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2024MathKangarooJuniorLevelD(China)1、Whichofthefollowingstringscannotbetransformedintothestringontherightwithoutcutting?请问下列哪条绳子在不切割的情况下,无法变成右图所示的样式?A.B.C.D.E.2、Ashapeismadeofequal-sizedpentagonaltiles.Whichofthefollowingtilescanbeplacedinthespaceintheshapetoproducetwoclosedcurves?右侧图形由尺寸相同的五边形瓷砖组成.请问将下列哪块瓷砖放入这个图形的空白处可以形成两条封闭曲线?A.B.C.D.E.3、Thefirstdiagramshowsarhombus.Theareaofthefirstdia-gramisincreasedbyaddingtworight-angledtriangles,asshown.Bywhatpercentagehastheareaincreased?如图所示,第一个图形为菱形,加上两个直角三角形之后,图形面积有所增加.请问面积增加了百分之几?A.20%B.25%C.30%D.40%E.50%4、Whatisthevalueof20×242×0+2×4请问20×242×0+2×4A.12B.30C.48D.60E.1205、Juliocutsoffthefourcornersofaregulartetrahedron,asshown.Howmanycornersdoestheshapethatremainshave?如图所示,Julio切掉了一个正四面体的四个角.请问余下图形有多少个角?A.8B.9C.11D.12E.156、Riahasthreecountersmarked1,5and11,asshown.Shewantstoplacethemsidebysidetomakeafour-digitnumber.Howmanydifferentfour-digitnumberscanshemake?Ria有三个筹码,分别标记有1、5和11,如图所示.将三个筹码并排放置组成一个4位数,请问Ria可以得到多少个不同的4位数?A.3B.4C.6D.8E.97、Afruitbowlcontainsfivetypesoffruit
,
,
,
and
.Allikes
.Boklikes,
,
and
.Camlikes
,
,
,and
.Donlikes
,
and
.Evalikes
and
.Thefruitissharedsothateveryonegetsadifferenttypeoffruitandeveryonegetsatypeoffruitthattheylike.Whogets?一个果篮里有5种水果:、、、、.Al喜欢.Bok喜欢、、、
.Cam喜欢、、、.Don喜欢、、.Eva喜欢、.大家分享这些水果时,每个人拿到的水果都不同且都是自己喜欢的水果.请问谁拿到了?A.AlB.BokC.CamD.DonE.Eva8、Theweightrestrictionnoticeforanelevatorsaysitcancarryeither12adultsor20children.Accordingtotheweightrestrictions,whatisthelargestnumberofchildrenthatcanrideintheelevatorwithnineadults?电梯超载提示标明,该电梯能承载12名成年人或20名儿童.根据该提示,如果该电梯已经搭载了9名成年人,那么最多还能搭载多少名儿童?A.3B.4C.5D.6E.89、Fourdifferentpositiveintegersareplacedonagridandthencoveredup.Theproductsoftheintegersineachrowandineachcolumnareshowninthediagram.Whatisthesumofthefourintegers?在一个网格中放入4个不同的正整数,然后将其遮盖.右图中显示的数字分别为每行和每列中的整数之积.请问这4个整数的总和是多少?A.10B.12C.13D.14E.1510、Thelengthofasetoffourwell-parkedandfittedsupermarkettrolleysis108cm.Thelengthofasetoftenwell-parkedandfittedsupermarkettrolleysis168一排4辆整齐停放的超市手推车的长度为108cm.一排10辆整齐停放的超市手推车的长度是168A.60B.68C.78D.88E.9011、Carinabakedacakeandcutitintotenequalpieces.Sheateonepieceandthenarrangedtheremainingpiecesevenly,asshown.Whatisthesizeoftheanglebetweenanytwopieces?Carina将自己烤的蛋糕等分为10块.她吃了一块,然后将剩下的9块均匀分布,如图所示.请问任意两块相邻的蛋糕之间的角度是多少?A.5°B.4°C.3°D.2°E.1°12、Wernercanmakea4×4square,wherethesumofthenumbersinallfourrowsandallfourcolumnsisthesame,fromthethreepiecesshown
andonefurtherpiece.Whichofthefollowingpiecesisneededtocompletehissquare?Werner做了一个4×4的正方形,这个正方形中每行、每列的4个数字之和相同.正方形可分成四块碎片,其中三块碎片为:.请问下列哪个选项是该正方形的最后一块碎片?A.B.C.D.E.13、Asquarehasside-length10m.Itisdividedintopartsbythreestraightlinesegments,asshown.TheareasofthetwoshadedtrianglesareAandB.WhatisthevalueofA−B如图所示,一个边长为10m的正方形被三条线段切分.其中两个阴影三角形的面积分别为A和B.请问A−BA.0B.1C.2D.5E.1014、Paulathepenguingoesfishingeverydayandalwaysbringsbacktwelvefishforhertwochicks.Eachday,shegivesthefirstchicksheseessevenfishandgivesthesecondchickfivefish,whichtheyeat.Inthelastfewdaysonechickhaseaten44fish.Howmanyhastheotherchickeaten?企鹅Paula每天都出门捕鱼,并且总是会给她的两只企鹅幼崽带回12条鱼.每一天,Paula会给她看到的第一只企鹅幼崽喂7条鱼,给看到的第二只企鹅幼崽喂5条鱼.在过去的几天中,其中一只企鹅幼崽一共吃掉44条鱼.请问另一只企鹅幼崽一共吃了多少条鱼?A.34B.40C.46D.52E.5815、Johanhadalargenumberofidenticalcubes.Hemadethestructureontherightbytakingasinglecubeandthenstickinganothercubetoeachface.Hewantstomakeanextendedstructureinthesamewaysothateachfaceofhisoriginalstructurewillhaveacubestucktoit.Howmanyextracubeswillheneedtocompletehisextendedstructure?Johan有许多相同的立方体.他选取其中一个立方体,然后将其他立方体贴在该立方体的各个面上,最终形成右侧所示结构.接下来,他想用同样的方式制作一个扩展结构,使得原结构的每一面上都贴上一个立方体.请问Johan还需要多少个立方体才能完成这个扩展结构?A.18B.16C.14D.12E.1016、Akangaroojumpsupamountainandthenjumpsbackdownalongthesameroute.Itcoversthreetimesthedistancewitheachdownhilljumpasitdoeswitheachuphilljump.Goinguphill,itcovers1metreperjump.Intotal,thekangaroomakes2024jumps.Whatisthetotaldistance,inmetres,thatthekangaroojumps?一只袋鼠跳上山,然后按照同样的路线跳下山.它下山时每次跳跃的距离是上山时每次跳跃距离的三倍.袋鼠上山时每次跳跃的距离是1米.袋鼠上下山总共跳了2024次,请问袋鼠总共跳跃了多少米?A.506B.1012C.2024D.3036E.404817、Gerardcutsalargerectangleintofoursmallerrectangles.Theperimetersofthreeofthesesmallerrectanglesare16,18and24,asshowninthediagram.Whatistheperimeterofthefourthsmallrectangle?Gerard将一个大矩形切割成4个小矩形.其中三个小矩形的周长分别为16、18、24,如图所示.请问第四个小矩形的周长是多少?A.8B.10C.12D.14E.1618、Watermakesup80percentofthemassoffreshmushrooms.However,watermakesuponly20percentofthemassofdriedmushrooms.Bywhatpercentagedoesthemassofthemushroomdecreaseduringdrying?新鲜蘑菇中的水分占总质量的80%,但干蘑菇中的水分只占总质量的20%.请问在晒干过程中,蘑菇的质量减少了百分之几?A.60B.70C.75D.80E.8519、Terithetilerisplanningtomakealarge,squaremosaicfloorwitharepeatingpattern,usinghexagonalandtriangulartiles,arrangedasshowninthediagram.泥瓦匠Teri计划按照一定的规律将六边形瓷砖和三角形瓷砖拼接成一个大块正方形马赛克地板,排列方式如图所示.Shethinksshewilluse3000hexagonaltilestomakethewholefloor.Approximately,howmanytriangulartileswillsheneed?Teri认为铺成这样一整块地板需要用3000块六边形瓷砖.请问Teri大约需要用多少块三角形瓷砖?A.1000B.1500C.3000D.6000E.900020、Ninecardsnumberedfrom1to9wereplacedfacedownonthetable.Aleksa,Bart,ClaraandDeindraeachpickeduptwoofthecards.Aleksasaid"Mynumbersaddupto6".Bartsaid"Thedifferencebetweenmynumbersis5".Clarasaid"Theproductofmynumbersis18".Deindrasaid"Oneofmynumbersistwicetheotherone".Allfourmadeatruestatement.Whichnumberwasleftonthetable?九张编号为1到9的卡牌正面朝下放在桌子上.Aleksa,Bart,Clara和Deindra每个人都从桌子上挑选2张牌.Aleksa说:“我拿到的卡牌上的数字相加等于6.”Bart说:“我拿到的卡牌上的数字之差是5.”Clara说:“我拿到的卡牌上的数字的乘积为18.”Deindra说:“我拿到的卡牌上的其中一个数字是另一个数字的两倍.”如果他们4个人说的都是真的,那么请问桌子上剩余卡牌上的数字是什么?A.1B.3C.6D.8E.921、Thedigits0-9canbedrawnwithhorizontalandverticalsegments,asshown.Gregchoosesthreedifferentdigits.Intotal,hisdigitshave5horizontalsegmentsand10verticalsegments.Whatisthesumofhisthreedigits?用横线和竖线表示数字0-9,如图所示.Greg从中选取三个不同数字.他选取的数字一共包含5条横线和10条竖线.请问他选取的三个数字之和是多少?A.9B.10C.14D.18E.1922、Tarekwantstoshadetwofurthersquaresonthediagramshownsothattheresultingpatternhasasingleaxisofsymmetry.Inhowmanydifferentwayscanhecompletehispattern?Tarek想将下图中的另外两个方格涂黑,使得最终所得图形只有一条对称轴.请问他能用几种不同的涂法来完成他想要的图形?A.2B.3C.4D.5E.623、Thediagramshowsthreesemi-circlesinsidearectangle.Themiddlesemi-circletouchestheothertwosemi-circleswhich,inturn,eachtouchashortersideoftherectangle.Thelargestsemi-circlealsotouchesoneofthelongersidesoftherectangle.Theshortestdistancesfromthatsideoftherectangletotheothertwosemi-circlesare5cmand7cmrespectively,asshown.Whatistheperimeter,in图中展示了一个矩形中有三个半圆.中间的半圆与两侧的半圆相切,两侧的半圆分别与矩形的一条短边相切,同时,最大的半圆与矩形的一条长边相切,且这条长边到另外两个半圆的最短距离分别为5cm和7cm,如图所示.请问这个矩形的周长为多少A.82B.92C.96D.108E.12024、Agroupof50studentssitinacircle.Theythrowaballaroundthecircle.Eachstudentwhogetstheballthrowsittothe6thstudentsittinganti-clockwisefromwheretheyaresitting,whocatchesit.Fredacatchestheball100times.Inthattime,howmanystudentsnevergettocatchtheball?50名学生坐成一圈,然后绕着这个圆圈传球.每名拿到球的学生会把球传给从自己所在位置起逆时针方向上的第6名学生.Freda共接到100次球.在这段时间里,有多少名学生从来没有接到过球?A.0B.8C.10D.25E.4025、Donggyuwantstocompletethediagramsothateachboxinthemiddleandtoprowswillcontaintheproductofthevaluesinthetwoboxesbelowitandeachboxcontainsapositiveinteger.Hewantsthevalueinthetopboxtobe720.Howmanydifferentvaluescantheintegerntake?Donggyu想完成右图,使得中间行和顶行中的每个方格都包含其下方紧邻的两个方格内的数字之积,且每个方格内均为正整数.他希望顶行方格中的数字为720,那么请问整数n可以有多少个不同的数值?A.1B.4C.5D.6E.826、FarmerFiissellingchickenandduckeggs.Shehasbasketsholding4,6,12,13,22,and29eggs.Herfirstcustomerbuysalltheeggsinonebasket.Finoticesthatthenumberofchickereggsshehasleftistwicethenumberofduckeggs.Howmanyeggsdidthecustomerbuy?农夫Fi正在卖鸡蛋和鸭蛋.她有很多个篮子,里面分别装有4、6、12、13、22、29个蛋.第一位顾客买了其中一个篮子中所有的蛋.此时Fi注意到在剩下的蛋中,鸡蛋数量是鸭蛋数量的两倍.请问这位顾客买了多少个蛋?A.4B.12C.13D.22E.2927、Threeanglesα,β
andγ
aremarkedonsquaredpaper,asshown.Whatisthevalueof
α+β+γ?如图所示,方格纸上标记有α、β、γ三个角.请问α+β+γ的值是多少?A.6B.7C.75D.90E.1228、CaptainFlintaskedfourofhispiratestowriteonapieceofpaperhowmanygold,silverandbronzecoinswereinthetreasurechest.Theirresponsesareshowninthediagrambutunfortunatelypartofthepaperwasdamaged.Onlyoneofthefourpiratestoldthetruth.Theotherthreeliedinalltheiranswers.Thetotalnumberofcoinsis30.Whotoldthetruth?海盗船长Flint要求他的4位船员在一张纸上记录下藏宝箱中金币、银币、铜币的数量.船员们的记录如下图所示,但不幸的是,纸张出现了部分破损.四位船员中只有一位是如实记录,其他三位记录的数字全部都是虚假的.已知硬币的总数量为30枚.请问哪位船员记录的数字是真实的?A.TomB.AlC.PitD.JimE.wecannotbesure无法确定29、AlexdrivesfrompointAtopointB,thenimmediatelyreturnstoA.BobdrivesfrompointBtopointA,thenimmediatelyreturnstoB.Theytravelonthesameroad,startatthesametimeandeachtravelsataconstantspeed.Alex'sspeedisthreetimesBob'sspeed.Theypasseachotherforthefirsttime15minutesafterthestart.Howlongafterthestartwilltheypasseachotherforthesecondtime?Alex开车从A点到B点,然后又立刻返回A点.Bob开车从B点到A点,然后又立刻返回B点.他们在同一条路上行驶,同一时间出发,并且匀速前行.Alex的速度是Bob的三倍.他们出发15min后第一次相遇.请问他们在出发多久之后会第二次相遇?A.20minB.25minC.30minD.35minE.45min30、InthepentagonABCDE,∠A=∠B=90°,AE=BCandED=DC.FourpointsaremarkedonABdividingitintofiveequalparts.Thenperpendicularsaredrawnthroughthesepoints,asshowninthediagram.Thedarkshadedregionhasanareaof13cm2在五边形ABCDE中,∠A=∠B=90°,AE=BC,ED=DC.在线段AB上标出4个点,将其分成5等份.然后经过这4点做垂线,如图所示.深色阴影区的面积为13cm2A.45B.47C.49D.58E.601、【答案】B;【解析】OnlyforB,tworingsareformedthatmustpassthrougheachotheranditisimpossibletodothiswithoutcuttingthestring.【标注】2、【答案】C;【解析】Notethatalltilesarerotatedby180°.Nootherrotationcanmakethetilefitasthepentagonaltilehasexactlytworightangles.【标注】3、【答案】E;【解析】Theinitialfigurecanbedividedintofourrighttrianglesofthesamearea,andtheinitialfigureintosixtriangles,thustheproportionin6/4,thatis3/2=1.5,thereforeithasincreasedby50%.【标注】4、【答案】D;【解析】20×24【标注】5、【答案】D;【解析】Atetrahedronhasfourcorners.Threesidesmeetateachvertex.Everycutcornertherforgivesthreenewcorners.Soifallfouroldcornersarecutoff,4×3=12newcornersarecreated.【标注】6、【答案】B;【解析】Youcanmake1511,1115,5111and1151.Noticethat,normallyyoucanmake3⋅2⋅1=6numbers,butwhen1and11arenexttoeachother,theorderisnotimportant,soyoulose2possibilities.【标注】7、【答案】E;【解析】Ifwewantthateveryonegetsthefruitshe/helikesthenAlgetstheappleandEvagetsthecherries.【标注】8、【答案】C;【解析】Weneedtodeterminehowmanychildrencanbeintheelevatorinsteadof12−9=3adults.Ifinsteadof12adultstherecanbe20children,theninsteadoffourtimeslessadultstherecanbefourtimeslesschildren,i.e.20:4=5【标注】9、【答案】C;【解析】Inthetoprow,weeitherhavea2anda3,ora1anda6.Ifweplacethe2inthetopleftsquare,wewillneedtorepeata2inthebottomleftsquaresothisisnotpossible.Ifweplacea3ora6inthetopleftsquare,itgivesafractioninthebottomleft.Hence,wemustplacea1inthetopleftsquare.Fromhere,wecanfillinthewholegridasfollows.Alternativesolution:Inthetopleftsquarewemustwriteacommondivisorof4and6,itmaybeonly1or2.Ifwewritethe2inthetopleftsquare,wewillneedtorepeata2inthebottomleftsquaresothisisnotpossible.So,itremainsonly1forthetopleftsquare.Fromhere,wecanfillinthewholegridasfollows:【标注】10、【答案】C;【解析】Thedifferenceinlengthbetween4trolleysand10trolleysequals60cm.Adding10−4=6trolleysmeansadding60cm.So,addingoneextratrolleymeansadding60cm:6=10cmAlternativesolutionLetthelengthofonetrolleyequalxcmandlettheleftpartofthefirst(fromleft)trolley,whichisnotcoveredbyothertrolleys,equalycm.Thelengthofasetoffourwell-parkedtrolleysconsistsofthreepartsyofthefirstthreetrolleysandthelengthxoftheforthtrolley.Thus,3y+x=108.Analogously,fortentrolleyswehave9y+x=168.Itfollowsthat6y=168−160=60andy=10cm【标注】11、【答案】B;【解析】Theangleofeachpieceis360∘10=36【标注】12、【答案】A;【解析】Oneofthegivenpieceshasarowoffournumberswithsum2+1+3+1=7.Thereforethesumofthenumbersinthewholesquareis4×7=28.Thesumsofthenumbersonthethreepiecesare7,8and8andhenceapiecewherethenumberssumto28−7−8−8=5isrequired.Oftheoptionsgiven,theonlyonewithasumof5isA.Thediagrambelowshowshowthesefourpiecesfittogethertomakethesquare.【标注】13、【答案】A;【解析】AreasA+CandB+Careequalsincebotharehalfthesquare.SoA−B=(A+C)−(B+C)=0.【标注】14、【答案】D;【解析】Theonlywayachickcanhaveeaten44fishintotalistohaveeaten5fishsixtimesand7fishtwice.Thereforeithadeatenfishon8days.ThenumberoffishPaulabroughtbackonthose8dayswas8×12=96.Hencethenumberoffisheatenbythesecondchickwas96−44=52.【标注】15、【答案】A;【解析】Thereare30facestocover.Addingacubeintooneofthe"angles"aboutoneedgeoftheinnermostcubeofthestructurecovers2(inner)facesatthesametime.Thereare12edgesofthisinnermostcube,hencewith12cubesyoucoverthese24innerfaces.Tocovertheoutermostfacesyouneed6morecubes,hence18cubesaltogether.【标注】16、【答案】D;【解析】Letudenotethenumberofuphilljumpsanddthenumberofdownhilljumps.Sincethekangaroocoversthreetimesthedistancewitheachdownhilljumpasitdoeswitheachuphilljump,itwillmakethreetimesasmanyuphilljumpsasitdoesdownhilljumps.Thereforeu=3d.Sincewearetoldthatu+d=2024.Thereforethetotaldistance,inmetres,thatthekangaroojumpsis506×3+3×506×1=3036.【标注】17、【答案】B;【解析】Fromthediagram,itcanbeseenthattheperimeteroftherectangleinthetopleftandtheperimeteroftherectangleinthebottomrighttogetherareequaltotheperimeterofthelargerectangle.Thesameargumentistruefortheperimeteroftherectangleinthebottomleftandtheperimeteroftherectangleinthetopright.Therefore
24+?=18+16,andhence
?=10.【标注】18、【答案】C;【解析】Consider100gramsoffreshmushrooms.Since80%ofthisiswater,theremainderhasamassof20grams.Whendried,this20gramsnowrepresents80%ofthetotalmassandsothe20%thatiswaterhasamassof5grams.Thereforethetotalmassofthedriedmushroomsis25gramsandhencethedecreaseis75gramsor75%oftheoriginalmass.AlgebraicSolution:LetthemassofthewaterinthedriedmushroomsbeXgrams.Sincethisrepresents20%ofthetotalmass,themassoftheremainderfourtimesasmuchandsois4Xgrams.However,this4Xgramsrepresentsonly20%ofthemassoffreshmushroomsandhencethemassofwaterinthefreshmushroomsisfourtimesasmuchandsois16Xgrams.Thereforethepercentagedecreaseinthemassis(16X+4X)−(4X+X)【标注】19、【答案】D;【解析】Eachhexagonissurroundedbysixtriangles,andeverytriangletouchesthreehexagons.Thereare6/3=2trianglesperhexagon,soapproximately6000altogether.【标注】20、【答案】E;【解析】Sinceallfourmadeatruestatement,thenumbersonAleksa'scardswere1and5or2and4,thenumbersonBart'scardswere1and6,2and7,3and8or4and9,thenumbersonClara'scardswere2and9or3and6andthenumbersonDeindra'scardswere1and2,2and4,3and6or4and8.SupposethenumbersonAleksa'scardswere2and4.ThenthenumbersonClara'scardscouldonlybe3and6.However,thiswouldnotleaveanypossiblecardsforDeindra.Thereforethenumbersonleksa'scardswere1and5.NowsupposethenumbersonClara'scardswere2and9.ThenthenumbersonDeindra'scardscouldonlybe3and6.However,thiswouldnotleaveanypossiblecardsforBart.ThereforethenumbersonClara'scardswere3and6.FinallysupposethenumbersonBart'scardswere4and9.HoweverthisleavesnopossiblecardsforDeindra.ThereforethenumbersonBart'scardswere2and7,leavingcardsnumbered4and8forDeindra.Hencethecardnumbered9isleftonthetable.【标注】21、【答案】A;【解析】Eachdigithas0,1,2or3horizontalsegments,sothetotalof5canbeobtainedas5=2+2+1or5=3+1+1or5=3+2+0.However,thefirstoptionisnotpossiblesinceonly0hastwohorizontalsegments.Thesecondoptionisnotalsopossible,sinceonly4and7haveonehorizontalsegment,andthedigits4and7haveatotalof3+2=5verticalsegments,meaningthethirddigitwouldneedtohave5verticalsegmentsandthemaximumpossibleis4.Thereforetheremustbe3,2,and0horizontalsegmentsinthedigits.Onlydigit1hasnohorizontalsegmentsandonlydigit0hastwohorizontalsegmentsandtheyhavesixverticalsegmentsbetweerthem.Thereforethefinaldigithasthreehorizontalsegmentsandfourverticalsegmentsandsoisdigit8.Hence,thesumofthedigitsis8+0+1=9.【标注】22、【答案】E;【解析】Thesingleaxisofsymmetrycanbehorizontal,vertical,diagonalfromtoplefttobottomrightanddiagonalfrombottomlefttotopright.Inthefirstthreecases.Tarekcanonlyshadetwofurthersquaresinonewaytogiveasymmetricalpattern.However,inthefinalcase,therearethreepossiblewaystocompleteasymmetricpattern.Hence,Tarekcancompletehispatternin1+1+1+3=6differentways.【标注】23、【答案】B;【解析】Letℎcmbethelengthoftheunknownsideoftherectangle.Thereforetheradiofthethreesemi-circles,in
cm,areℎ,ℎ−5andℎ−7.Therefore,byconsideringthelongersideoftheectangle,wehave2(ℎ+ℎ−5+ℎ−7)=36.Thishassolutionℎ=10.Thereforetheperimetertherectangle,incm,is2⋅(36+10)=92【标注】24、【答案】D;【解析】Inorderforastudenttoreceivetheballagainafterpassingiton,theballmustbypassamultipleof50students.Astheballiscatchedbyevery6thstudent,itmustalsohavebypassedamultipleof6studentsatanygiventime.Therefore,theballmustbypass150(theLCMof50and6)studentsforthefirststudenttoreceivetheballagain.Beforethisoccures,theballhasbeenpassedto150/6=25studentsandwecanbesurethatnotwostudentsarethesamebecausethiswouldtakeatleast150passes.Afterthefirststudentreceivetheballagainandstartpassingitaroundforthesecondtime,thepassingpatternrepeatitselfandthesame25playerswillgettheballagain,meaningtheother25playerswillnevertouchtheball.【标注】25、【答案】D;【解析】Letaandbbethemissingvaluesintheboxesintheleft-handsideandright-handsideofthebottomrowrespectively.Thereforethevaluesintheboxesinthemiddlerowareanandbnandthev
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