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1、FLOJEL 60 Basic parameter:Dry rate was 3253 kg/hr commercial production 12.15% moisture, Dryer air inlet temperature of 20 deg C,Starch in the mixing boxes at 25 deg C,Cake moisture was 37.92%, Dryer inlet airflow of 233 deg CDryer outlet airflow of 52.7 deg C, Finished product temp of 52.7 deg C,Ai
2、r humidity:, and the (P=101300 pa, t=20)Therefore the thermodynamic loads can be calculated as follows:Wet cakeG1, w1, q1, cm1Dry starchG2 , w2 , q2, cm2HOT AIRL, H1, t1, i1Air outL, H2, t2, i2Air inL, H0, t0, i0QLPGPGQl3253 kg/hr 87.85% dry solids = 2857.8 kg/hr DS =0.794 kg/s DS3253 kg/hr 12.15% =
3、 395.2 kg/hr = 0.11 kg/s water left in the product2857.8 kg/hr DS / 62.08% solids = 4603.4 kg/hr =1.279 kg/s total feed at 37.92% moisture 4603.4 kg/hr Total - 2857.8 kg/hr DS = 1745.6 kg =0.485 kg/s water/hr introduced into the dryerTOTAL EVAPORATED W = 1745.6 kg/hr - 395.2 kg/hr left = 1350.4 kg /
4、hr =0.375 kg/s water evaporatedDry Air consumed total:Saturation steam pressure at 20 C So the humility of the air is And the specific heat of the air isThe specific heat of the final product isBasing on the Heat Balance Equation Where L = dry air quantity, kg/s W = water evaporated quantity, kg/s =
5、 Dry starch, kg/s = Evaporated heat,KG/KJ , , = Specific heat, KJ/(KG.K) , = Inlet & outlet temp of starch, L=5.87 kg/s = 21132 kg/h FOR = 17461.9 ALL THE ENERGY COMES FROM LPG BURNNING, SO= 4626360 Kj/h=4.63 MM Kj/hThat is to say the sum of heat load is 4.63 MM KJ/hr starch dried at 12.15% moisture
6、.That is to say 1.42 MM KJ/ metric tonAnd the heat loads distribution is:Heat added to final product:Heat of water evaporation:Heat lost by the outlet air: =194.73 =0.71 MM KJ/hHeat lost to the surrounding =5% (3.356+0.37) MM KJ/h=0.19MM KJ/hIn other words:And heat efficiency is = 80.6 % From the We
7、b, I got the reference that 26000 Kcal/will be received from the LPG burning =26000 Kcal/m3 = 260004.184=108784 KJ/SoIf basing Baos data, Total plant LPG usage in Oct is 27320.14 , and 3939 of it was Used for boiler, that is to say Dryer consume is = 23381.14 / 1287.867 metric ton = 18.155 / metric tonSo the heat from LPG burning is =108784 KJ/ 18.155 / metric ton =1.97 MM KJ/ metric ton=72.1%If basing Rays data, the average LPG consume is 28.1 / metric tonThe heat from burning is =108784 KJ/ 28.1 / metric ton =3.07 MM KJ/ metric ton=46.3%公司名称:常州力马干燥工程有限公司联 系 人:周友来1380
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