C语言实训实例3

题目3假设某单位有10人，职工工资表如下所示，要求奖金按以下条件给出：(1)中级职称的奖金是该职工工资的40%；(2)高级职称的奖金是该职工工资的60%；(3)初级职称的奖金是该职工工资的30%。方法一：#include"stdio.h"#include"string.h"main(){inti;charc[20];floata[10][3];a[0][0]=1024.56;a[1][0]=1102.41;a[2][0]=812.27;a[3][0]=1589.35;a[4][0]=1638.47;a[5][0]=1017.59;a[6][0]=789.35;a[7][0]=1687.69;a[8][0]=1024.25;a[9][0]=1815.27;printf("请输入教师职称；“工程师、会计师、助工、高工、高会”\n");for(i=0;i<5;i++)/*实现根据不同职称计算奖金及总收入的功能*/{gets(c);if(strcmp(c,"工程师")==0){a[0][1]=a[0][0]*0.4;a[0][2]=a[0][0]+a[0][1];a[8][1]=a[8][0]*0.4;a[8][2]=a[8][0]+a[8][1];}elseif(strcmp(c,"会计师")==0){a[1][1]=a[1][0]*0.4;a[1][2]=a[1][0]+a[1][1];a[5][1]=a[5][0]*0.4;a[5][2]=a[5][0]+a[5][1];}elseif(strcmp(c,"助工")==0){a[2][1]=a[2][0]*0.3;a[2][2]=a[2][0]+a[2][1];a[6][1]=a[6][0]*0.3;a[6][2]=a[6][0]+a[6][1];}elseif(strcmp(c,"高工")==0) {a[3][1]=a[3][0]*0.6;a[3][2]=a[3][0]+a[3][1]; a[7][1]=a[7][0]*0.6;a[7][2]=a[7][0]+a[7][1]; }elseif(strcmp(c,"高会")==0) {a[4][1]=a[4][0]*0.6;a[4][2]=a[4][0]+a[4][1]; a[9][1]=a[9][0]*0.6;a[9][2]=a[9][0]+a[9][1];}}system("cls");/*清除上述显示，输出工资表*/printf("职工号职称工资奖金总收入\n");printf("----------------------------------------------\n");printf("A1101工程师%-6.2f%-6.2f%-6.2f\n",a[0][0],a[0][1],a[0][2]);printf("----------------------------------------------\n");printf("B1014会计师%-6.2f%-6.2f%-6.2f\n",a[1][0],a[1][1],a[1][2]);printf("----------------------------------------------\n");printf("B1016助工%-6.2f%-6.2f%-6.2f\n",a[2][0],a[2][1],a[2][2]);printf("----------------------------------------------\n");printf("A1105高工%-6.2f%-6.2f%-6.2f\n",a[3][0],a[3][1],a[3][2]);printf("----------------------------------------------\n");printf("B1019高会%-6.2f%-6.2f%-6.2f\n",a[4][0],a[4][1],a[4][2]);printf("----------------------------------------------\n");printf("A1115会计师%-6.2f%-6.2f%-6.2f\n",a[5][0],a[5][1],a[5][2]);printf("----------------------------------------------\n");printf("A1117助工%-6.2f%-6.2f%-6.2f\n",a[6][0],a[6][1],a[6][2]);printf("----------------------------------------------\n");printf("B1024高工%-6.2f%-6.2f%-6.2f\n",a[7][0],a[7][1],a[7][2]);printf("----------------------------------------------\n");printf("A1124工程师%-6.2f%-6.2f%-6.2f\n",a[8][0],a[8][1],a[8][2]);printf("----------------------------------------------\n");printf("B1028高会%-6.2f%-6.2f%-6.2f\n",a[9][0],a[9][1],a[9][2]);printf("----------------------------------------------\n");}程序效果图如下；方法二#include"stdio.h"#include"string.h"main(){inti,j,k=0,m=0,w=0;charb[20],c[20];floata[10][3];a[0][0]=1024.56;a[1][0]=1102.41;a[2][0]=812.27;a[3][0]=1589.35;a[4][0]=1638.47;a[5][0]=1017.59;a[6][0]=789.35;a[7][0]=1687.69;a[8][0]=1024.25;a[9][0]=1815.27;printf("请输入各教职工职称代码；1,2,3,4,5,6,7,8,9,1o\n");for(i=0;i<5+k+m+w;i++){gets(b);if((strcmp(b,"1")!=0)&&(strcmp(b,"2")!=0)&&(strcmp(b,"3")!=0)&&(strcmp(b,"4")!=0)&&(strcmp(b,"5")!=0)&&(strcmp(b,"6")!=0)&&(strcmp(b,"7")!=0)&&(strcmp(b,"8")!=0)&&(strcmp(b,"9")!=0)&&(strcmp(b,"10")!=0)){printf("wrong!!\n");printf("只接受1-10表示的字符,请重新输入!!\n");k++;getch();system("cls");printf("请输入各教职工职称代码；1,2,3,4,5,6,7,8,9,1o\n");continue;}elseif(strcmp(b,"1")==0){a[0][1]=a[0][0]*0.4;a[0][2]=a[0][1]+a[0][0];}elseif(strcmp(b,"2")==0){a[1][1]=a[1][0]*0.4;a[1][2]=a[1][0]+a[1][1];}elseif(strcmp(b,"3")==0){a[2][1]=a[2][0]*0.3;a[2][2]=a[2][0]+a[2][1];} elseif(strcmp(b,"4")==0){a[3][1]=a[3][0]*0.6;a[3][2]=a[3][0]+a[3][1];} elseif(strcmp(b,"5")==0){a[4][1]=a[4][0]*0.6;a[4][2]=a[4][0]+a[4][1];}elseif(strcmp(b,"6")==0){a[5][1]=a[5][0]*0.4;a[5][2]=a[5][0]+a[5][1];}elseif(strcmp(b,"7")==0){a[6][1]=a[6][0]*0.3;a[6][2]=a[6][0]+a[6][1];} elseif(strcmp(b,"8")==0){a[7][1]=a[7][0]*0.6;a[7][2]=a[7][0]+a[7][1];}elseif(strcmp(b,"9")==0){a[8][1]=a[8][0]*0.4;a[8][2]=a[8][0]+a[8][1];}elseif(strcmp(b,"10")==0){a[9][1]=a[9][0]*0.6;a[9][2]=a[9][0]+a[9][1];}gets(c);{if((strcmp(c,"1")!=0)&&(strcmp(c,"2")!=0)&&(strcmp(c,"3")!=0)&&(strcmp(c,"4")!=0)&&(strcmp(c,"5")!=0)&&(strcmp(c,"6")!=0)&&(strcmp(c,"7")!=0)&&(strcmp(c,"8")!=0)&&(strcmp(c,"9")!=0)&&(strcmp(c,"10")!=0)){printf("wrong!!\n");printf("只接受1-10表示的字符,请重新输入!!\n");getch();system("cls");printf("请输入各教职工职称代码；1,2,3,4,5,6,7,8,9,1o\n"); for(j=0;j<10;j++) {a[j][1]=0;a[j][2]=0;} getch();w++;continue;}elseif(strcmp(b,c)==0){printf("\n不能输入相同值!!\n");m++;getch();system("cls");printf("请输入各教职工职称代码；1,2,3,4,5,6,7,8,9,1o\n");continue;}elseif(strcmp(c,"1")==0){a[0][1]=a[0][0]*0.4;a[0][2]=a[0][1]+a[0][0];}elseif(strcmp(c,"2")==0){a[1][1]=a[1][0]*0.4;a[1][2]=a[1][0]+a[1][1];}elseif(strcmp(c,"3")==0){a[2][1]=a[2][0]*0.3;a[2][2]=a[2][0]+a[2][1];}elseif(strcmp(c,"4")==0){a[3][1]=a[3][0]*0.6;a[3][2]=a[3][0]+a[3][1];} elseif(strcmp(c,"5")==0){a[4][1]=a[4][0]*0.6;a[4][2]=a[4][0]+a[4][1];}elseif(strcmp(c,"6")==0){a[5][1]=a[5][0]*0.4;a[5][2]=a[5][0]+a[5][1];}elseif(strcmp(c,"7")==0){a[6][1]=a[6][0]*0.3;a[6][2]=a[6][0]+a[6][1];} elseif(strcmp(c,"8")==0){a[7][1]=a[7][0]*0.6;a[7][2]=a[7][0]+a[7][1];} elseif(strcmp(c,"9")==0){a[8][1]=a[8][0]*0.4;a[8][2]=a[8][0]+a[8][1];}if(strcmp(c,"10")==0){a[9][1]=a[9][0]*0.6;a[9][2]=a[9][0]+a[9][1];}}}system("cls");printf("职工号职称工资奖金总收入\n");printf("----------------------------------------------\n");printf("A1101工程师%-6.2f%-6.2f%-6.2f\n",a[0][0],a[0][1],a[0][2]);printf("----------------------------------------------\n");printf("B1014会计师%-6.2f%-6.2f%-6.2f\n",a[1][0],a[1][1],a[1][2]);printf("----------------------------------------------\n");printf("B1016助工%-6.2f%-6.2f%-6.2f\n",a[2][0],a[2][1],a[2][2]);printf("----------------------------------------------\n");printf("A1105高工%-6.2f%-6.2f%-6.2f\n",a[3][0],a[3][1],a[3][2]);printf("----------------------------------------------\n");printf("B1019高会%-6.2f%-6.2f%-6.2f\n",a[4][0],a[4][1],a[4][2]);printf("----------------------------------------------\n");printf("A111