C++第4次作业.doc

1. 设计并测试一个名为Rectangle的矩形类，其属性为矩形的左上角与右下角两个点的坐标，根据坐标能计算矩形的面积。（1） 实验目的：根据坐标求矩形的面积。（2） 实验分析：类的基础题，题目的主要难点在于函数的调用。（3） 程序代码：#includeusing namespace std;class Rectangle public:Rectangle(double newL1=0,double newL2=0,double newR1=0,double newR2=0);double GetArea() const;private:double left1,left2,right1,right2;Rectangle:Rectangle(double newL1,double newL2,double newR1,double newR2)left1=newL1;left2=newL2;right1=newR1;right2=newR2;double Rectangle:GetArea() constdouble Width = right1 - left1;double Height = right2 - left2;return (Width * Height);int main()Rectangle MyRectangle (10, 20, 50, 80 );double Area = MyRectangle.GetArea();cout 矩形的面积: Area endl;return 0;（4） 程序结果：2. 定义一个Circle类，有数据成员radius（半径），成员函数getArea（），计算圆的面积，构造一个Circle的对象进行测试。（1） 实验分析：构造一个Circle类来计算圆的面积。（2） 程序代码:#include#define Pi 3.14using namespace std;class Circleprivate:double Radius;public:Circle(double R)Radius=R;double GetArea();double Circle:GetArea()return Pi*Radius*Radius;void main()double i;cout请输入半径:i;Circle C(i);double area=C.GetArea();cout面积为:areaendl;（3） 运行结果:3. 设计一个类sample,实现两个复数的加法和减法运算。(1) 实验分析：题目不难，将复数的实部和虚部分开加减即可(2) 程序代码：#include class Sample private: double real; double imag;public: Sample(double r=0.0,double i=0.0); void print(); Sample Sample:operator+(Sample s); Sample Sample:operator-(Sample m); Sample:Sample(double r,double i) real=r;imag=i; Sample Sample:operator+(Sample s) Sample a; a.real=real+s.real; a.imag=imag+s.imag; return a; Sample Sample:operator-(Sample m) Sample a; a.real=real-m.real; a.imag=imag-m.imag; return a; void Sample:print() cout0)cout+; if(imag!=0)coutimagi; int main() double r1,i1,r2,i2; cout请输入第一个复数的实部和虚部:r1i1;cout请输入第二个复数的实部和虚部:r2i2; Sample s1=Sample(r1,i1),s2=Sample(r2,i2); Sample s3=s1+s2;cout两复数的和为:; s3.print(); coutendl;Sample m1=Sample(r1,i1),m2=Sample(r2,i2); Sample m3=m1-m2; cout两复数的差为:; m3.print(); coutendl;return 0; (3) 运行结果：4. 设计一个字符串类MYSTRING，具有构造函数、析构函数、拷贝构造函数等，尽可能的完善它，使之能满足各种需要。5. 参照下例：“小程序：看看你活了多少天？”编写如下程序：(1)用OOP方法改写上述程序，(编写类Date实现)。(2)编写一个时间类，它包含Date和Clock类对象；(3)求到现在你总共活了多少小时？例：小程序：看看你活了多少天/*filename:mylife.cpp*/#includeint dayspass(int y,int m,int d);/求y年m月d日这年过了多少天int daysofyear(int y); /求y年共有多少天int daysleft(int y,int m,int d);/求y年m月d日这年还剩多少天void main()int y1,m1,d1,y2,m2,d2,days;couty1m1d1;couty2m2d2;days=daysleft(y1,m1,d1);for(int y=y1+1;ydays+=daysofyear(y);days+=dayspass(y2,m2,d2);coutYou have lived int dayspass(int y,int m,int d)int i,leap=0,md212=31,28,31,30,31,30,31,31,30,31,30,31,31,29,31,30,31,30,31,31,30,31,30,31;if(y%4=0&y%100!=0|y%400=0)leap=1;for(i=0;ireturn(d);int daysofyear(int y)if(y%4=0&y%100!=0|y%400=0)return(366);return(365);int daysleft(int y,int m,int d)return(daysofyear(y)-dayspass(y,m,d);（1） 实验分析：首先需要考虑闰年、平年，然后算出日期之间的年数，闰年乘以366，平年乘以355，再考虑出生那年的天数和现在这年的天数，最后乘以24就是所活的小时数。（2） 程序代码：#include using namespace std;class Datepublic:int year; int month; int day; bool isTrue(int y, int m, int d);Date() year = 1990; month = 1; day = 1; Date(int y, int m, int d) if (isTrue(y, m, d) year = y; month = m;day = d; else year = 1990; month = 1; day = 1; void display()coutyear-month-dayendl;void set(int x,int y,int z)year = x;month = y;day = z;void next()if (year%4 = 0) & (year%100 != 0) | (year%400 = 0)if (month=2)if(day=29)day = 1;month = 3;else day+;else if(month=4 | month=6 | month=9 | month=11)if(day=30)day = 1;month+;else day+;elseif(day=31)day = 1;if(month=12)month = 1;year+;else month+;else day+;elseif (month=2)if(day=28)day = 1;month = 3;else day+;else if(month=4 | month=6 | month=9 | month=11)if(day=30)day = 1;month+;else day+;elseif(day=31)day = 1;if(month=12)month = 1;year+;else month+;else day+;bool Date:isTrue(int y, int m, int d) if (y=0 | m=0 | d=0) return false; if (y%4 = 0) & (y%100 != 0) | (y%400 = 0) if (m = 2 & d = 29) return true; else if (m=4 | m=6 | m=9 | m=11) if (d=30) return true; else return false; if (m=2) if (d=28) return true; else return false; else if (d=31) return true; else return false;int application(Date data1,Date data2)int num = 0;for(int i=0;i+)if(data1.year=data2.year&data1.month=data2.month&data1.day=data2.day) break;data1.next();num+;return num;void main() c