECTSOFSTRAINRATEANDTEMPERATUREONTHEMECHANICALPROPERTIESOFMETALLICMATERIALS15POINTS42WHATARETHEEFFECTSOFCOLDWORKONMETALLICMATERIALSHOWTOELIMINATETHOSEEFFECTSANDWHATISMICROMECHANISMFORTHEELIMINATINGCOLDWORKEFFECTS15POINTS51BASEDONTHEPBSNBITERNARYDIAGRAMASSHOWNINFIG2,TRYTO1SHOWTHEVERTICALSECTIONOF40WTSN4POINTS2DESCRIBETHESOLIDIFICATIONPROCESSOFTHEALLOY2WITHVERYLOWCOOLINGSPEEDINCLUDINGPHASEANDMICROSTRUCTURECHANGES4POINTS3PLOTTHEISOTHERMALSECTIONAT150OC7POINTSFIG252A1MMSHEETOFFCCIRONISUSEDTOCONTAINN2INAHEATEDEXCHANGERAT1200OCTHECONCENTRATIONOFNATONESURFACEIS004ATOMICPERCENTANDTHECONCENTRATIONATTHESECONDSURFACEIS0005ATOMICPERCENTAT1000OC,IFSAMENCONCENTRATIONISDEMANDEDATTHESECONDSURFACEANDTHEFLUXOFNBECOMESTOHALFOFTHATAT1200OC,THENWHATISTHETHICKNESSOFSHEET15POINTS61SUPPOSEDTHATACERTAINLIQUIDMETALISUNDERCOOLEDUNTILHOMOGENEOUSNUCLEATIONOCCURS15POINTS1HOWTOCALCULATETHECRITICALRADIUSOFTHENUCLEUSREQUIREDPLEASEGIVETHEDEDUCTIONPROCESS2FORTHEMETALNI,THEFREEZINGTEMPERATUREIS1453C,THELATENTHEATOFFUSIONIS2756J/CM3,ANDTHESOLIDLIQUIDINTERFACIALENERGYIS255107J/CM2PLEASECALCULATETHECRITICALRADIUSAT1353CASSUMETHATTHELIQUIDNIISNOTSOLIDIFIED62FIG3ISAPORTIONOFTHEMGALPHASEDIAGRAM15POINTS1IFTHESOLIDIFICATIONISTOORAPID,PLEASEDESCRIBETHESOLIDIFICATIONPROCESSOFMG10WTALALLOY2PLEASEDESCRIBETHEEQUILIBRIUMSOLIDIFICATIONPROCESSOFMG20WTALALLOY,ANDCALCULATETHEAMOUNTOFEACHPHASEAT300CFIG371FIGURE4SHOWSUSTHEALCUBINARYDIAGRAMANDSOMEMICROSTRUCTURESFOUNDINACOOLINGPROCESSFORANAL4CUALLOYPLEASEANSWERFOLLOWINGQUESTIONSACCORDINGTOTHISFIGURE20POINTSFIG41WHATAREPRECIPITATE,MATRIXANDMICROCONSTITUENTPLEASEPOINTTHEMOUTINTHEINTHEFIGUREANDEXPLAIN2WHYISNEEDLIKEPRECIPITATENOTGOODFORDISPERSIONSTRENGTHENINGTHETYPICALMICROSTRUCTURESHOWNINTHEFIGUREISGOODORNOTWHY3PLEASETELLUSHOWTOOBTAINTHEIDEALMICROSTRUCTURESHOWNINTHISFIGURE4CANDISPERSIONSTRENGTHENEDMATERIALSBEUSEDATHIGHTEMPERATUREPLEASEGIVETHEREASONSCOMPARINGWITHCOLDWORKINGSTRENGTHENING72PLEASEANSWERFOLLOWINGQUESTIONSACCORDINGTOTHETIMETEMPERATURETRANSFORMATIONTTTDIAGRAMASSHOWNINFIG520POINTS1WHATSTEELISTHISTTTDIAGRAMFORANDWHATMEANSP,B,ANDMINTHEFIGURE2WHYDOSETHETTTDIAGRAMEXHIBITSACSHAPE3POINTOUTWHATMICROCONSTITUENTWILLBEOBTAINEDAFTERAUSTENITEISCOOLEDACCORDINGTOTHECURVESI,II,IIIANDIV4WHATISMICROSTRUCTURALDIFFERENCEBETWEENTHECURVEIANDTHECURVEII5HOWTOOBTAINTHESTEELWITHTHESTRUCTUREOFAPBBPMARESIDUALCPBMARESIDUALDFULLTEMPEREDMARTENSITEIFYOUCAN,PLEASEDRAWTHERELATIVECOOLINGCURVEORTHEFLOWCHARTOFHEATTREATMENTFIG5IIIIIIIV英文原版教材班“材料科学基础”考试试题答案SOLUTIONSOFTHECOURSEOF“FUNDAMENTOFMATERIALSSCIENCE”1GLOSSARY2POINTSFOREACH1THEARRANGEMENTOFTHEATOMSINAMATERIALINTOAREPEATABLELATTICE2AGROUPOFATOMSASSOCIATEDWITHALATTICE3THEFRACTIONOFSPACEINAUNITCELLOCCUPIEDBYATOMS4THECOMBINATIONOFTHESLIPPLANEANDTHESLIPDIRECTION5THEMINIMUMSIZETHATMUSTBEFORMEDBYATOMSCLUSTERINGTOGETHERINTHELIQUIDBEFORETHESOLIDPARTICLEISSTABLEANDBEGINSTOGROW6FORMATIONOFACRITICALLYSIZEDSOLIDFROMTHELIQUIDBYTHECLUSTERINGTOGETHEROFALARGENUMBEROFATOMSATAHIGHUNDERCOOLINGWITHOUTANEXTERNALINTERFACE7APRECIPITATEWHOSECRYSTALSTRUCTUREANDATOMICARRANGEMENTHAVEACONTINUOUSRELATIONSHIPWITHMATRIXFROMWHICHPRECIPITATEISFORMED8ASTRENGTHENINGMECHANISMTHATRELIESONASEQUENCEOFSOLIDSTATEPHASETRANSFORMATIONSINADISPERSIONOFULTRAFINEPRECIPITATESOFA2NDPHASETHISISSAMEASAGEHARDENINGITISAFORMOFDISPERSIONSTRENGTHENING9ATEMPERATUREDEPENDENTCOEFFICIENTRELATEDTOTHERATEATWHICHATOM,ION,OROTHERSPECIESDIFFUSIONTHEDCDEPENDSONTEMPERATURE,THECOMPOSITIONANDMICROSTRUCTUREOFTHEHOSTMATERIALANDALSOCONCENTRATIONOFTHEDIFFUSIONSPECIES10ADIFFUSIONPROCESSINWHICHSPECIESMOVEFROMREGIONSOFLOWERCONCENTRATIONTOTHATOFHIGHERCONCENTRATION2SOLUTIONA364,B340,C3463SOLUTIONAFCCBBCC41WHATISTHECHARACTERISTICOFBRINELLHARDNESSTEST,ROCKWELLHARDNESSTESTANDVICKERSHARDNESSTESTWHATARETHEEFFECTSOFSTRAINRATEANDTEMPERATUREONTHEMECHANICALPROPERTIESOFMETALLICMATERIALS15POINTS42WHATARETHEEFFECTSOFCOLDWORKONMETALLICMATERIALSHOWTOELIMINATETHOSEEFFECTSANDWHATISMICROMECHANISMFORTHEELIMINATINGCOLDWORKEFFECTS15POINTS51BASEDONTHEPBSNBITERNARYDIAGRAMASSHOWNINFIG2,TRYTO1SHOWTHEVERTICALSECTIONOF40WTSN5POINTS2DESCRIBETHESOLIDIFICATIONPROCESSOFTHEALLOY2WITHVERYLOWCOOLINGSPEEDINCLUDINGPHASEANDMICROSTRUCTURECHANGES5POINTS3PLOTTHEISOTHERMALSECTIONAT150OC5POINTSFIG252A1MMSHEETOFFCCIRONISUSEDTOCONTAINN2INAHEATEDEXCHANGERAT1200OCTHECONCENTRATIONOFNATONESURFACEIS004ATOMICPERCENTANDTHECONCENTRATIONATTHESECONDSURFACEIS0005ATOMICPERCENTAT1000OC,IFSAMENCONCENTRATIONISDEMANDEDATTHESECONDSURFACEANDTHEFLUXOFNBECOMESTOHALFOFTHATAT1200OC,THENWHATISTHETHICKNESSOFSHEET15POINTS61SUPPOSEDTHATACERTAINLIQUIDMETALISUNDERCOOLEDUNTILHOMOGENEOUSNUCLEATIONOCCURS15POINTS3HOWTOCALCULATETHECRITICALRADIUSOFTHENUCLEUSREQUIREDPLEASEGIVETHEDEDUCTIONPROCESS4FORTHEMETALNI,THEFREEZINGTEMPERATUREIS1453C,THELATENTHEATOFFUSIONIS2756J/CM3,ANDTHESOLIDLIQUIDINTERFACIALENERGYIS255107J/CM2PLEASECALCULATETHECRITICALRADIUSAT1353CASSUMETHATTHELIQUIDNIISNOTSOLIDIFIED62FIG3ISAPORTIONOFTHEMGALPHASEDIAGRAM15POINTS3IFTHESOLIDIFICATIONISTOORAPID,PLEASEDESCRIBETHESOLIDIFICATIONPROCESSOFMG10WTALALLOY4PLEASEDESCRIBETHEEQUILIBRIUMSOLIDIFICATIONPROCESSOFMG20WTALALLOY,ANDCALCULATETHEAMOUNTOFEACHPHASEAT300CFIG371FIGURE4SHOWSUSTHEALCUBINARYDIAGRAMANDSOMEMICROSTRUCTURESFOUNDINACOOLINGPROCESSFORANAL4CUALLOYPLEASEANSWERFOLLOWINGQUESTIONSACCORDINGTOTHISFIGURE20POINTSFIG41WHATAREPRECIPITATE,MATRIXANDMICROCONSTITUENTPLEASEPOINTTHEMOUTINTHEINTHEFIGUREANDEXPLAIN2WHYISNEEDLIKEPRECIPITATENOTGOODFORDISPERSIONSTRENGTHENINGTHETYPICALMICROSTRUCTURESHOWNINTHEFIGUREISGOODORNOTWHY3PLEASETELLUSHOWTOOBTAINTHEIDEALMICROSTRUCTURESHOWNINTHISFIGURE4CANDISPERSIONSTRENGTHENEDMATERIALSBEUSEDATHIGHTEMPERATUREPLEASEGIVETHEREASONSCOMPARINGWITHCOLDWORKINGSTRENGTHENING72PLEASEANSWERFOLLOWINGQUESTIONSACCORDINGTOTHETIMETEMPERATURETRANSFORMATIONTTTDIAGRAMASSHOWNINFIG520POINTS1WHATSTEELISTHISTTTDIAGRAMFORANDWHATMEANSP,B,ANDMINTHEFIGURE2WHYDOSETHETTTDIAGRAMEXHIBITSACSHAPE3POINTOUTWHATMICROCONSTITUENTWILLBEOBTAINEDAFTERAUSTENITEISCOOLEDACCORDINGTOTHECURVESI,II,IIIANDIV4WHATISMICROSTRUCTURALDIFFERENCEBETWEENTHECURVEIANDTHECURVEII5HOWTOOBTAINTHESTEELWITHTHESTRUCTUREOFAPBBPMARESIDUALCPBMARESIDUALDFULLTEMPEREDMARTENSITEIFYOUCAN,PLEASEDRAWTHERELATIVECOOLINGCURVEORTHEFLOWCHARTOFHEATTREATMENTFIG5IIIIIIIV英文原版教材班“材料科学基础”考试试题试卷二EXAMINATIONPROBLEMSOFTHECOURSEOF“FUNDAMENTOFMATERIALSSCIENCE”姓名班级记分1YOUWOULDLIKETOBEABLETOPHYSICALLYSEPARATEDIFFERENTMATERIALSINASCRAPRECYCLINGPLANTDESCRIBESOMEPOSSIBLEMETHODSTHATMIGHTBEUSEDTOSEPARATEMATERIALSSUCHASPOLYMERS,ALUMINUMALLOYS,ANDSTEELSFROMONEANOTHER5POINTS2PLOTTHEMELTINGTEMPERATUREOFTHEELEMENTSINTHE1ACOLUMNOFTHEPERIODICTABLEVERSUSATOMICNUMBERIE,PLOTMELTINGTEMPERATURESOFLITHROUGHCSDISCUSSTHISRELATIONSHIP,BASEDONATOMICBONDINGANDBINDINGENERGY10POINTS3ABOVE882,TITANIUMHASABCCCRYSTALSTRUCTURE,WITHA0332NMBELOWTHISTEMPERATURE,TITANIUMHASAHCPSTRUCTURE,WITHA02978NMANDC04735NMDETERMINETHEPERCENTVOLUMECHANGEWHENBCCTITANIUMTRANSFORMSTOHCPTITANIUMISTHISACONTRACTIONOREXPANSION10POINTS4THEDENSITYOFBCCIRONIS7882G/CM3ANDTHELATTICEPARAMETERIS02866NMWHENHYDROGENATOMSAREINTRODUCEDATINTERSTITIALPOSITIONSCALCULATEATHEATOMICFRACTIONOFHYDROGENATOMSANDBTHENUMBEROFUNITCELLSREQUIREDONAVERAGETOCONTAINONEHYDROGENATOM15POINTS5ACARBURIZINGPROCESSISCARRIEDOUTONA010CSTEELBYINTRODUCING10CATTHESURFACEAT980,WHERETHEIRONISFCCCALCULATETHECARBONCONTENTAT001CM,005CM,AND010CMBENEATHTHESURFACEAFTER1H15POINTS6THEFOLLOWINGDATAWERECOLLECTEDFROMASTANDARD0505INDIAMETERTESTSPECIMENOFACOPPERALLOYINITIALLENGTHTO20INLOADGAGELENGTHSTRESSSTRAINLBINPSIIN/IN02000000003,00020016715,00000008356,00020033330,00000016657,50020041737,50000020859,0002009045,0000004510,500204052,50000212,00022660,00001312,400250MAXLOAD62,00002511,400302FRACTURE57,000051AFTERFRACTURE,THEGAGELENGTHIS3014INANDTHEDIAMETERIS0374INPLOTTHEDATAANDCALCULATEATHE02OFFSETYIELDSTRENGTH,BTHETENSILESTRENGTH,CTHEMODULUSOFELASTICITY,DTHEELONGATION,ETHEREDUCTIONINAREA,FTHEENGINEERINGSTRESSATFRACTURE,GTHETRUESTRESSATFRACTURE,ANDHTHEMODULUSOFRESILIENCE15POINTS7A15EMDIAMETERMETALBARWITHA3CMGAGELENGTHISSUBJECTEDTOATENSILETESTTHEFOLLOWINGMEASUREMENTSAREMADECHANGEINFORCENGAGELENGTHCMDIAMETERCM16,240066421202819,066147541088419,2732466309848DETERMINETHESTRAINHARDENINGCOEFFICIENTFORTHEMETALISTHEMETALMOSTLIKELYTOBEFCC,BCC,ORHCPEXPLAIN15POINTS8BASEDONHUMEROTHERYSCONDITIONS,WHICHOFTHEFOLLOWINGSYSTEMSWOULDBEEXPECTEDTODISPLAYUNLIMITEDSOLIDSOLUBILITYEXPLAIN15POINTSAAUAGBALCUCALAUDUWEMOTAFNBWGMGZNHMGCD英文原版教材班“材料科学基础”考试试题答案SOLUTIONSOFTHECOURSEOF“FUNDAMENTOFMATERIALSSCIENCE”1STEELSCANBEMAGNETICALLYSEPARATEDFROMTHEOTHERMATERIALSSTEELORCARBONCONTAININGIRONALLOYSAREFERROMAGNETICANDWILLBEATTRACTEDBYMAGNETSDENSITYDIFFERENCESCOULDBEUSEDPOLYMERSHAVEADENSITYNEARTHATOFWATERTHESPECIFICGRAVITYOFALUMINUMALLOYSISAROUND27THATOFSTEELSISBETWEEN75AND8ELECTRICALCONDUCTIVITYMEASUREMENTSCOULDBEUSEDPOLYMERSAREINSULATORS,ALUMINUMHASAPARTICULARLYHIGHELECTRICALCONDUCTIVITY5POINTS2TOCLI1807NA978K632RB389ASTHEATOMICNUMBERINCREASES,THEMELTINGTEMPERATUREDECREASES,10POINTS3WECANFINDTHEVOLUMEOFEACHUNITCELLTWOATOMSAREPRESENTINBOTHBCCANDHCPTITANIUMUNITCELLS,SOTHEVOLUMESOFTHEUNITCELLSCANBEDIRECTLYCOMPAREDVBCC0332NM3003659NM3VHCP02978NM204735NMCOS30003637NM3VX10010006THEREFORETITANIUMCONTRACTS06DURINGCOOLING10POINTS4A7882G/CM3X00081HATOMS/CELLTHETOTALATOMSPERCELLINCLUDE2FEATOMSAND00081HATOMSTHUS10POINTSBSINCETHEREIS00081H/CELL,THENTHENUMBEROFCELLSCONTAININGHATOMSISCELLS1/000811235OR1HIN1235CELLS5POINTS5D023EXP32,900/1987125342108CM2/SCX087CCX043CCX018C15POINTS6FI/405052F/02L2/2A02OFFSETYIELDSTRENGTH45,000PSIBTENSILESTRENGTH62,000PSICE30,0000/0001665018X106PSIDELONGATIONEREDUCTIONINAREAFENGINEERINGSTRESSATFRACTURE57,000PSIGTRUESTRESSATFRACTURE11,400LB/TC/403742103,770PSIHFROMTHEGRAPH,YIELDINGBEGINSATABOUT37,500PSITHUS15POINTS7FORCELBGAGELENGTHINDIAMETERINTRUESTRESSPSITRUESTRAINPSI16,2403664212028143020019,0664475410884205040019,2735466398482490600TKT2ORLN143LNKNLN02LN249LNKNLN06N051ASTRAINHARDENINGCOEFFICIENTOF051ISTYPICALOFFCCMETALS15POINTS8THEAUAG,MOTA,ANDMGCDSYSTEMSHAVETHEREQUIREDRADIUSRATIO,THESAMECRYSTALSTRUCTURES,ANDTHESAMEVALENCESEACHOFTHESEMIGHTBEEXPECTEDTODISPLAYCOMPLETESOLIDSOLUBILITYTHEAUAGANDMOTADOHAVEISOMORPHOUSPHASEDIAGRAMSINADDITION,THEMGCDALLOYSALLSOLIDIFYLIKEISOMORPHOUSALLOYSHOWEVERANUMBEROFSOLIDSTATEPHASETRANSFORMATIONSCOMPLICATETHEDIAGRAM15POINTS英文原版教材班“材料科学基础”考试试题试卷三EXAMINATIONPROBLEMSOFTHECOURSEOF“FUNDAMENTOFMATERIALSSCIENCE”姓名班级记分1YOUWOULDLIKETOBEABLETOIDENTIFYDIFFERENTMATERIALSWITHOUTRESORTINGTOCHEMICALANALYSISORLENGTHYTESTINGPROCEDURESDESCRIBESOMEPOSSIBLETESTINGANDSORTINGTECHNIQUESYOUMIGHTBEABLETOUSEBASEDONTHEPHYSICALPROPERTIESOFMATERIALS5POINTS2PLOTTHEMELTINGTEMPERATURESOFELEMENTSINTHE4ATO810COLUMNSOFTHEPERIODICTABLEVERSUSATOMICNUMBERIE,PLOTMELTINGTEMPERATURESOFTITHROUGHNI,ZRTHROUGHPD,ANDHFTHROUGHPTDISCUSSTHESERELATIONSHIPS,BASEDONATOMICBONDINGANDBINDINGENERGY,AASTHEATOMICNUMBERINCREASESINEACHROWOFTHEPERIODICTABLEANDBASTHEATOMICNUMBERINCREASESINEACHCOLUMNOFTHEPERIODICTABLE10POINTS3BERYLLIUMHASAHEXAGONALCRYSTALSTRUCTURE,WITHAO022858NMANDCO035842NMTHEATOMICRADIUSIS01143NM,THEDENSITYIS1848G/CM3,ANDTHEATOMICWEIGHTIS901G/MOLDETERMINEATHENUMBEROFATOMSINEACHUNITCELLANDBTHEPACKINGFACTORINTHEUNITCELL10POINTS4SUPPOSEWEINTRODUCEONECARBONATOMFOREVERY100IRONATOMSINANINTERSTITIALPOSITIONINBCCIRON,GIVINGALATTICEPARAMETEROF02867NMFORTHEFECALLOY,FINDATHEDENSITYANDBTHEPACKINGFACTOR15POINTS5IRONCONTAINING005CISHEATEDTO912OCINANATMOSPHERETHATPRODUCES120CATTHESURFACEANDISHELDFOR24HCALCULATETHECARBONCONTENTAT005CMBENEATHTHESURFACEIFATHEIRONISBCCANDBTHEIRONISFCCEXPLAINTHEDIFFERENCE15POINTS6THEFOLLOWINGDATAWERECOLLECTEDFROMA04INDIAMETERTESTSPECIMENOFPOLYVINYLCHLORIDEL020INLOADLBGAGELENGTHINSTRESSPSISTRAININ/IN02000000003002007462,3870003736002014964,7730007489002023747,160001187120020329,54700161500204611,933002316602070MAXLOAD13,20600351600209412,72900471420212FRACTURE11,297006AFTERFRACTURE,THEGAGELENGTHIS209INANDTHEDIAMETERIS0393INPLOTTHEDATAANDCALCULATEATHE02OFFSETYIELDSTRENGTH,BTHETENSILESTRENGTH,CTHEMODULUSOFELASTICITY,DTHEELONGATION,ETHEREDUCTIONINAREA,FTHEENGINEERINGSTRESSATFRACTURE,GTHETRUESTRESSATFRACTURE,ANDHTHEMODULUSOFRESILIENCE15POINTS7ATITANIUMALLOYCONTAINSAVERYFINEDISPERSIONOFTINYER203PARTICLESWHATWILLBETHEEFFECTOFTHESEPARTICLESONTHEGRAINGROWTHTEMPERATUREANDTHESIZEOFTHEGRAINSATANYPARTICULARANNEALINGTEMPERATUREEXPLAIN15POINTS8SUPPOSE1ATOFTHEFOLLOWINGELEMENTSISADDEDTOCOPPERFORMINGASEPARATEALLOYWITHEACHELEMENTWITHOUTEXCEEDINGTHESOLUBILITYLIMITWHICHONEWOULDBEEXPECTEDTOGIVETHEHIGHERSTRENGTHALLOYISANYOFTHEALLOYINGELEMENTSEXPECTEDTOHAVEUNLIMITEDSOLIDSOLUBILITYINCOPPERAAUBMNCSRDSIECO15POINTS英文原版教材班“材料科学基础”考试试题答案SOLUTIONSOFTHECOURSEOF“FUNDAMENTOFMATERIALSSCIENCE”1STEELSCANBEMAGNETICALLYSEPARATEDFROMTHEOTHERMATERIALSSTEELORCARBONCONTAININGIRONALLOYSAREFERROMAGNETICANDWILLBEATTRACTEDBYMAGNETSDENSITYDIFFERENCESCOULDBEUSEDPOLYMERSHAVEADENSITYNEARTHATOFWATERTHESPECIFICGRAVITYOFALUMINUMALLOYSISAROUND27THATOFSTEELSISBETWEEN75AND8ELECTRICALCONDUCTIVITYMEASUREMENTSCOULDBEUSEDPOLYMERSAREINSULATORS,ALUMINUMHASAPARTICULARLYHIGHELECTRICALCONDUCTIVITY5POINTS2TI1668ZR1852HF2227V1900NB2468TA2996CR1875MO2610W3410MN1244TC2200RE3180FE1538RU2310OS2700CO1495RH1963IR2447NI1453PD1552PT1769FOREACHROW,THEMELTINGTEMPERATUREISHIGHESTWHENTHEOUTER“D”ENERGYLEVELISPARTLYFULLINCR,THEREARE5ELECTRONSINTHE3DSHELLINMO,THEREARE5ELECTRONSINTHE4DSHELLINWTHEREARE4ELECTRONSINTHE5DSHELLINEACHCOLUMN,THEMELTINGTEMPERATUREINCREASESASTHEATOMICNUMBERINCREASESTHEATOMCORESCONTAINALARGERNUMBEROFTIGHTLYHELDELECTRONS,MAKINGTHEMETALSMORESTABLE10POINTS3V022858NM2035842NMCOS30001622NM316221024CM3AFROMTHEDENSITYEQUATION1848G/CM3X2ATOMS/CELLBTHEPACKINGFACTORPFISPF07710POINTS4THEREISONECARBONATOMPER100IRONATOMS,OR1C/50UNITCELLS,OR1/50CPERUNITCELLAB15POINTS5T24H3600S/H86,400SDBCC0011EXP20,900/19871185154106CM2/SDFCC023EXP32,900/19871185197107CM2/SBCCERF006850077CX111CFCCERF019202139CX095CFASTERDIFFUSIONOCCURSINTHELOOSERPACKEDBCCSTRUCTURE,LEADINGTOTHEHIGHERCARBONCONTENTATPOINT“X”15POINTS6F/4042F/01257L2/2A02OFFSETYIELDSTRENGTH11,600PSIBTENSILESTRENGTH12,729PSICE71600/0011870603,000PSIDELONGATIONEREDUCTIONINAREAFENGINEERINGSTRESSATFRACTURE11,297PSIGTRUESTRESSATFRACTURE1420LB/TC/40393211,706PSIHFROMTHEFIGURE,YIELDINGBEGINSNEAR9550PSITHUS15POINTS7THESEPARTICLES,BYHELPINGPINDIEGRAINBOUNDARIES,WILLINCREASETHEGRAINGROWTHTEMPERATUREANDDECREASETHEGRAINSIZE15POINTS8THECUSRALLOYWOULDBEEXPECTEDTOBESTRONGESTLARGESTSIZEDIFFERENCETHECUAUALLOYSATISFIESHUMEROTHERYSCONDITIONSANDMIGHTBEEXPECTEDTODISPLAYCOMPLETESOLIDSOLUBILITYINFACTITFREEZESLIKEANISOMORPHOUSSERIESOFALLOYS,BUTANUMBEROFSOLIDSTATETRANSFORMATIONSOCCURATLOWERTEMPERATURES15POINTS英文原版教材班“材料科学基础”考试试题试卷四EXAMINATIONPROBLEMSOFTHECOURSEOF“FUNDAMENTOFMATERIALSSCIENCE”姓名班级记分1ALUMINUMHASADENSITYOF27G/CM3SUPPOSEYOUWOULDLIKETOPRODUCEACOMPOSITEMATERIALBASEDONALUMINUMHAVINGADENSITYOF15G/CM3DESIGNAMATERIALTHATWOULDHAVETHISDENSITYWOULDINTRODUCINGBEADSOFPOLYETHYLENE,WITHADENSITYOF095G/CM3,INTOTHEALUMINUMBEALIKELYPOSSIBILITYEXPLAIN5POINTS2AALUMINUMFOILUSEDFORSTORINGFOODWEIGHSABOUT03GPERSQUAREINCHHOWMANYATOMSOFALUMINUMARECONTAINEDINTHISSAMPLEOFFOILBUSINGTHEDENSITIESANDATOMICWEIGHTSGIVENINAPPENDIXA,CALCULATEANDCOMPARETHENUMBEROFATOMSPERCUBICCENTIMETERINILEADANDIILITHIUM10POINTS3THEDENSITYOFPOTASSIUM,WHICHHASTHEBCCSTRUCTUREANDONEATOMPERLATTICEPOINT,IS0855G/CM3THEATOMICWEIGHTOFPOTASSIUMIS3909G/MOLCALCULATEATHELATTICEPARAMETERANDBTHEATOMICRADIUSOFPOTASSIUM10POINTS4THEDENSITYOFASAMPLEOFHCPBERYLLIUMIS1844G/CM3ANDTHELATTICEPARAMETERSAREA0022858NMANDC0035842NMCALCULATEATHEFRACTIONOFTHELATTICEPOINTSTHATCONTAINVACANCIESANDBTHETOTALNUMBEROFVACANCIESINACUBICCENTIMETER15POINTS5ACERAMICPARTMADEOFMGOISSINTEREDSUCCESSFULLYAT1700IN90MINUTESTOMINIMIZETHERMALSTRESSESDURINGTHEPROCESS,WEPLANTOREDUCETHETEMPERATURETO1500WHICHWILLLIMITTHERATEATWHICHSINTERINGCANBEDONEDIFFUSIONOFMAGNESIUMIONSORDIFFUSIONOFOXYGENIONSWHATTIMEWILLBEREQUIREDATTHELOWERTEMPERATURE15POINTS6AATHERMOSETTINGPOLYMERCONTAININGGLASSBEADSISREQUIREDTODEFLECT05MMWHENAFORCEOF500NISAPPLIEDTHEPOLYMERPARTIS2CMWIDE,05CMTHICK,AND10CMLONGIFTHEFLEXURALMODULUSIS69GPA,DETERMINETHEMINIMUMDISTANCEBETWEENTHESUPPORTSWILLTHEPOLYMERFRACTUREIFITSFLEXURALSTRENGTHIS85MPAASSUMETHATNOPLASTICDEFORMATIONOCCURSBTHEFLEXURALMODULUSOFALUMINAIS45X106PSIANDITSFLEXURALSTRENGTHIS46,000PSIABAROFALUMINA03INTHICK,10INWIDE,AND10INLONGISPLACEDONSUPPORTS7INAPARTDETERMINETHEAMOUNTOFDEFLECTIONATTHEMOMENTTHEBARBREAKS,ASSUMINGTHATNOPLASTICDEFORMATIONOCCURS15POINTS7BASEDONTHEFOLLOWINGOBSERVATIONS,CONSTRUCTAPHASEDIAGRAMELEMENTAMELTSAT850CANDELEMENTBMELTSAT1200CELEMENTBHASAMAXIMUMSOLUBILITYOF5INELEMENTA,ANDELEMENTAHASAMAXIMUMSOLUBILITYOF15INELEMENTBTHENUMBEROFDEGREESOFFREEDOMFROMTHEPHASERULEISZEROWHENTHETEMPERATUREIS725CANDTHEREIS35BPRESENTATROOMTEMPERATURE1BISSOLUBLEINAAND7AISSOLUBLEINB15POINTS8SUPPOSETHATAGEHARDENINGISPOSSIBLEINTHEALMGSYSTEMSEEFIGURE1011ARECOMMENDANARTIFICIALAGEHARDENINGHEATTREATMENTFOREACHOFTHEFOLLOWINGALLOYS,ANDBCOMPARETHEAMOUNTOFTHEPRECIPITATETHATFORMSFROMYOURTREATMENTOFEACHALLOYIAL4MGIIAL6MGIIIAL12MGCTESTINGOFTHEALLOYSAFTERTHEHEATTREATMENTREVEALSTHATLITTLESTRENGTHENINGOCCURSASARESULTOFTHEHEATTREATMENTWHICHOFTHEREQUIREMENTSFORAGEHARDENINGISLIKELYNOTSATISFIED15POINTS英文原版教材班“材料科学基础”考试试题答案SOLUTIONSOFTHECOURSEOF“FUNDAMENTOFMATERIALSSCIENCE”1INORDERTOPRODUCEANALUMINUMMATRIXCOMPOSITEMATERIALWITHADENSITYOF15G/CM3,WEWOULDNEEDTOSELECTAMATERIALHAVINGADENSITYCONSIDERABLYLESSTHAN15G/CM3WHILEPOLYETHYLENESDENSITYWOULDMAKEITAPOSSIBILITY,THEPOLYETHYLENEHASAVERYLOWMELTINGPOINT