实验二大数据类型、运算符和简单地输入输出

1、word实验二 数据类型、运算符和简单的输入输出实验报告一、实验目的1. 掌握C语言数据类型，了解字符型数据和整型数据的内在关系。2. 掌握对各种数值型数据的正确输入方法。3. 学会使用C的有关算术运算符，以与包含这些运算符的表达式,特别是自加和自减运算符的使用。4. 学会编写和运行简单的运用程序。5. 进一步熟悉的编辑、编译、连接和运行的过程。二、实验内容(源代码)1 .sy2-(l)#in clude<stdio.h>int mai n()char c1,c2;c1=97;c2=98;prin tf("%c %cn",c1,c2);prin tf("

2、;%d %dn",c1,c2);return 0;a b97 99Pi'ess ainy key to cantinue#in clude<stdio.h> int mai n()char c1,c2;c1=197;c2=198;printf("%c %cn",c1,c2);prin tf("%d %dn",c1,c2); return 0;77-59 -58Pvess ajiy key to contirtue#in clude<stdio.h> int mai n()int c1,c2;c1=97;c2=98

3、;prin tf("%c %cn",c1,c2);prin tf("%d %dn",c1,c2); return 0;7 98<n y key 七q ucjinf nu書2. sy2-(2)#in clude<stdio.h>int mai n() int a,b;float x,y;char c1,c2;sea nf("a=%db=%d", &a,&b);sca nf("%f%e", &x,&y);sca nf("%c%c",&c1,

4、&c2); return 0;a-3,h8589934C0, x107374176 - 000000, v1073741.G00000, clf c2-b Press 讯ny key 七口 continuea=J Jb=7 x=B.bH a|a=3 ,b=?,x=-107374176 - 0S0B00,-107374176 - 00B006,cl=x, c2 =Press Qn* kev to continue<i-3 h=7 8.2 71.82 A a»-311=7,-8 .20000®,=71 _ 820000, ci - , c2=APress mny&

5、quot;to continue-3 b-7 8.5 7L,8Zrta-3.1)-7P a-H . SHHHHH». HriklHHHji(; I - A PGfi -dfps5? an l/ kfi i| tn rnnfriniif?3 7 B,5 71-82Aa,k-a5S9?346O,b=-85S9?3460,x=3.000003=7 国 000(9(3.匚1= ,cZ=8 Pi'ees in# key to eonti.nue=3 b=78-5 ?1_82nLi=a , b=7,x=8 _ 500000,=71 -S20900,cl =Lg2=At*ress any

6、key to continue萨3 b=7.H.5 71.82.Ha.卜=3* h=7f x=K. S30H30J.y=71 - S2RO03,cl= HLg2-A.Prefis 戍ny kt?9cocontinueHa-3 b=7B.5 71.B2Aaa=3 ,b=7,x=8.500000, y=?l -820000 g1=FI .c;2=6iPress anv hey to continue3. sy2-(3) #in clude<stdio.h> int mai n()int i,j,m,n;i=8;j=10;m=+i;n=j+;prin tf("%d,%d,%d,

7、%dn",i,j,m, n);return 0;Ml,9,16nn* kcj to cont in#in clude<stdio.h> int mai n()int i,j,m,n;i=8;j=10;m=i+;n=+j；prin tf("%d,%d,%d,%dn",i,j,m, n);return 0;lri*e££ anu ktiy to concinue#in clude<stdio.h> int mai n()int i,j;i=8;j=10;prin tf("%d,%dn",i+,j+);re

8、turn 0;Pi*es3key to CDntinuB#in clude<stdio.h>int mai n()int i,j;i=8;j=10;prin tf("%d,%dn",+i,+j);return 0;,11jese any key to continue#in clude<stdio.h>int mai n()int i,j;i=8;j=10；prin tf("%d,%d,%d,%dn" ,i,j,i+,j+);return 0;8.10,8.10Press Hny key to coritiriue#in clud

9、e<stdio.h> int mai n()int i,j,m=0,n=0;i=8;j=10;m+=i+;n-二-j;prin tf("i=%d,j=%d,m=%d ,n=%dn",i,j,m, n);return 0;j =9,08 rn=-9Press any to cent inue4. sy2-(4)#in clude<stdio.h>#in clude<math.h> int mai n()float p,r, n;r=0.1;n=10; p=pow(1+r, n);prin tf("p=%fn",p);re

10、turn 0;i=2_593742any key to continue#in clude<stdio.h>#in clude<math.h> int mai n()float p,r, n;sca nf("%f",&r);n=10;p=pow(1+r, n);prin tf("p=%fn",p);return 0;M-07 p-1.967151Press an5/ hcv to co nt inue0.08p=2.158925Press anu ke u to cont inue0.1 p=2.5?3742 Pi*ess Any key to cantinue#in clude<stdio.h> #in clude<math.h> int mai n()float p,r, n;prin tf("r=:");sca nf("%f",&r);n=10; p=pow(1+r, n);prin