新高考数学二轮复习分层训练专题03 不等式（原卷版）

答案第=page11页，共=sectionpages22页解密03讲：不等式【练基础】一、单选题1．（2022·四川·中和中学高三模拟）若SKIPIF1<0，则下列不等式一定成立的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·广东湛江·高三阶段练习）已知SKIPIF1<0，则下列说法正确的是（

）A．若SKIPIF1<0，则SKIPIF1<0 B．若SKIPIF1<0，则SKIPIF1<0C．若SKIPIF1<0，且SKIPIF1<0，则SKIPIF1<0 D．若SKIPIF1<0，SKIPIF1<0，则SKIPIF1<03．（2021·安徽·高三阶段练习（文））已知a，b>1且a≠b，下列各式中最大的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·重庆·高三阶段练习）关于SKIPIF1<0的不等式SKIPIF1<0恒成立，则实数SKIPIF1<0的取值范围为（

）.A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2023·全国·高三专题练习）对任意不相等的两个正实数SKIPIF1<0，SKIPIF1<0，满足SKIPIF1<0的函数是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<06．（2023·内蒙古赤峰·高三阶段练习（文））已知实数SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，则下列说法中，正确的是（

）．A．SKIPIF1<0 B．存在a，b，使得SKIPIF1<0C．SKIPIF1<0 D．存在a，b，使得直线SKIPIF1<0与圆SKIPIF1<0相切7．（2023·四川资阳·模拟预测（文））已知a，b均为正数，且SKIPIF1<0，则SKIPIF1<0的最小值为（

）A．8 B．16 C．24 D．328．（2022·山东聊城·高一期中）已知SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，不等式SKIPIF1<0恒成立，则正实数SKIPIF1<0的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0二、多选题9．（2022·福建·莆田一中高三阶段练习）已知关于SKIPIF1<0的不等式SKIPIF1<0解集为SKIPIF1<0，则（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．不等式SKIPIF1<0的解集为SKIPIF1<010．（2022·湖北·咸丰春晖学校高三阶段练习）若SKIPIF1<0，则下列不等式中一定不成立的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<011．（2022·安徽·合肥一中高三阶段练习）不等式SKIPIF1<0对任意SKIPIF1<0恒成立，则下列关系正确的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<012．（2022·山东聊城·高三模拟）设SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，则下列说法中正确的是（

）A．SKIPIF1<0有最小值SKIPIF1<0 B．SKIPIF1<0有最大值SKIPIF1<0C．SKIPIF1<0有最大值SKIPIF1<0 D．SKIPIF1<0有最小值SKIPIF1<0三、填空题13．（2022·广东·广州市番禺区大龙中学高三阶段练习）若SKIPIF1<0则SKIPIF1<0的最小值是__________.14．（2022·河北·高三阶段练习）若关于SKIPIF1<0的不等式SKIPIF1<0在区间SKIPIF1<0内有解，则实数SKIPIF1<0的取值范围是______.15．（2022·江苏·高三课时练习）在SKIPIF1<0中，设边SKIPIF1<0所对的角为SKIPIF1<0，若SKIPIF1<0，则SKIPIF1<0的最大值为________．16．（2022·山西临汾·高三阶段练习）已知SKIPIF1<0，若SKIPIF1<0是SKIPIF1<0与SKIPIF1<0的等比中项，则SKIPIF1<0的最小值为__________．四、解答题17．（2022·陕西·兴平市南郊高级中学高三阶段练习）已知函数SKIPIF1<0，SKIPIF1<0的解集为SKIPIF1<0或SKIPIF1<0.(1)求实数SKIPIF1<0、SKIPIF1<0的值；(2)若SKIPIF1<0时，求函数SKIPIF1<0的最大值.18．（2022·江苏·句容碧桂园学校高三开学考试）已知不等式SKIPIF1<0的解集为SKIPIF1<0，不等式SKIPIF1<0的解集为SKIPIF1<0．(1)若SKIPIF1<0，不等式SKIPIF1<0的解集为SKIPIF1<0，求不等式SKIPIF1<0的解集；(2)SKIPIF1<0，SKIPIF1<0，求a的取值范围．19．（2020·河南新乡·高二期中（文））（1）比较SKIPIF1<0与SKIPIF1<0的大小（2）已知SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，证明：SKIPIF1<020．（2021·江西·高二阶段练习（理））设函数SKIPIF1<0.(1)当SKIPIF1<0时，求关于SKIPIF1<0的不等式SKIPIF1<0的解集；(2)若SKIPIF1<0，当SKIPIF1<0时，不等式SKIPIF1<0恒成立，求实数SKIPIF1<0的取值范围.21．（2023·广东·惠来县第一中学高三阶段练习）已知实数SKIPIF1<0，SKIPIF1<0，(1)若SKIPIF1<0，求SKIPIF1<0的最小值．(2)若SKIPIF1<0，求SKIPIF1<0的最大值与SKIPIF1<0的最小值；(3)求SKIPIF1<0的最大值，并求此时x的值；22．（2022·浙江·杭十四中高三专练）已知函数SKIPIF1<0.(1)当SKIPIF1<0时，解关于SKIPIF1<0的不等式SKIPIF1<0.(2)不等式SKIPIF1<0对任意SKIPIF1<0恒成立，求实数SKIPIF1<0的取值范围.【提能力】一、单选题1．（2022·浙江·镇海中学高三期中）已知SKIPIF1<0，则（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·天津市第七中学高三期中）若SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，则SKIPIF1<0，SKIPIF1<0，SKIPIF1<0的大小关系是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·山东聊城一中高三期中）对于实数a，b，c，下列命题中正确的是（

）A．若SKIPIF1<0，则SKIPIF1<0B．若SKIPIF1<0，则SKIPIF1<0C．若SKIPIF1<0，则SKIPIF1<0D．若SKIPIF1<0，则SKIPIF1<04．（2022·江苏泰州·高三期中）对任意正数x，y，不等式x（x+y）≤a（x2+y2）恒成立，则实数a的最小值为（）A．SKIPIF1<0 B．SKIPIF1<0﹣1 C．SKIPIF1<0+1 D．SKIPIF1<05．（2022·江西赣州·二模（理））在等差数列SKIPIF1<0和等比数列SKIPIF1<0中，有SKIPIF1<0，且SKIPIF1<0，则下列关系式中正确的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2022·陕西·西安市第三中学高三阶段练习）已知正数SKIPIF1<0满足SKIPIF1<0，则SKIPIF1<0的最小值为（

）A．1 B．SKIPIF1<0 C．2 D．SKIPIF1<07．（2022·贵州贵阳·高三阶段练习（理））已知函数SKIPIF1<0的图像恒过一点P，且点P在直线SKIPIF1<0的图像上，则SKIPIF1<0的最小值为（

）A．4 B．6 C．7 D．88．（2022·山东省青岛第五十八中学高三期中）已知对任意SKIPIF1<0，且SKIPIF1<0，SKIPIF1<0恒成立，则SKIPIF1<0的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0二、多选题9．（2022·广东·广州市第九十七中学高三阶段练习）下列几种说法中，正确的是（

）A．“SKIPIF1<0”是“SKIPIF1<0”的充要条件B．命题“SKIPIF1<0，SKIPIF1<0”的否定是“SKIPIF1<0，SKIPIF1<0”C．若不等式SKIPIF1<0的解集是SKIPIF1<0，则SKIPIF1<0的解集是SKIPIF1<0D．“SKIPIF1<0”是“不等式SKIPIF1<0对一切SKIPIF1<0都成立”的充要条件10．（2022·湖南经纬实验学校高三期中）以下命题为真命题的是（

）A．不等式SKIPIF1<0的解集为SKIPIF1<0.B．方程SKIPIF1<0有异号根的充要条件是SKIPIF1<0C．若SKIPIF1<0，SKIPIF1<0，则SKIPIF1<0D．“SKIPIF1<0”是“SKIPIF1<0”的充分不必要条件11．（2022·重庆十八中高三阶段练习）不等式SKIPIF1<0对任意SKIPIF1<0恒成立，则（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<012．（2022·辽宁·东北育才学校高三阶段练习）已知正实数SKIPIF1<0，满足SKIPIF1<0，则（

）A．SKIPIF1<0的最大值为1 B．SKIPIF1<0的最小值为4C．SKIPIF1<0的最小值为1 D．SKIPIF1<0的最小值为18三、填空题13．（2022·福建泉州·高三期中）已知函数SKIPIF1<0与函数SKIPIF1<0有公共点，则SKIPIF1<0的最小值为______.14．（2023·全国·高三专题练习）若SKIPIF1<0，使SKIPIF1<0成立，则实数SKIPIF1<0的取值范围是______________．15．（2022·福建省福州第十一中学高三期中）已知SKIPIF1<0，SKIPIF1<0，直线SKIPIF1<0与直线SKIPIF1<0垂直，则SKIPIF1<0的最小值是___________.16．（2022·安徽·合肥一六八中学高三阶段练习）已知函数SKIPIF1<0，SKIPIF1<0为直线SKIPIF1<0上一点，过点SKIPIF1<0作函数SKIPIF1<0图象的两条切线，切点分别为A，B，则SKIPIF1<0的最小值为____________．四、解答题17．（2022·陕西·永寿县中学高三阶段练习（文））已知命题p：SKIPIF1