电工与电子技术课后习题答案习题

-word.zl---UCC=12V、RC=3KΩ、RB=240KΩ、ui=0)C1、C2RBC1+RC+TC2RLuORSuieS(a)放大电路321(b)输出特性TUIBIC(1)直流通路3QQ21(2)CE--CE++uieS+T(a)uO+TuOuieST(a)TuiuieS-T(a)uOTuiuieS(b)word.zl------U-URRRRCC+CCCC++TTRBC2RLRRRLRREuOuiuOuiuiRLRLuO(a)(b)(c)&AuriIEri=RB//rbe»rbe=0.82KWro=RC=3KW=-bRc//RL=-73.2rbecIbbrbe&UiriEro&UO=-bRc//RL=-97.6rbe&LL----RE2=EE+C+CC1eS+uiuiβ+CEuOUBβUβICE&CEAuri、输出&roAus。CEIE--=-bRc//RL=-9.2rbe+(1+b)RE1ri=RB2//RB1//[rbe+(1+b)RE1]=5KWro=RC=3.3KW&riAus=-Aus=-8.4RS+ricbRrbeRRCRE&ESR&Ui&IbRrirori(1)接电容CE时BUiUi&ESri&IbRri&I&IcbrbeRRRRERLro(2)断开电容CE时&UO题9-6图=-bRc//RL=-1.3rbe+(1+b)(RE1+RE2)ri=RB2//RB1//[rbe+(1+b)(RE1+RE2]=6.9KWro=RC=3.3KW&riAus=-Aus=-12RS+ri.L-432102.21.631.6Q6-word.zl----①RL=3KΩ②RL=6KΩUCC=12V、RB1=100KΩ、RB2=30KΩ、&eSC1+uiβC2&&ESuO&UiriBIc&IbIbrber/ir/iro&UO----AβRE//RL=0.96rbe+(1+β)RE//RLri=RB2//RB1//[rbe+(1+β)RE//RL]=19.3KΩ4K+++1.5KKβKKβ4KuiuOUIIB1IE1IB2UβUIE2&U&UO-&Ic2&&Ib2&Ib1rbe2&rbe1riri2b&Ic1UO1&UiroIE1rbe2=IE2③ri=RB12//RB11//rbe1»rbe1=1.56KW④ri2=RB2//[rbe2+(1+b2)RE2//RL]=37KWRE2//(RC1//RB2+rbe2)Rc1//ri2)=-115.7rbe1rbe2+)RE2//RLAu=Au1Au2=-113.4=bC1+bC2++bC37.5KuiuOC4+RIB1IE1RURRCRRIC1IE2----IE1rbe2=IE2&Ic1&Ib1&I&Ib1&Ib2rbe1Rrbe1R&UoRR&Uo1UiRR&Uo1UiRRRRriririri2③ri2βui-ro=RC=10KΩ④Au1rbe2)RE21Au=Au1Au2=一17.4esC1+uiC2C2β+C4+βC3βuOuOC(a)C2βL