C语言下期考试题库知识分享

1、Good is good, but better carries it.精益求精，善益求善。C语言下期考试题库-改错.1.程序D8.c的功能是打开文件d:te.c用于读并判断打开是否成功【此部分在计算中心已公布的题库中，未标明正确答案，同学们自己做】#includeintmain(void)FILE*fp;/*Found*/charfileName=d:te.c;/*Found*/fp=fopen(fileName,r);/*Found*/if(fp=NULL)puts(FileOpenError!);return1;putchar(fgetc(fp);fclose(fp);return0;2

2、.程序D9.c的功能是申请100个字节的内存空间，显示其首地址，然后释放申请到的内存空间#include#includeintmain(void)/*Found*/char*pch2;/*Found*/if(pch=(char*)malloc(100)=NULL)printf(mallocmemoryfail!n);return1;printf(%pn,pch);/*Found*/free(pch);return0;3.程序D10.c的功能是将字符串str2显示在屏幕上#include/*Found*/#defineSTART/*Found*/#defineNEXTintmain(void)c

3、har*str2constinti=0;for(printf(n);str2i;)STARTputchar(str2i);/*Found*/p+;NEXTreturn0;4.程序D16.c的功能是worker2的信息使用结构体存储，从键盘读入其各项信息并显示。#includeintmain(void)structWKERlongID;longintnum;charname20;charsex;/*Found*/worker2;worker2.ID=1L;/*Found*/scanf(%ld%s%c,&worker2.num,&worker2.sex);/*Found*

4、/printf(workersinfo:num=%ldname=%ssex=%cn,worker2.num,worker2.sex);return0;程序D19.c的功能是将inBuf中字符串拆分成一个个的单词。程序说明：(1)单词之间的分隔符由串divChar，程序中定义为“;?!,./”。(2)函数getStrFromBuf的功能是从Buf的开始处寻找第一个单词，将找到的单词作为一个字符串复制到Str处，divStr指明单词间的分隔符。GetStrFromBuf的返回值指向已找到单词的下一个字符。(3)函数charInStr的功能是判断字符t是否出现在串Str中。(4)主程序的功能是将in

5、Buf中的所有单词在屏幕上显示出来。#include#defineYes1#defineNo0char*getStrFromBuf(char*Buf,char*Str,char*divStr);intcharInStr(char*Str,chart);intmain(void)charinBuf100=howoldare/you?,*point,oneWord20;chardivChar=;?!,./;point=inBuf;while(*point)/*Found*/P=getStrFromBuf(point,oneWord,divChar);if(*oneWord)puts(oneWord

6、);return0;intcharInStr(char*Str,chart)for(;*Str;Str+)/*Found*/if(*Str=*t)(去掉*)/*Found*/returnYes;/*Found*/returnNo;char*getStrFromBuf(char*Buf,char*Str,char*divStr)for(;*Buf;Buf+)if(charInStr(divStr,*Buf)=No)break;for(;*Buf;Buf+)if(charInStr(divStr,*Buf)=Yes)break;/*Found*/*Str=*Buf;Str+;/*Found*/*S

7、tr=0;/*Found*/returnBuf;填空题【附带正确答案】一：#defineM10main()intsub_max();inti,aM,*ptr=a;intmax;for(i=0;i=9;i+)scanf(%d,a+i);max=sub_max(ptr,10);printf(max=%dn,max);intsub_max(int*b,inti)inttemp,j;temp=*b;for(j=1;j=i-1;j+)if(temp*(b+j)temp=*(b+j);returntemp;二、求数组中值最大的元素值及其位置main()inta34,*ptr,i,j,max,maxi,ma

8、xj;for(i=0;i3;i+)for(j=0;j4;j+)scanf(%d,&aij);ptr=a0;max_arr(ptr,&max,&maxi,12);maxj=maxi%4;maxi=maxi/4;printf(max=%d,maxi=%d,maxj=%d,max,maxi,maxj);intmax_arr(b,p1,p2,n)int*b,*p1,*p2,n;inti;*p1=b0;*p2=0;for(i=1;i*p1)*p1=bi;*p2=i;三、求二维数组中每行元素的和#defineM3#defineN4main()voidfun();floataMN;floatscore1=0

9、,score2=0,score3=0,*pa=a0;inti,j;for(i=0;iM;i+)for(j=0;jN;j+)/*二维数组的数据输入*/scanf(%f,&aij);fun(pa,&score1,&score2,&score3);printf(%.2f,%.2f,%.2fn,score1,score2,score3);voidfun(b,p1,p2,p3)floatbN,*p1,*p2,*p3;inti,j;*p1=*p2=*p3=0;for(i=0;iM;i+)for(j=0;jN;j+)if(i=0)*p1=*p1+bij;/*第0行的数据相加*/if(i=1)*p2=*p2+

10、bij;/*第1行的数据相加*/if(i=2)*p3=*p3+bij;/*第2行的数据相加*/四、输出二维数组任意行任意列元素的值#includestdio.hmain()inta34=1,3,5,7,9,11,13,15,17,21,23,56;int(*p)4,i,j;p=a;scanf(%d%d,&i,&j);printf(a%d,%d=%dn,i,j,*(*(p+i)+j);/或*(pi+j)或Pij五、有一个班，3个学生，各学4门课，计算总平均分数，以及第n个学生的成绩。mian()voidaverage(float*p,intn);voidserch(float(*p)4,int)

11、;floatscore34=65,67,70,60,80,87,90,81,90,99,100,98;average(*score,12):serch(score,2);六、动态数组的实现。/*程序功能：实现动态数组*/#include“alloc.h”#include“stdlib.h”main()int*array=NULL,num,i;printf(“Inputthenumberofelement:”);scanf(“%d”,&num);/*申请动态数组array=(int*)malloc(sizeof(int)*num);if(array=NULL)printf(“outofmemor

12、y,pressanykeytoquit”);exit(0);printf(“Input%delements:”,num);for(i=0;inum;i+)scanf(“%d”,&arrayi);printf(“%delementsare:”,num);for(i=0;inum;i+)printf(“%d,”,arrayi);printf(“b”);free(array);七、用函数调用方式，实现字符串的复制。voidstring_copy(char*str_from,char*str_to)inti=0;for(;(*(str_from+i)!=0;i+)*(str_to+i)=*(str_f

13、rom+i)*(str_to+i)=0;main()chararray_str120=”Iamateacher.”;chararray_str220;string_copy(array_str1,array_str2);printf(“array_str2=%sn”,array_str2);八、用指针变量实现将字符串a复制为字符串bmain()chara=“Iamaboy.”,b20,*p1,*p2;inti;p1=a;p2=b;for(;*p1!=0;p1+,p2+)*p2=*p1;*p2=0;printf(“stringais:%sn”,a);printf(“stringbis:”);fo

14、r(i=0;bi!=0;i+)printf(“%c”,bi);printf(“n”);九、找出十个数中的最大值main()int*max();intn,a10,*s,i;for(i=0;i10;i+)scanf(%d,a+i);s=max(a,10);printf(max=%d,index=%dn,*s,s-a);int*max(a,n)int*a,n;int*p,*t;for(p=a,t=a;p-a*t)t=p;returnt;十、用指针数组的各指针指向字符串数组、指向一维整型数组、指向二维整型数组。#includestdlib.hmain()char*ptr14=china,chengdu

15、,sichuang,chongqin;inti,*ptr23;inta3=1,2,3,b32=1,2,3,4,5,6;for(i=0;i4;i+)printf(n%s,ptr1i);printf(n);for(i=0;i3;i+)ptr2i=&ai;/*将整型一维数组a的3个元素的地址传递给指针数组ptr2的三个元素*/for(i=0;i3;i+)/*输出3个整型变量的值*/printf(%4d,*ptr2i);printf(n);for(i=0;i3;i+)ptr2i=bi;for(i=0;i3;i+)printf(%4d%4dn,*ptr2i,*(ptr2i+1);十一。用冒泡排序法对4个

16、字符串数组按字典排序。#includestdlib.h#includestring.hmain()voidsort(char*n);voidprint(char*ptr1,intn);char*ptr14,str420;inti,j,n=4;for(i=0;in;i+)gets(stri);/*输入4个字符串*/for(i=0;in;i+)ptr1i=stri;sort(ptr1,n);print(ptr1,n);voidsort(char*ptr1,intn)inti,j,temp20;for(i=0;in-1;i+)/*冒泡排序*/for(j=0;j0)strcpy(tem

17、p,ptr1j);strcpy(ptr1j,ptr1j+1);strcpy(ptr1j+1,temp);voidprint(char*ptr1,intn)inti;for(i=0;in;i+)printf(%sn,ptr1i);十二.利用malloc()函数为指针分配存储空间，实现字符串的排序#includestdlib.h“#includestring.hmain()voidsort(char*ptr1,intn);voidprint(char*ptr1,intn);char*ptr14;inti,j;for(i=0;i4;i+)ptr1i=malloc(20);/*让指针数组各指针指向动态

18、分配的20字节的存储空间*/if(ptr1i=NULL)/*内存申请失败：printf(“outofmemory,pressanykeytoquit”);exit(0);for(i=0;i4;i+)gets(ptr1i);/*输入字符串*/sort(ptr1,4);print(ptr1,4);for(i=0;i4;i+)free(ptr1i);voidsort(char*ptr2,intn)char*temp;inti,j;for(i=0;in-1;i+)for(j=0;j0)temp=ptr2j;ptr2j=ptr2j+1;ptr2j+1=temp;voidprint(char*ptr1,i

19、ntn)inti;for(i=0;in;i+)printf(%sn,ptr1i);十三、用指向指针的指针变量访问一维和二维数组。main()inta10,b34,*p1,*p2,*p3,i,j;/*p3是指向指针的指针变量*/for(i=0;i10;i+)scanf(“%d”,&ai);for(i=0;i3;i+)for(j=0;j4;j+)scanf(%d,&bij);for(p1=a;p1-a10;p1+)/*用指向指针的指针变量输出一维数组*/p3=&p1;printf(%4d,*p3);printf(n);for(i=0;i3;i+)/*用指向指针的指针变p2=bi;量输出二维数组*/

20、for(;p2-biname);scanf(%ld,&student-num);scanf(%d%d%d,&student-birthday.year,&student-birthday.month,&student-birthday.day);printf(outputname,number,year,month,dayn);printf(%20s%10ld%10d/%d/%dn,student-name,student-num,student-birthday.year,student-birthday.month,student-birthday.day);十五structdataint

21、day,month,year;structstucharname20;longnum;structdatabirthday;main()inti;structstu*p,student4=liying,1,1978,5,23,wangping,2,1979,3,14,libo,3,1980,5,6,xuyan,4,1980,4,21;p=student;printf(n1-Outputname,number,year,month,dayn);for(i=0;iname,(p+i)-num,(p+i)-birthday.year,(p+i)-birthday.month,(p+i)-birthd

22、ay.day);十六、编写一个creat()函数，按照规定的节点结构体，创建一个单链表（链表中的节点个数不限，以输入学号0作结束）。#include#include#defineLENsizeof(structstudent)#defineNULL0structstudentlongnum；intscore；structstudent*next；;intn;structstudent*creat()structstudent*head=NULL,*tail,*newp；n=0;newp=(structstudent*)malloc(LEN);printf(inputNumberandScore

23、n);scanf(“%ld,%d”,&newp-num,&newp-score);tail=newp;while(newp-num!=0)n+;if(n=1)head=newp；elsetail-next=newp;tail=newp;newp=(structstudent*)malloc(LEN);printf(inputNumberandScoren);scanf(“%ld,%d”,&newp-num,&newp-score);tail-next=NULL;return(head);main()structstudent*head;printf(Pleasecreatthelistn);h

24、ead=creat();十七、输出链表的某节点数据typedefstructstudentcharname10;intscore;structstudent*next;NODE;voidprint_list(NODE*head)NODE*p=head;while(p!=NULL)printf(n%s%d,p-name,p-score);p=p-next;十八。该子函数的功能是统计链表节点的个数typedefstructstudentcharname10;intscore;structstudent*next;NODE;intcount_list(NODE*head)NODE*p=head;in

25、tcount=0;while(p!=NULL)count+;p=p-next;return(count);十九，该子函数的功能是删除链表中的某节点structnodeintnum;charstr20;structnode*next;structnode*delet(structnode*head,char*pstr)/*以head为头指针，删除pstr所在节点*/structnode*temp,*p;temp=head;if(head=NULL)printf(nListisnull!n);elsetemp=head;while(strcmp(temp-str,pstr)!=0&temp-nex

26、t!=NULL)p=temp;temp=temp-next;/*跟踪链表的节点，即指针后移*/if(strcmp(temp-str,pstr)=0)if(temp=head)printf(deletestring:%sn,temp-str);head=head-next;free(temp);else/*表中节点或最后节点*/p-next=temp-next;printf(deletestring:%sn,temp-str);free(temp);elseprintf(nnofindstring!n);/*没找到要删除的字符串*/return(head);/*返回表头指针*/二十、以学号为顺序

27、建立链表，插入某节点structnode*insert(structnode*head,char*pstr,intn)/*插入学号为n、姓名为pstr的节点*/structnode*p1,*p2,*p3;p1=(structnode*)malloc(sizeof(structnode);strcpy(p1-str,pstr);/*写入节点的姓名字串*/p1-num=n;p2=head;if(head=NULL)head=p1;p1-next=NULL;/*新节点插入表头*/else/*非空表*/while(np2-num&p2-next!=NULL)/*输入的学号小于节点的学号，并且未到表尾*

28、/p3=p2;p2=p2-next;/*跟踪链表增长*/if(nnum)/*找到插入位置*/if(head=p2)head=p1;p1-next=p2;/*插入位置在表头*/elsep3-next=p1;p1-next=p2;/*插入位置在表中*/elsep2-next=p1;p1-next=NULL;/*插入位置在表尾*/return(head);/*返回链表的头指针*/二十二、打开d盘根下的myfile.c文件,验证文件能否正确打开.includevoidmain()FILE*fa;if(fa=fopen(“d:myfile.c”，“r”)=NULL)printf(“nCannotopen

29、thefile!”);exit(0);elseprintf(“nOpen!”);fclose(fa);二十三【编程题】、将键盘上输入的一个字符串（以#作为结束字符），存储到一个文件中。#includestdio.h”main()charch,filename10;printf(“Enterthefilename:”);scanf(%s,filename);if(fp=fopen(filename,“w”)=NULL)printf(cannotopenthisfilen);exit(0);ch=getchar();/*输入字符并存储到文件中*/while(ch!=#)fputc(ch,fp);c

30、h=getchar();fclose(fp);二十四、【编程题】将一个磁盘文件的信息复制到另一个文件中并显示在屏幕上。#includestdio.h“main()FILE*in,*out;charch,infile20,outfile20;printf(Entertheinfilename:);scanf(%s,infile);printf(Entertheoutfilename:);scanf(%s,outfile);if(in=fopen(infile,r)=NULL)printf(cannotopeninfilen);exit(0);if(out=fopen(outfile,w)=NUL

31、L)printf(cannotopenoutfilen);exit(0);while(!feof(in)chfgetc(in)；fputc(ch,out);putchar（ch）；fclose(in);fclose(out);二十五、编写一个程序,实现DOS中的type命令的功能。命令格式如下：c:typed:file1.cpp#include#includevoidmain(intargc,char*argv)FILE*fp;charc;if(argc2)printf(“nNOfilename”);exit(0);if(fp=fopen(argv1,“r”)=NULL)printf(“nFi

32、lenotexist!”);exit(0);while(c=fgetc(fp)!=EOF)putchar(c);fclose(fp);二十六、从键盘读入字符串存入文件file1.txt，再将文本文件file1.txt中的内容全部读出并显示在屏幕上。#includemain()FILE*fp;charstring81;if(fp=fopen(file1.txt,w)=NULL)printf(canntopenfile);exit(0);while(strlen(gets(string)0)fputs(string,fp);fputs(n,fp);fclose(fp);if(fp=fopen(fi

33、le1.txt,r)=NULL)printf(canntopenfile);exit(0);while(fgets(string,81,fp)!=NULL)fputs(string,stdout);fclose(fp);二十七、【编程题】把文件1的内容追加到文件2#include#include#defineBUFSIZE256voidmain(intargc,char*argv)inti;charbuffBUFSIZE;FILE*fp1,*fp2;if(argc=1)printf(Rsage:fcatfilenamelinke_fnamelink_fname.);printf(n);exit

34、(0);if(fp1=fopen(argv1,a)=NULL)printf(file%scannotopened.n,argv1);exit(1);for(i=2;iargc;i+)if(fp2=fopen(argvi,r)=NULL)printf(file%scannotopened.n);exit(1);while(fgets(buff,BUFSIZE,fp2)!=NULL)fputs(buff,fp1);fclose(fp2);fclose(fp1);二十八。从键盘输入4个学生的有关数据，然后把它们转存到一个写入磁盘文件student.dat中。#includestdio.h”#defi

35、neSIZE4typedefstructintnum;charname10;stutype;stutypestudentSIZE;voidsave()FILE*fp;inti;if(fp=fopen(“student.dat,wb)=NULL)printf(“Cannotopenthisfilen);return;for(i=0;iSIZE;i+)if(fwrite(&studenti,sizeof(stutype),1,fp)!=1)printf(filewriteerrorn);fclose(fp);main()inti;printf(Enter%dstudentsNo.andname:n

36、“,SIZE);for(i=0;iSIZE;i+)scanf(%d%s,&studenti.num,);save();二十九、【编程题】从文件中读入数据，然后在屏幕上输出。#includestdio.h”#defineSIZE4typedefstructintnum;charname10;stutype;stutypestudentSIZE;main()inti;FILE*fp;fp=fopen(“student.dat,rb);printf(%dstudentsNo.andname:n,SIZE);for(i=0;iSIZE;i+)fread(&studenti,s

37、izeof(stutype),1,fp);printf(%d%10sn,studenti.num,);fclose(fp);三十、按指定的格式,将学生信息写入到文件stud.dat中#includestructstudentcharname10;intnum;intage;charaddr15;boy2,*pp;voidmain()FILE*fp;charch,filename20;inti;gets(filename);pp=boy;if(fp=fopen(filename,w)=NULL)printf(Cannotopenfile!);getch();exit(1

38、);printf(ninputdatan);for(i=0;iname,&pp-num,&pp-age,pp-addr);pp=boy;for(i=0;iname,pp-num,pp-age,pp-addr);fclose(fp);从文件stud.dat中,按指定的格式,将学生信息读出并显示到屏幕上.#includestructstudentcharname10;intnum;intage;charaddr15;voidmain()FILE*fp;charch,filename20;inti;structstudentboy2,*pp=boy;printf(nfilename:);gets(f

39、ilename);fp=fopen(filename,r);for(i=0;iname,&pp-num,&pp-age,pp-addr);printf(nnnametnumberagetaddrn);pp=boy;for(i=0;iname,pp-num,pp-age,pp-addr);fclose(fp);三十二、【编程题】有一个文本文件，第一次将它的内容显示在屏幕上，第二次把它复制到另一个文件中#includestdio.hmain()FILE*fp1,*fp2;fp1=fopen(file1.c,r);fp2=fopen(file12.c,w);while(!feof(fp1)putch

40、ar(fgetc(fp1);rewind(fp1);while(!feof(fp1)fputc(fgetc(fp1),fp2);fclose(fp1);fclose(fp2);三十三。【编程题】在一个文件上存放了4个学生的数据，要求将第一个和第三个学生的信息在屏幕上显示出来。#includestdio.h#defineSIZE4typedefstructcharname10;intnum;intage;charaddr15;stutype;stutypestudentSIZE;voidmain()FILE*fp;inti;if(fp=fopen(student.dat,rb)=NULL)pri

41、ntf(cannotopenthisfilen);exit(0);for(i=0;iSIZE;i+=2)fseek(fp,i*sizeof(stutype),0);fread(&studenti,sizeof(stutype),1,fp);printf(%d%6sn,studenti.num,);fclose(fp);三十四，求文件长度#includestdio.hmain()FILE*fp;charfilename80;longlength;gets(filename);fp=fopen(filename,rb);if(fp=NULL)printf(filenotf

42、ound!n);elsefseek(fp,0L,SEEK_END);length=ftell(fp);printf(LengthofFileis%1dbytesn,length);fclose(fp);三十五题*填空!main()char*s=man,woman,girl,boy,sister;char*q;intk;for(k=0;k5;k+)q=s+k;/*这里填写什么语句*/printf(%sn,*q);三十六题、输出年龄最大的人#defineN4#includestdio.hstaticstructmancharname20;intage;personN=li,18,wang,19,z

43、hang,20,sun,22;main()structman*q,*p;inti,m=0;p=person;for(i=0;iN;i+)if(mage)q=p+;m=q-age;printf(%s,%d,(*q).name,(*q).age);题目取一个整数a从右端开始的47位。程序分析：【12章的位运算非重点但会涉及考查】(1)先使a右移4位。(2)设置一个低4位全为1,其余全为0的数。可用(04;c=(0n2)swap(pointer1,pointer2);if(n1n3)swap(pointer1,pointer3);if(n2n3)swap(pointer2,pointer3);pri

44、ntf(thesortednumbersare:%d,%d,%dn,n1,n2,n3);swap(p1,p2)int*p1,*p2;intp;p=*p1;*p1=*p2;*p2=p;题目：输入数组，最大的与第一个元素交换，最小的与最后一个元素交换，输出数组。main()intnumber10;input(number);max_min(number);output(number);input(number)intnumber10;inti;for(i=0;i9;i+)scanf(%d,&numberi);scanf(%d,&number9);max_min(array)intarray10;i

45、nt*max,*min,k,l;int*p,*arr_end;arr_end=array+10;max=min=array;for(p=array+1;p*max)max=p;elseif(*p*min)min=p;k=*max;l=*min;*p=array0;array0=l;l=*p;*p=array9;array9=k;k=*p;return;output(array)intarray10;int*p;for(p=array;parray+9;p+)printf(%d,*p);printf(%dn,array9);题目：有n个整数，使其前面各数顺序向后移m个位置，最后m个数变成最前面的

46、m个数1.程序分析：2.程序源代码：main()intnumber20,n,m,i;printf(thetotalnumbersis:);scanf(%d,&n);printf(backm:);scanf(%d,&m);for(i=0;in-1;i+)scanf(%d,&numberi);scanf(%d,&numbern-1);move(number,n,m);for(i=0;iarray;p-)*p=*(p-1);*array=array_end;m-;if(m0)move(array,n,m);题目：有n个人围成一圈，顺序排号。从第一个人开始报数（从1到3报数），凡报到3的人退出圈子，问

47、最后留下的是原来第几号的那位。#definenmax50main()inti,k,m,n,numnmax,*p;printf(pleaseinputthetotalofnumbers:);scanf(%d,&n);p=num;for(i=0;in;i+)*(p+i)=i+1;i=0;k=0;m=0;while(mn);for(i=0;idata=num;ptr-next=(link)malloc(sizeof(node);if(i=4)ptr-next=NULL;elseptr=ptr-next;ptr=head;while(ptr!=NULL)printf(Thevalueis=%dn,pt

48、r-data);ptr=ptr-next;题目：反向输出一个链表。#includestdlib.h#includestdio.hstructlistintdata;structlist*next;typedefstructlistnode;typedefnode*link;voidmain()linkptr,head,tail;intnum,i;tail=(link)malloc(sizeof(node);tail-next=NULL;ptr=tail;printf(npleaseinput5data=n);for(i=0;idata=num;head=(link)malloc(sizeof(

49、node);head-next=ptr;ptr=head;ptr=ptr-next;while(ptr!=NULL)printf(Thevalueis=%dn,ptr-data);ptr=ptr-next;【程序74】题目：连接两个链表。#includestdlib.h#includestdio.hstructlistintdata;structlist*next;typedefstructlistnode;typedefnode*link;linkdelete_node(linkpointer,linktmp)if(tmp=NULL)/*deletefirstnode*/returnpoin

50、ter-next;elseif(tmp-next-next=NULL)/*deletelastnode*/tmp-next=NULL;else/*deletetheothernode*/tmp-next=tmp-next-next;returnpointer;voidselection_sort(linkpointer,intnum)linktmp,btmp;inti,min;for(i=0;idata;btmp=NULL;while(tmp-next)if(mintmp-next-data)min=tmp-next-data;btmp=tmp;tmp=tmp-next;printf(40:%

51、dn,min);pointer=delete_node(pointer,btmp);linkcreate_list(intarray,intnum)linktmp1,tmp2,pointer;inti;pointer=(link)malloc(sizeof(node);pointer-data=array0;tmp1=pointer;for(i=1;inext=NULL;tmp2-data=arrayi;tmp1-next=tmp2;tmp1=tmp1-next;returnpointer;linkconcatenate(linkpointer1,linkpointer2)linktmp;tm

52、p=pointer1;while(tmp-next)tmp=tmp-next;tmp-next=pointer2;returnpointer1;voidmain(void)intarr1=3,12,8,9,11;linkptr;ptr=create_list(arr1,5);selection_sort(ptr,5);题目：编写一个函数，输入n为偶数时，调用函数求1/2+?+.+1/n,当输入n为奇数时，调用函数1/1+1/3+.+1/n(利用指针函数)main()#includestdio.hmain()floatpeven(),podd(),dcall();floatsum;intn;wh

53、ile(1)scanf(%d,&n);if(n1)break;if(n%2=0)printf(Even=);sum=dcall(peven,n);elseprintf(Odd=);sum=dcall(podd,n);printf(%f,sum);floatpeven(intn)floats;inti;s=1;for(i=2;i=n;i+=2)s+=1/(float)i;return(s);floatpodd(n)intn;floats;inti;s=0;for(i=1;i0)swap(str1,str2);if(strcmp(str1,str3)0)swap(str1,str3);if(str

54、cmp(str2,str3)0)swap(str2,str3);printf(afterbeingsortedn);printf(%sn%sn%sn,str1,str2,str3);charswap(p1,p2)char*p1,*p2;char*p20;strcpy(p,p1);strcpy(p1,p2);strcpy(p2,p);题目：八进制转换为十进制main()char*p,s6;intn;p=s;gets(p);n=0;while(*(p)!=0)n=n*8+*p-0;p+;printf(%d,n);题目：计算字符串中子串出现的次数#includestring.h#includestd

55、io.hmain()charstr120,str220,*p1,*p2;intsum=0;printf(pleaseinputtwostringsn);scanf(%s%s,str1,str2);p1=str1;p2=str2;while(*p1!=0)if(*p1=*p2)while(*p1=*p2&*p2!=0)p1+;p2+;elsep1+;if(*p2=0)sum+;p2=str2;printf(%d,sum);getch();题目：从键盘输入一些字符，逐个把它们送到磁盘上去，直到输入一个#为止。#includestdio.hmain()FILE*fp;charch,filename1

56、0;scanf(%s,filename);if(fp=fopen(filename,w)=NULL)printf(cannotopenfilen);exit(0);ch=getchar();ch=getchar();while(ch!=#)fputc(ch,fp);putchar(ch);ch=getchar();fclose(fp);题目：从键盘输入一个字符串，将小写字母全部转换成大写字母，然后输出到一个磁盘文件“test”中保存。输入的字符串以！结束。#includestdio.hmain()FILE*fp;charstr100,filename10;inti=0;if(fp=fopen(

57、test,w)=NULL)printf(cannotopenthefilen);exit(0);printf(pleaseinputastring:n);gets(str);while(str!=!)if(str=a&str=z)str=str-32;fputc(str,fp);i+;fclose(fp);fp=fopen(test,r);fgets(str,strlen(str)+1,fp);printf(%sn,str);fclose(fp);题目:有两个磁盘文件A和B,各存放一行字母,要求把这两个文件中的信息合并(按字母顺序排列),输出到一个新文件C中.#includestdio.hma

58、in()FILE*fp;inti,j,n,ni;charc160,t,ch;if(fp=fopen(A,r)=NULL)printf(fileAcannotbeopenedn);exit(0);printf(nAcontentsare:n);for(i=0;(ch=fgetc(fp)!=EOF;i+)ci=ch;putchar(ci);fclose(fp);ni=i;if(fp=fopen(B,r)=NULL)printf(fileBcannotbeopenedn);exit(0);printf(nBcontentsare:n);for(i=0;(ch=fgetc(fp)!=EOF;i+)ci

59、=ch;putchar(ci);fclose(fp);n=i;for(i=0;in;i+)for(j=i+1;jcj)t=ci;ci=cj;cj=t;printf(nCfileis:n);fp=fopen(C,w);for(i=0;in;i+)putc(ci,fp);putchar(ci);fclose(fp);题目:有五个学生,每个学生有3门课的成绩,从键盘输入以上数据(包括学生号,姓名,三门课成绩),计算出平均成绩,原有的数据和计算出的平均分数存放在磁盘文件stud中.#includestdio.hstructstudentcharnum6;charname8;intscore3;floa

60、tavr;stu5;main()inti,j,sum;FILE*fp;for(i=0;i5;i+)printf(npleaseinputNo.%dscore:n,i);printf(stuNo:);scanf(%s,stui.num);printf(name:);scanf(%s,);sum=0;for(j=0;j3;j+)printf(score%d.,j+1);scanf(%d,&stui.scorej);sum+=stui.scorej;stui.avr=sum/3.0;fp=fopen(stud,w);for(i=0;i5;i+)if(fwrite(&stui,siz