2025年GRE数学QuantitativeComparison专项训练卷

2025年GRE数学QuantitativeComparison专项训练卷考试时间：______分钟总分：______分姓名：______Section1:QuantitativeReasoning*Directions:Foreachquantitativecomparisonquestion,compareQuantityAandQuantityB.Selectoneofthefollowingfouranswerchoicesandfillinthecorrespondingcircleonyouranswersheet.(A)ThequantityinColumnAisgreater.(B)ThequantityinColumnBisgreater.(C)Thetwoquantitiesareequal.(D)Therelationshipcannotbedeterminedfromtheinformationgiven.1.QuantityA:Thevalueof(3^7)/(3^3)QuantityB:3^42.QuantityA:Theperimeterofarectanglewithwidth5andlength12.QuantityB:Theperimeterofasquarewithsidelength9.3.QuantityA:25%of80QuantityB:0.75*804.QuantityA:Thesumofthefirst50positiveintegers.QuantityB:50*255.QuantityA:(15^2)-(14^2)QuantityB:29*26.QuantityA:Theareaofatrianglewithbase10andheight6.QuantityB:Theareaofatrianglewithbase8andheight9.7.QuantityA:x^2+6x+9QuantityB:(x+3)^28.QuantityA:Thevalueofywheny=|-5|QuantityB:Thevalueofywheny=-|5|9.QuantityA:Thevalueof1/(0.5)QuantityB:Thevalueof2/(0.25)10.QuantityA:Theaverage(arithmeticmean)of4,7,and10.QuantityB:Theaverage(arithmeticmean)of3,8,and9.11.QuantityA:Thenumberofprimenumbersbetween1and10,inclusive.QuantityB:Thenumberofevenintegersbetween1and10,inclusive.12.QuantityA:Theproductofthefirst5positiveoddintegers.QuantityB:Theproductofthefirst5positiveevenintegers.13.QuantityA:Thevalueof(1/2)^(-3)QuantityB:Thevalueof2^314.QuantityA:Thelengthofanedgeofacubewithvolume27cubicunits.QuantityB:Thelengthofanedgeofacubewithsurfacearea54squareunits.15.QuantityA:Theintegerx,where5<x<8QuantityB:Theintegery,where7<y<1016.QuantityA:Thedifferencebetween50%of200and25%of300.QuantityB:Thedifferencebetween75%of150and50%of250.17.QuantityA:Thevalueofkwhen2k+7=11QuantityB:Thevalueofkwhen3k-5=1018.QuantityA:Theareaofacirclewithradius4units.QuantityB:Theareaofacirclewithdiameter10units.19.QuantityA:Thenumberofdegreesinananglesupplementarytoa35-degreeangle.QuantityB:Thenumberofdegreesinananglecomplementarytoa55-degreeangle.20.QuantityA:Thevalueof(10^3)-(9^3)QuantityB:19*9121.QuantityA:Thevalueof1/(1+1/3)QuantityB:Thevalueof3/(3+1)22.QuantityA:Thesumofthedigitsofthenumber543.QuantityB:Thesumofthedigitsofthenumber654.23.QuantityA:Thevalueof(1/3)^0QuantityB:Thevalueof0^324.QuantityA:Thevalueof|-8|QuantityB:-8^225.QuantityA:Theaverage(arithmeticmean)of8consecutiveintegersstartingwith7.QuantityB:Theaverage(arithmeticmean)of8consecutiveintegersstartingwith6.---试卷答案1.(B)*解析：QuantityA:(3^7)/(3^3)=3^(7-3)=3^4.QuantityB:3^4.Thetwoquantitiesareequal.2.(B)*解析：QuantityA:Perimeter=2*(5+12)=34.QuantityB:Perimeter=4*9=36.QuantityBisgreater.3.(C)*解析：QuantityA:25%of80=(1/4)*80=20.QuantityB:0.75*80=(3/4)*80=60.Thetwoquantitiesareequal.4.(B)*解析：QuantityA:Sum=n(n+1)/2withn=50=50*51/2=25*51=1275.QuantityB:50*25=1250.QuantityAisgreater.5.(A)*解析：QuantityA:(15^2)-(14^2)=(15-14)(15+14)=1*29=29.QuantityB:29*2=58.QuantityAisgreater.6.(A)*解析：QuantityA:Area=(1/2)*base*height=(1/2)*10*6=30.QuantityB:Area=(1/2)*8*9=36.QuantityBisgreater.7.(C)*解析:QuantityA:x^2+6x+9=(x+3)^2.QuantityB:(x+3)^2.Thetwoquantitiesareequal.8.(A)*解析:QuantityA:y=|-5|=5.QuantityB:y=-|5|=-5.QuantityAisgreater.9.(C)*解析:QuantityA:1/(0.5)=1/(1/2)=2.QuantityB:2/(0.25)=2/(1/4)=8.Thetwoquantitiesareequal.10.(A)*解析:QuantityA:Average=(4+7+10)/3=21/3=7.QuantityB:Average=(3+8+9)/3=20/3≈6.67.QuantityAisgreater.11.(B)*解析:QuantityA:Primenumbersbetween1and10:2,3,5,7.Count=4.QuantityB:Evenintegersbetween1and10:2,4,6,8,10.Count=5.QuantityBisgreater.12.(A)*解析:QuantityA:Product=1*3*5*7*9=945.QuantityB:Product=2*4*6*8*10=3840.QuantityBisgreater.13.(B)*解析:QuantityA:(1/2)^(-3)=2^3=8.QuantityB:2^3=8.Thetwoquantitiesareequal.14.(D)*解析:QuantityA:Edgelength=³√27=3.QuantityB:Letedgelength=s.SurfaceArea=6s^2=54=>s^2=9=>s=3.Thetwoquantitiesareequal.15.(D)*解析:QuantityA:Integerx,where5<x<8:6,7.QuantityB:Integery,where7<y<10:8,9.Therelationshipcannotbedeterminedfromtheinformationgiven(bothhavepossiblevalueslessthantheother).16.(B)*解析:QuantityA:(50/100)*200-(25/100)*300=100-75=25.QuantityB:(75/100)*150-(50/100)*250=112.5-125=-12.5.QuantityAisgreater.17.(C)*解析:From2k+7=11,weget2k=4,sok=2.From3k-5=10,weget3k=15,sok=5.Thetwoquantitiesareequal.18.(D)*解析:QuantityA:Area=π*4^2=16π.QuantityB:Radius=Diameter/2=10/2=5.Area=π*5^2=25π.QuantityBisgreater.19.(C)*解析:QuantityA:Supplementaryangle=180-35=145degrees.QuantityB:Complementaryangle=90-55=35degrees.Thetwoquantitiesareequal.20.(A)*解析:QuantityA:(10^3)-(9^3)=(10-9)(10^2+10*9+9^2)=1*(100+90+81)=271.QuantityB:19*91=1729.QuantityAisgreater.