




文档简介
is in is by as of is to of M to in in of in of is of of I. of is a to as of of of a 1-4. As a is a In a is of a or a to in to to it 5. To a is a of a to 6. As 1, x , y z of be of or of of be on is of z 1, is in it is to be of of of of in at OF of of OF a an a in of of 7. a of in of an in by of of in an 8 9. as is of to of of a . P. . J. 2, 39798, 1. of 05/$2005 1157 in as a of 0% of in is no 10. to be in of 11 12. EM M of A EM to M is to In a by is to be a as in to to by of is 3D to of in F . of of . on is to in of is to is as a on of to of of of By N ,000,000 13. is 0,000 50 In be at of is in of up 0,000 be on of in of to (2 10 2). or in of be of is a .5 mm a B. of of a as a). as is of As b), of a of to be to If of to of of be In of a of of at a F 0 1 2 3 2. of 1158 4. of be in on of as c). of Ms in in in so in A of is to Ms in as d). be by an of be to on it in of be 1= (1) F is 2F is is to be 2+ (2) T T by C. of he of be to of an by (3) 2 (4) oD iD of D of is 3. of we 0 (5) we 3208(1)(1)(6) C is Q is of in sn is in 3011 10, = (7) of as A is wK is EK is MF In . of is by is to be .3 be to a so as to of it to In gl is .5 ml is to .5 to I, be as is a to of of So 4. D (a) (b) (c) (d) 3. of (a) (b) (c) (d) 1159 is to 500 s of as a, b c on of a is as a be as a if by M be by of by an of by be as of of as of 14 15. s r a d of , as as =(8) ( )()2322bs = =(9) ( )()2cs = +=+(10) =(11) sN is of of in of b), , ) = 3/2, so = . be s (12) is of in of MF is to (13) ml mH is by of f fN i be 22 = (14) rB is r is is of 410 . of is as g , as 0(15) As an us of to in a /022/0() () . as s as s s +=(16) 22202()8as o i = (17) of we as bs cs = (18) o. of of of 30 of 6 .5 ir .5 8 2 8 0 ir of 16 I 500 0 s 160 22202()8f = (19) a f is 022/0()() . 4as s f r s if iP +=(20) In as be 202()L = (21) 2202()2 / 3 )8= (22) 2202()2 / 3 )8=+ (23) be (24) ()= ff cf fT ac bs ac cs L L = (25) is of 8)(19) 21)-(24). 31) be in = (26) be )( )1i 2f d = (27) sF be )2202222 2 2 2()s d i = =+(28) s sT be 203( )3()216dq qd f = (29) of Ms at is so at be (/)cg m + (30) is s is . F T be by g + ,1 28)(29) F T be by g , 2 z is of in 1) 2). of by of is of of of f= + (31) is in of is of be (3
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 公司自制销售管理制度
- 河南省郑州市中牟县2024~2025学年 高二下册3月月考数学试卷附解析
- 广东省汕尾市2024~2025学年 高二下册第一次(3月)月考数学试卷附解析
- 2024年宁波市宁海县机关事业单位招聘真题
- 身份验证漏洞基础知识点归纳
- 西宁市口腔医院招聘笔试真题2024
- 杭州市公安局滨江区分局招聘警务辅助人员笔试真题2024
- 深圳市福田区区属公办中小学招聘教师笔试真题2024
- 历史服饰风格角色设计师基础知识点归纳
- 2025年江苏省生物初赛试题
- 2025年中医基础理论考试试题及答案
- 外研版七年级英语上册跨学科项目计划
- 2025年瑜伽教练认证考试体式教学与课程设计模拟试题集(含答案详解)
- 2025年英语专业四级(TEM4)完形填空专项模拟试卷(词汇与逻辑推理)-深度解析版
- 2025年广西高一学业水平考试模拟生物试卷试题(含答案)
- 综合实践项目 设计并制作人体结构模型(教学设计) 七年级生物下册 (人教版2024)
- 思想道德与法治(湖南师范大学)智慧树知到期末考试答案章节答案2024年湖南师范大学
- 商品猪场日处理200立方污水处理工程设计预案
- 技术变更通知单(模版)
- 生物应试技巧 完整版课件
- 平行线新初一在线英语暑期分班测(剑桥think体系)测试题
评论
0/150
提交评论