数字电子技术第4章组合逻辑电路习题解答2

。ABFF(AB)BBABAABFA••B•A••B•AB•ABD&&&C&LCD•BC•ABDCDBCABD〔〕LL0001001100010111CSSBL10AB&LSS0习题4.5图1〕LAS•BSS(ASBS)S110110SSLABAB&AF&&&BC&习题4.6图〕F(ABC)ABCF01111110CFFABCF习题4.7图F10010010FABCABCF(,,C,D)FFBCDADBCDABCBCDADBCDABCBCD•AD•BCD•ABCFCD)(ABC)(ABC)(BD)CDABCABCBD）FCDABCBDABCF01101001000011110001101100011011FABCABCAFBC8L3203201111100011××××××L(DDDD)m(m3210L(DDDD)DDDD•DD32102102101D&&0LD2CCABF10当CC10CC10CCB10CC10CC10F(C,C,A,B)m()CCACCCAB1010010CCFCCF101000000001001000110100010101100111010000100111010110110110011101111100111100010111CC&AC0&&&ABFC1ABC0ABCG(,B,C)mY(,B,C)m）；）；）。210210210210SS010112F；12）AABBA10BFBF12&YYYYYYYYYYYYYYYY01234567893210ABCD〕F12当或或F。1212AABB0101010112F01101001Fm〕12(AB)C(AB)CABCABCABCm)22074LS138～Y～Y8073477CBCBAY～YY7Y717D0001C0110B0010A0011a0000b0100cd0010efg*004790100001101101104只012•3456789••••••••••ABCD习题4.20图9时9、）G1）G地址输入0123YYYYYYYYY745671数据输入GGGG11（）习题4.21图GG11GG、用8选1FFYWADDDDDDD07654321D1习题4.22图FF(,B,C,D)mABDABDACDACD〕F(,B,C,D)ABDABDACDACDABDABDACDACDABACm)F(,B,C)F12〕1。2YW765432101〕Fm22YWADDDDDDDD76543210D110F(A,B,C,D)m(0,2,3,5,6,7,8,9)d3ABC•1ABC•1ABC•1ABCDABCD3YWADDDDDDD0765432101D141出F为4F为F、F。121200000001001000110100010101100111FF10001001101010111100110111101111FF121201111101110101111101001000101000F(A,B,C,D)m1，，，，F(A,B,C,D)m(067,8,9)2和SSSS3210AAAABBBB3210321032103210AAAABBBB32103210AAAABBBB32103210SSSS320ABABABAB33221100AB0K32103210321032103210321032103210321032103210321032103解余3码故余3码—余3码+补码=余3码++1321013322110011