C#求常见数学题目实例

1、C#求常见数学题目实例求除以7余5,除以5余2,除以3余1的所有三位数之和程序代码：using System;using System.Collections.Generic;using System.Text;namespace RemainerMaths class Program static void Main(string args) /求除以7余5,除以5余2,除以3余1的所有三位数之和 Console.WriteLine(除以7余5,除以5余2,除以3余1的所有三位数如下：); int from = 100; int to = 1000; int sum = 0; for (in

2、t i = from; i to; i+) if (i % 7 = 5 & i % 5 = 2 & i % 3 = 1) Console.WriteLine(i); sum += i; Console.WriteLine(除以7余5,除以5余2,除以3余1的所有三位数之和为：0, sum); Console.ReadLine(); 答案：1-9九个数字不重复组成一个三位数加法算式，求出所有组合：程序代码：using System;using System.Collections.Generic;using System.Text;namespace RemainerMaths class Pr

3、ogram static void Main(string args) int count = 0;/可能性个数 int a = 1, 2, 3, 4, 5, 6, 7, 8, 9 ; for (int i = 0; i a.Length; i+) for (int j = 0; j a.Length; j+) for (int k = 0; k a.Length; k+) if (ai != aj & aj != ak & ak != ai) /从9个数中随机找出3个数组成三位数 int add1 = 100 * ai + 10 * aj + ak; /将剩下的6个数字组成一个数组 int

4、b = GetNewArray(a, i, j, k); for (int x = 0; x b.Length; x+) for (int y = 0; y b.Length; y+) for (int z = 0; z b.Length; z+) if (bx != by & by != bz & bz != bx) /从这6个数中随机找出3个数组成三位数 int add2 = 100 * bx + 10 * by + bz; /将剩下的3个数字组成一个数组 int c = GetNewArray(b, x, y, z); /获得最后剩下的3个数字组成的所有三位数 int lastNumbe

5、r = GetAllThreeNumber(c); /如果两数之和等于第三个数就输出 for (int index = 0; index lastNumber.Length; index+) if (add1 + add2 = lastNumberindex) count+; Console.WriteLine(0 + 1 = 2, add1, add2, lastNumberindex); break; Console.WriteLine(共有0种情形-因加法存在交换律，则实际有1种情形。, count, count / 2); Console.ReadLine(); / / 由原数组，去除

6、掉索引在i、j、k处的元素后形成的新数组 / / / / / / static int GetNewArray(int a, int i, int j, int k) List list = new List(); for (int temp = 0; temp a.Length; temp+) if (temp != i & temp != j & temp != k) list.Add(atemp); int b = list.ToArray(); return b; / / 获得由最后三个数字组成的所有三位数 / / / static int GetAllThreeNumber(int list) List temp = new List(); if (list = null | list.Length != 3) return temp.ToArray(); temp.Add(100 * list0 + 10 * list1 + list2); temp.Add(100 * list0 + 10 * list2 + list1); temp.Add(100 * list1 + 10 * list0 + list2); temp.Add(100 * list1 + 10 * list2 + list0); temp.Add