GRE（QUANTITATIVE）模拟试卷2（共319题）

GRE（QUANTITATIVE）模拟试卷2（共9套）（共319题）GRE（QUANTITATIVE）模拟试卷第1套一、数值比较题(本题共12题，每题1.0分，共12分。)1、m,p,andxarepositiveintegersandmp=xColumnAColumnBmxA、ifthequantityinColumnAisgreaterB、ifthequantityinColumnBisgreaterC、ifthetwoquantityareequalD、iftherelationshipcannotbedeterminedfromtheinformationgiven标准答案：D知识点解析：m、p和x都是正整数，且mp=x。解：本题的正确答案为(D)。由于题目中并没有说明m、p和x是互不相同的正整数，所以当p=1时可解得m=x；当p≠1时可解得x>p。综上所述m和x的大小无法判断。2、ColumnAColumnBThenumberthatisasmuchgreaterthan63asitislessthan10184A、ifthequantityinColumnAisgreaterB、ifthequantityinColumnBisgreaterC、ifthetwoquantityareequalD、iftherelationshipcannotbedeterminedfromtheinformationgiven标准答案：B知识点解析：本题的正确答案是(B)。左项为比63大的量与比101小的量相同的数，注意题中that引导的定语从句修饰前面的“thenumber”，而“asmuchas”是指什么和什么一样多，因此可设该数为x，由题意可得：x-63=101-x→x=823、AK-numberisapositiveintegerwiththespecialpropertythat3timesitsunits’digitisequalto2timesitstens’digit.ColumnAColumnBThenumberofK-numbersbetween10and993A、ifthequantityinColumnAisgreaterB、ifthequantityinColumnBisgreaterC、ifthetwoquantityareequalD、iftherelationshipcannotbedeterminedfromtheinformationgiven标准答案：C知识点解析：K是一个具有特殊性质的正整数：其个位数(units)的3倍等于十位数(tens)的2倍。解：本题的正确答案为(C)。该题中的K-number为题中定义的一个函数，其个位数与十位数的关系为：3m=2n(m为个位数，n为十位数)。题目中的左项为10到99之间的K整数的数目，而满足方程3m=2n的数只有m=2，4，6；n=3，6，9。也就是10至99之间的K整数有32，64，96。4、nisaneveninteger.ColumnAColumnBThenumberofdifferentprimefactorsofnThenumberofdifferentprimefactorsof2nA、ifthequantityinColumnAisgreaterB、ifthequantityinColumnBisgreaterC、ifthetwoquantityareequalD、iftherelationshipcannotbedeterminedfromtheinformationgiven标准答案：C知识点解析：本题的正确答案为(C)。比较的左项为n的不同质因子(primefactor)数，比较的右项为2n的不同质因子数。对于2来说，只有1个质因子，即2本身；而n为偶数，所以2本来就是n的质因子，因此，n与2n的质因子数相同。5、x>zy>zColumnAColumnBx+yzA、ifthequantityinColumnAisgreaterB、ifthequantityinColumnBisgreaterC、ifthetwoquantityareequalD、iftherelationshipcannotbedeterminedfromtheinformationgiven标准答案：D知识点解析：本题的正确答案是(D)。考生在做该题时一定要注意思维的严密性。也就是说考生不但要注意到正数是越加越大，而且要注意到负数是越加越小。只要考生能想到这一点，就不会把本题做错。当x和y都是正数时，显然有x+y>z；但是当x和y都是负数时，则不能判定x+y与z孰大孰小。例如：-1>-2，-1.1>-2，那么x+y=-2.1就小于-2了，所以本题应为无法判断。6、Jillhas6xredmarblesandAygreenmarbles.BillhashalfasmanyredmarblesasJill,buthehastwiceasmanyredmarblesandgreenmarblescombinedasJill.ColumnAColumnBThenumberofgreenmarblesthatBillhas9x+8yA、ifthequantityinColumnAisgreaterB、ifthequantityinColumnBisgreaterC、ifthetwoquantityareequalD、iftherelationshipcannotbedeterminedfromtheinformationgiven标准答案：C知识点解析：Jill有6x颗红色弹珠和4y颗绿色弹珠。Bill的红色弹珠数是Jill的一半，但是他的红色弹珠和绿色弹珠数之和是Jill的两倍。比较Bill拥有的绿弹珠数与9x+8y。解：本题的正确答案为(C)。Bill的红弹珠数应为3x；由题意中得他的绿色弹珠应为：(6x+4y)×2-3x=9x+8y7、Anidentificationcodereadfromlefttorightconsistsof2digits,adash,3digits,adash,andthen4digits.Eachdigitcanbeanynumberfrom0through9.ColumnAColumnBThenumberofdifferentidentificationcodespossibleA、ifthequantityinColumnAisgreaterB、ifthequantityinColumnBisgreaterC、ifthetwoquantityareequalD、iftherelationshipcannotbedeterminedfromtheinformationgiven标准答案：C知识点解析：一个识别密码(identificationcode)从左至右包括2个数字，1个连字符号，3个数字，1个连字符号，然后是4个数字，每个数字可以是0至9的任一个。解：本题的正确答案是(C)。题目中比较的左项是所有可能的密码数，dash指连字符号，如123-456中的“-”，它与密码数无关。密码中共有9个数字，每个数字都可能是0至9这10个数字中的一个，所以共有种可能。8、Eachpersonatapartyshookhandsexactlyoncewitheachoftheotherpeopleattheparty.Therewasatotalof21handshakesexchangedattheparty.ColumnAColumnBThenumberofpeopleattheparty8A、ifthequantityinColumnAisgreaterB、ifthequantityinColumnBisgreaterC、ifthetwoquantityareequalD、iftherelationshipcannotbedeterminedfromtheinformationgiven标准答案：B知识点解析：参加某次舞会中的每个人都与其他的所有与会者刚好握一次手。在这个舞会中共有21次握手。解：本题的正确答案为(B)。设出席舞会的人数为n，则握手的总次数=n!/[2!(n-1)!]=n(n-1)/2=21so,n2-n-42=0。解二次方程可得，n=-6或n=7，舍去负根得出席这次舞会的人数为7。9、Thediameterofthecircleis10.ColumnAColumnBTheareaoftheregionenclosedbyquadrilateralABCD40A、ifthequantityinColumnAisgreaterB、ifthequantityinColumnBisgreaterC、ifthetwoquantityareequalD、iftherelationshipcannotbedeterminedfromtheinformationgiven标准答案：D知识点解析：本题的正确答案为(D)。比较的左项为四边形(quadrilateral)ABCD的面积。四边形ABCD是不规则四边形，在计算其面积时，可以把它分成两个三角形计算。对于该题，因为A、B、C和D四点的位置不确定，因此其面积也是不确定的。考生可以观察到当B和D点向C点靠近时，四边形面积ABCD的面积将逐渐减小，且可以任意地小；而当B、D居中时，面积将逐渐增大，当ABCD为正方形时，ABCD的面积达最大值=1/2×10×5×2=50；综上所述，四边形ABCD的面积将在0至50之间波动，所以本题无法判断比较左项与右项的大小。10、Oisthecenterofthecircle.Theareaoftheshadedregionis3∏.ColumnAColumnBThedegreemeasureof△AOB120A、ifthequantityinColumnAisgreaterB、ifthequantityinColumnBisgreaterC、ifthetwoquantityareequalD、iftherelationshipcannotbedeterminedfromtheinformationgiven标准答案：C知识点解析：O是圆心，阴影区的面积是3∏解：本题正确答案是(C)。该题主要考扇形的面积与圆的面积之间的关系。有些考生认为∠AOB既可以是外角以可以是内角，所以本题的正确答案应该为(D)。在这一点上这类考生应当注意的：在GRE数学中，指某角时，若无特殊指明或加上某些符号表示时，一般指内角。11、Thealtitudeofacertaintriangularsailis2metersgreaterinlengththanitsbase.Theareaofthefaceofthesailis24squaremeters.ColumnAColumnBThelengthofthebaseofthesail4metersA、ifthequantityinColumnAisgreaterB、ifthequantityinColumnBisgreaterC、ifthetwoquantityareequalD、iftherelationshipcannotbedeterminedfromtheinformationgiven标准答案：A知识点解析：一三角帆的高度比底边长2米，帆面的面积等于24平方米。解：本题的正确答案为(A)。设底边边长为x米，则高为(x+2)米，由题意可得：S三角帆=1/2x(x+2)=24so,x=612、ColumnAColumnBTheareaoftheshadedregionshowninFigure1TheareaoftheshadedregionshowninFigure2A、ifthequantityinColumnAisgreaterB、ifthequantityinColumnBisgreaterC、ifthetwoquantityareequalD、iftherelationshipcannotbedeterminedfromtheinformationgiven标准答案：C知识点解析：本题的正确答案为(C)。该题是让考生比较两个图中阴影区的面积。仔细观察后都会发现，两个阴影区都是由两个等底等高的三角形组成的，它们的面积自然是相等的。二、计算题(本题共12题，每题1.0分，共12分。)13、Ofthepositiveintegersthataremultiplesof30andarelessthanorequalto360,whatfractionaremultiplesof12?A、1/6B、1/5C、1/3D、2/5E、1/2标准答案：E知识点解析：在小于等于360的30的正倍数中，12的倍数占了几分之几?解：本题的正确答案是(E)。该题也就是求30和12的最小公倍数占了小于等于360的30的正倍数的几分之几。解答该题的关键在于理解“of”这个介词的作用。意为“…中”，而that引导的定语从句修饰这些正整数，fraction译为分数，whatfraction译为几分之几?30与12的最小公倍数是60，是30的倍数并且小于等于360的正整数共有12个，很显然是60的倍数并且小于等于360的正整数共有6个，所以1/2是正确答案。14、Howmanyofthepositiveintegerslessthan25are2lessthananintegermultipleof4?A、2B、3C、4D、5E、6标准答案：E知识点解析：在比25小的正整数中，有多少个数比4的倍数小2?解：本题的正确答案为(E)。考生仔细考虑一下就会发现，该题其实就是找小于(25+2)的正整数中有多少是4的倍数，因为(25+2)÷4=6余1，所以有6个数比4的倍数小2。15、WhichofthefollowingnumbersisNOTthesumofthreeconsecutiveoddintegers?A、15B、75C、123D、297E、313标准答案：E知识点解析：下列哪一个不是3个连续奇整数(consecutiveoddinteger)的和?解：本题的正确答案是(E)。设3个连续奇整数分别为2n+1，2n+3，2n+5，其中n为正数，则3个连续奇整数的和=(2n+1)+(2n+3)+(2n+5)=3(2n+3)，因此3个连续奇整数的和必为3的倍数。本题中只有(E)不是3的倍数。16、Aschooldistricthas1,989computers,whichisapproximatelyonecomputerforevery68.6students.Ofthefollowing,whichistheclosestapproximation,inthousands,ofthenumberofstudentsintheschooldistrict?A、30B、120C、140D、160E、200标准答案：C知识点解析：一校区有1989台计算机，大约为68.6名学生一台，以千为单位，下面哪一项最接近校区的学生数?解：本题的正确答案为(C)。此题比较简单，大多数的考生都会这样来解这道题：由平均68.6人一台电脑可得该校区共有1989×68.6≈136,445≈140,000名学生。但是考生要注意的一点是，本题只是让求近似解，因此可以通过取近似值的办法来大大简化计算过程，1989≈2000，68.6≈70，由此可以口算出该校区学生人数为140千。17、Acertainspiralstaircaseisdesignedsothateachstepafterthefirstoneisturned20°counterclockwisefromtheoneimmediatelybelowit,howmanyofthestepsmakeup2.5completerevolutions?A、18B、36C、38D、45E、50标准答案：D知识点解析：某一螺旋梯按照高一级台阶相对于低一级台阶逆时针旋转20°来设计，问2.5圈的旋梯共有多少级台阶组成?解：本题的正确答案为(D)。“revolution”意为旋转一周，由题意可得台阶数为：360°×2.5÷20°=4518、Thesumofthefirst50positiveintegersis1,275.Whatisthesumoftheintegersfrom51to100,inclusive?A、2525B、2550C、325D、3775E、5050标准答案：D知识点解析：前50个正整数的和是1275，问从51至100的整数(包括51和100)的和是多少?解：本题的正确答案为(D)。为简化计算，考生可把从51到100之间的整数拆开来计算：51=50+1，52=50+2，…100=50+50，由此可得：51+52+…100=50×50+(1+2+…+50)=377519、Ifnisanyprimenumbergreaterthan2,whichofthefollowingCANNOTbeaprimenumber?A、n-4B、n-3C、n-1D、n+2E、n+5标准答案：E知识点解析：若n是任一个大于2的质数，下面哪一项不能是质数?解：本题的正确答案是(E)。考生在解这类数字规律题时应采用排除法，把选项代入逐个排除。(A)9-4=5；(B)14-3=11，(C)3-1=2，(D)3+2=5，(E)无论如何也得不到质数，因为大于2的质数都是奇数，奇数加5必为大于2的偶数，所以，n+5不可能是质数。20、Onthenumberlineabove,whatnumbercorrespondstoapointthatis2/5ofthedistancefrom10to40?A、6B、8C、12D、15E、22标准答案：E知识点解析：在左面的数轴上，哪一个数字所对应的点是10与40之间距离的2/5?解：本题的正确答案是(E)。大多数的考生容易误选(C)选项，但该题是问哪一点的坐标把10与40之间的距离分成2/5和3/5两段，所以计算未知点的坐标应当从10开始，即为（10+30）×2/5=22。21、Thevalueofywilldecreaseasthevalueofxincreasesinwhichofthefollowingequations?A、y=xB、y=x-2C、2-y=3-xD、2x-y=4E、x+2y=1标准答案：E知识点解析：下面哪个等式中的y值随x值的增加而减小?解：本题的正确答案为(E)。此题也就是让考生找y是x的减函数的选项。而题目中的五个选项都是一次线性方程，我们知道对于一次方程y=kx+b来说，当k大于零时，y是x的减函数；当k小于零时，y是x的增函数。在本题的五个选项中只有(E)选项的k值等于-1/2小于零。22、Anexperimenthasthreepossibleoutcomes,I,J,andK.Theprobabilitiesoftheoutcomesare0.25,0.35,and0.40,respectively.Iftheexperimentistobeperformedtwiceandthesuccessiveoutcomesareindependent,whatistheprobabilitythatKwillnotbeanoutcomeeithertime?A、0.36B、0.4C、0.6D、0.64E、0.8标准答案：A知识点解析：一个实验有3个可能的结果：I，J和K。这些结果出现的概率分别是0.25，0.35和0.4，若连续进行该实验两次，并且两次的结果相互独立，问K不是任一次试验结果的概率有多大?解：本题的正确答案是(A)。K不是第一次试验结果的概率为：1-0.4=0.6；同理K不是第二次试验结果的概率也为0.6，两次试验的结果相互独立，所以K不是任一次试验结果的概率为0.6×0.6=0.3623、Oneintegerwillberandomlyselectedfromtheintegers11to60,inclusive.Whatistheprobabilitythattheselectedintegerwillbeaperfectsquareoraperfectcube?A、0.1B、0.125C、0.16D、0.5E、0.9标准答案：A知识点解析：从11至60，包括11和60的整数中随机挑出一个数，问其是完全平方数(perfectsquare)或完全立方数(perfectcube)的概率是多少?解：本题的正确答案为(A)。11至60间的完全平方数有16，25，36，49；完全立方数有27，共5个数，11至60之间共有50个数，所以挑出的数为完全平方数或完全立方数的概率为5/50=0.1。24、Inasoccerleague,iftherewere10teams,andeachteamplayedeachoftheotherteams16times,howmanygamesdideachteamplay?A、144B、140C、134D、125E、106标准答案：A知识点解析：某一足球协会有10支球队，若每支队与其他各队都踢16场球，问每支球队踢多少场比赛?解：本题的正确答案是(A)。每个球队要与其他的9个球队中的每一个踢16场球，所以每个球队踢的球的总数是9×16=144场。三、图表题(本题共1题，每题1.0分，共1分。)25、In1987theaverage(arithmeticmean)populationofthethreemostpopulousofthetenselectedstateswasmostnearlyequaltoA、18millionB、19millionC、20millionD、21millionE、22million标准答案：D知识点解析：标题：1980年和1987年美国10个特定州的人口数据。在1987年，十个选定的州中人口最多的三个州的人口算术平均值最接近于多少？解：本题的正确答案为(D)。“populous”是人口众多的意思。根据表格中的数据可知，排在前面的A，B，C三个州的人口最多，分别为27663000，17825000和16789000，因此他们的算术平均值为：(27663000+17825000+16789000)/3=20749000。计算结果与21million最为接近。GRE（QUANTITATIVE）模拟试卷第2套一、数值比较题(本题共14题，每题1.0分，共14分。)Somequestionsgiveyoutwoquantities,QuantityAandQuantityB.Comparethetwoquantitiesandchooseoneofthefollowinganswerchoices:AifQuantityAisgreater;BifQuantityBisgreater;Cifthetwoquantitiesareequal;Difyoucannotdeterminetherelationshipbasedonthegiveninformation.Note:Informationand/orfigurespertainingtooneorbothofthequantitiesmayappearabovethetwocolumns.AnyinformationthatappearsinbothcolumnshasthesamemeaningforbothQuantityAandQuantityB.YouwillalsobeaskedDataInterpretationquestions,whicharegroupedtogetherandrefertothesametable,graph,orotherdatapresentation.Thesequestionsasktheexamineetointerpretoranalyzethegivendata.ThetypesofquestionsmaybeMultiple-choice(bothtypes)orNumericEntry.1、A、

B、

C、

D、

标准答案：B知识点解析：ThecorrectanswerisB.Oppositeanglesofaparallelogramarecongruent,orequal.Therefore,(s-6)=(r-4).Selectonevariableandsolve:s-6=r-4s=r+2Ifs=r+2,thensmustbegreaterthanr,andQuantityBisgreaterthanQuantityA.2、A、

B、

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标准答案：B知识点解析：ThecorrectanswerisB.Because1/12islessthan1/8subtracting—from1willresultinalargernumberthanwillsubtracting1/8from1.Therefore,QuantityBisgreaterQuantityA.3、A、

B、

C、

D、

标准答案：B知识点解析：ThecorrectanswerisB.Tosolvethisproblem,payattentiontothelocationofthenegativesign.QuantityA=-(4×4)=-16.QuantityB=(-4×-4)=16.4、A、

B、

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标准答案：C知识点解析：ThecorrectanswerisC.Toeasilysolvethisproblem,recognizethat(4x)(7y)=28xy.Therefore,nomatterwhatvalueyouassigntoeitherxory,thequantitieswillbethesame.5、A、

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标准答案：A知识点解析：ThecorrectanswerisA.Tosolvethisproblemsetup3equations:Mike=Tom-3Mark=Tim+8Tom=Tim+9Substitute(Tim+9)forTominthefirstequation:Mike=Tim+9-3=Tim+6.IfMike=Tim+6andMark=Tim+8,thenMark=Mike+2.Therefore,Mark’sageisgreaterMike’sage,andQuantityAisgreaterthanQuantityB.6、A、

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标准答案：A知识点解析：ThecorrectanswerisA.Tosolvethisproblem,letxbetheradiusofeachracquetball.Theheightofthesixracquetballs,then,is12x,becausethediameterisequalto2x.Theracquetballsarecircles,sothecircumferenceofeachracquetballis2πx.QuantityA,thesumofthecircumferencesofthreeracquetballs,is6πx.Thevalueofπisapproximately3.14,so6πxwillbegreaterthan12x,andQuantityAisgreaterthanQuantityB.7、A、

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标准答案：A知识点解析：ThecorrectanswerisA.Thenumberofmaledogsis17-5or12.Thefractionofmaledogsinthekennelis12/17.Theratiooffemaletomaledogsis5/12.Therefore,QuantityAisgreaterthanQuantityB.EachofQuestions1to7presentstwoquantities,QuantityAandQuantityB.Comparethetwoquantities.Youmayuseadditionalinformationcenteredabovethequantitiesifsuchinformationisgiven.Chooseoneofthefollowinganswerchoices:AifQuantityAisgreater;BifQuantityBisgreater;Cifthetwoquantitiesareequal;Difyoucannotdeterminetherelationshipbasedonthegiveninformation.8、A、

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标准答案：D知识点解析：ThecorrectanswerisD.QuantityBislargerwhenx>1;quantitiesAandBareequalwhenx=l.Becausethevalueofxisnotspecified,youcannotdeterminearelationshipbetweenthequantities.9、A、

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标准答案：C知识点解析：ThecorrectanswerisC.Tosolvethisproblem,substitutethegivenvaluesintotheequationforQuantityA:Ifs=10,then(s-3)2=(10-3)2=49Ifs=-4,then(s-3)2=(-4-3)2=49Therefore,bothquantitiesareequal.10、A、

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标准答案：D知识点解析：ThecorrectanswerisD.EventhoughyouknowthatACisastraightline,youdon’tknowwhereBfallsinarcABC,becauseyouarenotgivenavalueforeitheroftheangles,andyoudonotknowwhereBOintersectsAC.11、A、

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标准答案：D知识点解析：ThecorrectanswerisD.Tosolvethisproblem,pickvaluesforrandsubstitutethemintoeachequation.Forexample,whenr=200,r-125=75,and300-r=100.Inthiscase,QuantityBisgreater.However,whenr=300,r-145=155,and300-r=0andQuantityAisgreater.Youcannotdeterminearelationshipbetweenthetwoquantities.12、A、

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标准答案：A知识点解析：ThecorrectanswerisA.Thesumofthelengthsofthetwosidesofatriangleisalwaysgreaterthanthelengthofthethirdside;thus,QR13、A、

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C、

D、

标准答案：D知识点解析：ThecorrectanswerisD.Tosolvethisproblem,youshouldfirstexpandQuantityAusingtheFOILmethod:MultiplytheFirstterms:x2MultiplytheOutsideterms:2xMultiplytheInsideterms:3xMultiplytheLastterms:6Nowaddthetermstogether:x2+5x+6.QuantityBisx2+6.Becausethevalueofxcouldbeeitherpositiveornegative,QuantityAcouldbeeithergreaterthanorlessthanQuantityB.Therefore,youcannotdeterminearelationshipbetweenthetwoquantities.14、A、

B、

C、

D、

标准答案：C知识点解析：ThecorrectanswerisC.Tosolvethisproblem,multiplybothsidesofthegivenequationby3toget9w+6v-3z=9w.Next,subtract9wfrombothsidestoget6v-3z=0.Nowyoucansolveforzintermsofv,asfollows:6v=3z2v=zBothquantitiesareequal.二、计算题(本题共17题，每题1.0分，共17分。)15、If65percentofthepeoplewhopurchaseacertainmodelofacararemale,whatistheratioofthenumberofmaleswhopurchasethemodeltothenumberoffemaleswhopurchasethemodel?A、13/10B、13/7C、7/13D、7/10E、7/5标准答案：B知识点解析：ThecorrectanswerisB.Because65percentofthepeoplearemale,thentherestofthe100percentmustbefemale;therefore,100-65,or35percentofthepeoplearefemale.If100peoplepurchasedthisparticularmodelofcar,thentheratioofmalestofemaleswouldbe65/35,whichreducesto13/7.16、Whichofthefollowingisthesumoftwopositiveintegerswhoseproductis36?A、1B、11C、15D、17E、19标准答案：C知识点解析：ThecorrectanswerisC.Tosolvethisproblem,considerthepairsofpositiveintegerswhoseproductis36:1and36;2and24;3and12;4and9;and6and6.Theonlypairwhosesumisananswerchoiceis3+12,or15.17、Therearesixmembersonacommittee,fourofwhomarewomenandtwoofwhomaremen.ThemembersagreetorandomlypulltwonamesoutofahattoserveasChairandSecretaryforthegroup,respectively.Whatistheprobabilitythatbothofthemenarechosen?Givetheprobabilityasafraction.______标准答案：1/15orequivalentfraction知识点解析：Thecorrectansweris1/15oranyequivalentfraction.Sincethereare6namesinthehatand2aremen,theprobabilitythatthefirstnamedrawnisamanis2/6=1/3.Oftheremaining5namesinthehat,only1isaman,sothechancesthathewillbechosenare1in5.Tofindtheprobabilityofbotheventsoccurring,take.18、Ifthedegreemeasuresoftheanglesofatriangleareintheratio2:3:4,whatisthedegreemeasureofthesmallestangle?A、15°B、20°C、40°D、45°E、60°标准答案：C知识点解析：ThecorrectanswerisC.Ifthedegreemeasuresoftheanglesofatriangleareintheratio2:3:4,thenthesmallestanglewillconstitute,or2/9ofthesumofthethreeanglesofthetriangle.Becausealltrianglesarecomposedofthreeangleswhosesumis180°,thedegreemeasureofthesmallestaneleis2/9of180°,or40°.19、If4morethantwicenisanegativenumberand6morethannisapositivenumber,whichofthefollowingnumberscouldbethevalueofn?Selectallsuchnumbers.A、-5B、-4C、-3标准答案：A,B,C知识点解析：ThecorrectanswerisA,B,andC.Tosolvethisproblem,firsttranslatethewordsintotheirmathematicalequivalents:4morethantwicentranslatesto4+2n.Youaregiventhatthisquantityisanegativenumber,whichtranslatesto4+2n<0.6morethanntranslatesto6+n.Youaregiventhatthisquantityisapositivenumber,whichtranslatesto6+n>0.Solveeachinequalityasfollows:4+2n<0n<-26+n>0n>-6So,ncouldbeanynumberlessthan-2andgreaterthan-6.20、Ifa+c=13andb-c=6,thena+b=?A、7B、13C、19D、22E、26标准答案：C知识点解析：ThecorrectanswerisC.Giventhata+c=13andb-c=6,thequantitya+bcanbedeterminedbysubstitution.Ifa+c=13,thenc=13-a.Substitutingc=13-aintoo-c=6yieldsthefollowing:b-(13-a)=6b-13+a=6b+a=6+13a+b=1921、Inthefigureabove,whatisthevalueofa?A、15°B、25°C、30°D、45°E、115°标准答案：A知识点解析：ThecorrectanswerisA.Tosolvethisproblem,recalltherelationshipsbetweenoppositeangles.Youaregiventheanglemeasuresoftwoanglesinoneofthetrianglesinthefigure:40°and25°.Therefore,thethirdanglemustmeasure180°-40°-25°=115°.Theangleoppositethisanglewillalsomeasure115°.Younowknowtwooftheanglemeasuresforthetrianglecontaininganglea,andcancalculatethevalueofanglea:180°-50°-115°=15°.22、Agiftboxhasedgesof2inches,3inches,and7inches.Whatisthesurfaceareaofthebox,insquareinches?______标准答案：82知识点解析：Thecorrectansweris82.Tocalculatethesurfacearea,firstcalculatetheareaofeachsideofthebox:2sideswillhaveanareaof2x3=6squareinches.2sideswillhaveanareaof2x7=14squareinches.2sideswillhaveanareaof3x7=21squareinches.Therefore,thesurfaceareaoftheboxis2(6)+2(14)+2(21)=82.23、Iftheaverage(arithmeticmean)oftwonumbersis16andoneofthenumbersisx,whatistheothernumberintermsofx?A、16-xB、16-2xC、16+xD、32-xE、32-2x标准答案：D知识点解析：ThecorrectanswerisD.Iftheaverageoftwonumbers,xandsomeothernumberwe’llcally,is16,then=16.Thusx+y=32andy=32-x.24、A、0.017328B、0.17328C、1.7328D、17.328E、17328标准答案：C知识点解析：ThecorrectanswerisC.Multiplying173.28by1/100isthesameasdivid100ing173.28by100,whichwillhavetheeffectofreducingthequantity.YoucaneliminateanswerchoiceE.Whendividingby100,thedecimalpointismovedtwoplacestotheleft.Thus,173.28×=1.7328.25、MandyandJordaneachboughtsomenotebooksandathree-ringbinder.Mandypaid$5.85for3notebooksand1binder.Jordanpaid$4.65for2notebooksand1binder.Whatisthepriceofoneofthenotebooks?A、$2.70B、$2.25C、$1.80D、$1.20E、$0.75标准答案：D知识点解析：ThecorrectanswerisD.Tosolvethisproblem,setupasystemofequationsandsolveforn:3n+b=5.852n+b=4.65n=1.2026、Whichofthefollowingisnotadivisorof336?A、6B、7C、8D、9E、12标准答案：D知识点解析：ThecorrectanswerisD.Tosolvethisproblem,simplydivide336byeachoftheanswerchoicesandseewhichonedoesnotcomeoutevenly.Thenumber336canbeevenlydividedby6,7,8,and12,butnot9.27、Inthefigureabove,XY=YZ.Ifangle7=40°,thenangleX=?______°标准答案：70知识点解析：Thecorrectansweris70.Tosolvethisproblem,recognizethattheanglesoppositethecongruentsideswillalsobecongruent.Thetotaloftheseanglesmustbe180-40=140,sobothangleXandangleZwillequal70°.28、A、5B、12C、24D、33E、41标准答案：C知识点解析：ThecorrectanswerisC.Tosolvethisproblem,firstaddthevaluesintheparentheses:.Recallthatxx=x2.Thus,,whichequals24.29、AcertainhighwayhasExits1,2,3,and4inthatorder.Whichofthefollowingstatementsindividuallyprovide(s)sufficientadditionalinformationtodeterminethedistancefromExit2toExit3?Selectallsuchstatements.A、ThedistancefromExit1toExit3is7miles,andthedistancefromExit3toExit4is4miles.B、ThetotaldistancefromExit1toExit4is23miles,thedistancefromExit1toExit2is3miles,andthedistancefromExit3toExit4is9miles.C、ThetotaldistancefromExit1toExit4is23miles,andthedistancefromExit2toExit4is20miles.标准答案：B知识点解析：ThecorrectanswerisB.Toanswerthisquestion,youneedinformationaboutthedistancebetweenallfourexits;therefore,Statement(A)aloneisnotsufficient.Statement(B)givesyousufficientinformationtocalculatethedistancebetweenExit2andExit3:theentiredistanceis23miles,thedistancebetweenExit1andExit2is3miles,thedistancebetweenExit3andExit4is9miles,whichmeansthatthedistancebetweenExit2andExit3is23-3-9=11.Statement(C)doesnotprovidesufficientinformationtodeterminethedistancefromExit2toExit3.30、Theaverageofasetofsixintegersis3Whenaseventhnumberisincludedintheset,theaverageofthesetincreasesto4Whatistheseventhnumber?标准答案：101知识点解析：Thecorrectansweris101.Iftheaverageofthesixintegersis38,thenthetotalmustbe6x38=228.Iftheaverageofthesevenintegersis47,thenthetotalmustbe7x47=329.Youareaddingtheseventhintegertotheset,sothevalueoftheseventhintegerwillbe329-228=101.31、Whatisthearea,insquareinches,ofacirclewithadiameterequalto12inches?A、144B、36C、12πD、36πE、144π标准答案：D知识点解析：ThecorrectanswerisD.Acirclewithdiameter12incheshasaradiusof6inches.TheareaofacircleisA=πr2,whereristheradius.Therefore,theareaofthecircleisπ62=36π.三、图表题(本题共9题，每题1.0分，共9分。)32、In1990,thetotalrevenueforwidgetssoldwasabouthowmanytimesasgreatasthenumberofwidgetssold?A、3B、10C、65D、98E、120标准答案：D知识点解析：ThecorrectanswerisD.Accordingtothegraphs,in1990totalrevenuewas$29millionandthenumberofwidgetssoldwas295,000.Because295,000isslightlylessthan10%of29,000,000,thetotalrevenuemusthavebeenjustunder100timesgreaterthanthenumberofwidgetssold.33、In1970,ifthecosttoproduceonewidgetwas$0.07,whatwouldhavebeenthetotalcosttoproducethenumberofwidgetssoldduringthatyear?______标准答案：22750知识点解析：Thecorrectansweris22,750.Accordingtothegraphs,in1970,325,000widgetsweresold;at$0.07perwidget,thetotalcostwouldhavebeen325,000($0.07),or$22,750.34、Thepercentdecreaseinaveragenumberofproductionhoursperwidgetfrom1990to2000wasapproximatelyA、44%B、36%C、34%D、32%E、27%标准答案：A知识点解析：ThecorrectanswerisA.Accordingtothegraphs,from1990to2000,theaveragenumberofproductionhoursperwidgetdecreasedfrom9to5.Tocalculatethepercentdecrease,dividethedifferencebetweenthestartingvalueandendingvalue(9-5)bythestartingvalue:4/9=0.44,whichisequivalentto44%.35、Inhowmanyoftheyearsshownwasthenumberofwidgetssoldatleastthreetimesthenumberofwidgetssoldin1960?A、FourB、ThreeC、TwoD、OneE、None标准答案：D知识点解析：ThecorrectanswerisD.Thefirststepinsolvingthisproblemistocalculatethreetimesthenumberofwidgetssoldin1960.Accordingtothegraphs,thenumberofwidgetssoldin1960was115,000;115,000(3)=345,000.Theonlyyearinwhichmorethan345,000widgetssoldwas1980(490,000widgetssold).36、Thenumberofhamburgerssoldatastandnearthebeachforagivenweekinthesummerisshowninthepreviouschart.Approximatelywhatwastheratioofhamburgerssoldontheweekdays(MondaythroughFriday)tohamburgerssoldontheweekend(SaturdayandSunday)?A、2:5B、16:29C、3:4D、29:16E、5:2标准答案：D知识点解析：ThecorrectanswerisD.Thegraphshowsapproximately125,100,125,150,and225hamburgerssold,MondaythroughFriday.Thesumofthesesalesisapproximately725hamburgers.Approximately400hamburgersweresoldovertheweekend,sotheratiois725:400,whichreducesto29:16.Andrewfittedanelectrictoycarwithhardrubberwheelsthathaddeeptreadsandplacedthecaronasmooth,flatsurface.Andrewstartedthecarandastopwatchatthesametime.Andrewstoppedthestopwatchasthecarcrossedthe75-footmark.Hecalculatedtheresultsof3separatetrialsasshowninthetablebelow.Andrewrepeatedtheprocedure,excepthefittedthecarwithsoftrubberwheelsthatweresmoothandlackedtreads.Theresultsareshowninthetablebelow.37、Whatwastheaveragetimethecarwiththesoftwheelstooktocrossthe75-footmark?A、22.8secondsB、33.9secondsC、39.8secondsD、56.7secondsE、170.1seconds标准答案：D知识点解析：ThecorrectanswerisD.Thesoftwheelsdataisinthesecondtable.Calculatetheaverageofthosethreetimes:(57.0+56.4+56.7)+3=56.738、Assumingthatthecartraveledataconstantspeed,approximatelyhowfarhadthecarwithhardwheelstraveledinTrial3after11.25seconds?A、22.5feetB、37.5feetC、75.0feetD、253.125feetE、Notenoughinformationisgiven.标准答案：B知识点解析：ThecorrectanswerisB.Sincethecartraveledataconstantspeed,youcansetupaproportionbetweenthetimeanddistanceofthewholerunandthetimeanddistanceofthepartialrun.75x11.25=22.5x843.75=22.5x37.5=xTherefore,thecartraveled37.5feetin11.25seconds.