现代数值计算方法习题解答肖筱南_第1页
现代数值计算方法习题解答肖筱南_第2页
现代数值计算方法习题解答肖筱南_第3页
现代数值计算方法习题解答肖筱南_第4页
现代数值计算方法习题解答肖筱南_第5页
已阅读5页,还剩2页未读 继续免费阅读

下载本文档

版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领

文档简介

1、? 1 ? ? ? ? ? ? ? ? ? ?E? r E? ? ?E? r E? ? ?E? r E? ? ? 7 22 ? ? ? ? ? ?E? r E? 14. 3 E ? 14. 3 0013. 0 ? ? 101 ? ? ? 1 ? ?)( * xEr? )1( 10 12 1 = n ? =?n? ?)()( 1 )()( 1 )( * 1 1 * 1 1 * xxx n xEx n xE nn n = ? ?)( 11)()(1)( )( * * * * * 1 1 * * * * xE nx xx n x xxx n x xE xE r n n n n n r = = = ?

2、 ?=20? ?=)( * xE? * xx ?47 . 4 20 ? ?= * x? ?20 ? ? ? 1 ? ?)( * xEr? )1( 10 42 1 = n ? =?= * x? ?x? 2 xy =?x? * x? ? ? ? ? * y ?y? ? 2 ?)(20)(20)(2)( * xExxxxxyE= = ? ?)( * xE? ?)()( *1 xxnxxE nn ? ?nxnE x xx n x xE xE r n n n r 01. 0)( )( )( * = =? ? ? ? ? ? ? ? ? ?)()()( * tgtEttgtSSSE=? ? t tE gt

3、 ttgt S SS SEr )(2 2/ )( )( 2 * = =? ? ? ? ? ? ?2 0= x?41. 1 * 0= x? * 00 xx ? =?= 2 10 2 1 ? ? ? * 11 xx ?110110 * 00 +xx? * 00 xx ? =10? ? * 22 xx ?110110 * 11 +xx? * 11 xx ? = 2 10? ? * 1010 xx? 0? 22 23 = 2 0? 301 022 123 = 4 0? ? A? ? ?A = L LT? ? 3 11= l 3 32 21= l 3 6 22= l 3 3 31= l 3 6 32 =

4、l 2 33= l ? L ? 2 3 6 3 3 0 3 6 3 32 003 ? ? ? LY = b ? ? Y = ? 3 35 ? 3 6 ?2?T? ? ? LTX = Y . ? X =?T? ? ?2? ? 5 ? 11 a? 3 0? 22 23 = 2 0? 1203 022 323 = 6 0? ? A? ?A = L LT? ? 3 11= l 3 32 21= l 3 6 22= l 3 31= l 6 32 =l 3 33= l ? L ? 363 0 3 6 3 32 003 ? ? ? ? LY = b ? ? Y = ? 3 35 ? 6 6 ? 3 3 ?

5、T ? ? ? LTX = Y . ? X = ?1? 2 1 ? 3 1?T ? ? ?1=i ? 2 111 = ad ? ?2=i?1 21 =t? 2 1 21 =l? 2 5 2 =d ? ?3=i?1 31= t? 2 7 32= t? 2 1 31= l? 5 7 32 =l? 5 27 3= d ? ? A ? = 5 27 5 7 2 1 0 2 5 2 1 002 A ? LY = b? ? Y = ?4?7? 5 69 ?T ? ? DLTX = Y? ? X = ? 9 10? 9 7 ? 9 23?T ? ? 6 5? ?1? A = LU = 1 01 000 00

6、 0 0 0 0 0 0 10 01 001 5 4 3 2 l l l l 5 4 3 2 1 0 6 000 000 0 0 0 6 0 0 00 60 06 u u u u u ? 5 1= u ? 5 1 2= l ? 19 5 2= u ? 19 5 3= l ? 19 65 3= u ? 65 19 4= l ? 65 211 4= u ? 211 65 5= l ? 211 665 5= u ? ? LY = d? Y = ?1? 5 1 ?19 1 ? 65 1 ? 211 212 ?T ? ? UX = Y? ? X = ? 665 1509? 665 1145? 665 7

7、03? 665 395 ?665 212 ?T ? ?2? A = LU = 10 01 001 3 2 l l 3 2 1 00 10 01 u u u ?5 1= u ? 5 1 2= l? 5 24 2= u ? 24 5 3= l ? 24 115 3= u ? ? LY = d ? ? Y = ?17? 5 53? 24 115?T? ? UX = Y ? ? X = ?T ? ? ? ? ? ? ? 7 10 7 2 7 1 )( 3 )( 2 )1( 1 += +kkk xxx? 1 4 1 4 1 )( 3 )( 1 )1( 2 += +kkk xxx? 3 2 9 2 9 2

8、 )( 2 )( 1 )1( 3 += +kkk xxx? ? 7 10 7 2 7 1 )( 3 )( 2 )1( 1 += +kkk xxx? 1 4 1 4 1 )( 3 )1( 1 )1( 2 += +kkk xxx? 3 2 9 2 9 2 )1( 2 )1( 1 )1( 3 += +kkk xxx? ? ? 7 5 4 5 1 5 2 )( 3 )( 2 )1( 1 += +kkk xxx? 5 2 5 3 5 1 )( 3 )( 1 )1( 2 += +kkk xxx? 5 11 5 1 5 2 )( 2 )( 1 )1( 3 += +kkk xxx? ? 5 4 5 1 5 2

9、 )( 3 )( 2 )1( 1 += +kkk xxx? 5 2 5 3 5 1 )( 3 )1( 1 )1( 2 += +kkk xxx? 5 11 5 1 5 2 )1( 2 )1( 1 )1( 3 += +kkk xxx? ? ? ? ? 5 12 5 1 5 2 )( 3 )( 2 )1( 1 = +kkk xxx? 5 2 1 4 1 )( 3 )( 1 )1( 2 += +kkk xxx? 10 3 10 3 5 1 )( 2 )( 1 )1( 3 += +kkk xxx? ? )0( x = ?3?1?1?T? ? ? )18( x = ?3.999?2.999?1.999?T

10、 . ? ? 5 12 5 1 5 2 )( 3 )( 2 )1( 1 = +kkk xxx? 5 2 1 4 1 )( 3 )1( 1 )1( 2 += +kkk xxx? 10 3 10 3 5 1 )1( 2 )1( 1 )1( 3 += +kkk xxx? ? )0( x = ?T? ? ? )8( x ?T? ? ? ? ? 8 ? =+= 0 3 2 3 1 001 100 )( 1 ULDBJ? 3 2 3 1 01 10 = J BI? ?1)(= J B? ? ? =+= 100 100 100 )( 1U LDM? 100 10 10 = MI? ?0 21 =?1 3=

11、?1)(=M? ? ? =+= 0 2 1 2 1 101 2 1 2 1 0 )( 1 ULDBJ? 2 1 2 1 11 2 1 2 1 = J BI? ?0 1= ?i 2 5 2= ?i 2 5 3 =?1)(= J B? ? ? ? =+= 4 3 4 1 0 2 1 2 1 0 2 1 2 1 0 )( 1U LDM? 4 3 4 1 0 2 1 2 1 0 2 1 2 1 = MI? ? 2 1 21 =?0 3= ?1)(M? ? a 0 ? 1 1 1 aa aa aa = (1 ? a)2(1 ?2a) 0? A ? ? 9 ? BJ ? 0 0 0 aa aa aa ?

12、|BJI | = aa aa aa = )2()(23 2233 aaaa+=+ ? |2|)(aBJ=? ?-0.5 a 0.5 ? 12? A? ? 1 A? ? F A?09 . 0 01 . 0 25 . 0 36 . 0 +? ATA = 3 . 05 . 0 1 . 06 . 0 3 . 01 . 0 5 . 06 . 0 = 34 . 0 33 . 0 33 . 0 37 . 0 |AAI T | = 34 . 0 33 . 0 33 . 0 37 . 0 = 2 ? 0.71 ? 0.0169 ? 0 ? max (ATA) = 0.685? 2 A? 685 . 0 = 0.

13、83? 13?(1)? = = = xnxxxxxx n i i n i i n i ii ni 11 11 1 1 1 maxmax ? xnxx 1 (2)? )()()()( 21max 2 2 AAAAAAAAA T n TTT +=LL 2 11 2 1 2 1 2 2 1 2 1 F n j n i ij n i in n i i n i i Aaaaa=+= = LL 2 21max 2 2 1 )()()( 1 )( F T n TTT A n AAAAAA n AAA=+=LL ? FF AAA n 2 1 ? 10 ? ? ? ? ? ? ?13)( 4 +=xxxf?0.

14、3,0.4?034)( 3 f?0)4 . 0(f?0.3,0.4? ? 1 2 +k? =? ? ?35 . 0 0= x? ? k?0)( 1 xf?35. 0 ,325. 0? ? k?0)( 3 xf?35. 0 ,3375. 0? ? k?0)( 4 += xxf?)(xf? ? ?0)2(f?0) 1 (f? ? ? 1 2 12 + k =? ? ? ? ?4/? 4 sincos 1 kk k xx x + = + ? ?)4(log2 1kk xx= + ? ?5 . 1 0= x? ?x?+= 32 1)(xx?)( x? =?L ? ? 3 2 1 1 kk xx+= +

15、 ? ?x?+= 2 /11)(xx?)( x? =?L ? ?1 1 = +kk xx? ?x?=1)( 3 xx?1 3 1 = +kk xx? ? ?5 . 1 0= x? ? 1 x? 2 x? 3 x ? 4 x? 5 x? 6 x ? ? 56 xx ? 3 10 2 1 ? ?* x? 6 x? ?2 . 0 5 += xx?)(x? 5 1 2 . 0+= +kk xx? ? 5 xy =?2 . 0+= xy? ?x?+= 5 2 . 0)(xx?)( x? =?L ? ? 3 2 1 1 kk xx+= + ? ?5 . 0 0= x? 1 x? 2 x? 3 x? 4 x

16、? 5 x? 6 x? 7 x? 8 x ? 9 x ? ? 89 xx ? 3 10 2 1 ? ?* x? 9 x? ?x?=10/ )2()( x ex?)( x? =?L ? ?10/ )2( 1 kx k ex= + ? ?5 . 0 0= x? ? 12 1 x? 2 x? 3 x? 4 x? 5 x? 6 x? ? 56 xx ? 4 10 2 1 ? ?* x? 6 x? ?)( x?5 . 0 * =x? 5 . 0 |)( = = x x ex?q? ? += = + + 607. 1/6 . 0607. 1/ 11 1 kkk x k xxx ex k ? ?5 . 0

17、0= x? ? 1 x? 2 x? 3 x? ? 23 xx ? 4 10 2 1 ? ?* x? 3 x? ? ? + = += += + + + + + + kkk k kk k kk kk xxx xxx x xx xx 12 1 2 2 1 3 12 3 1 2 1 1 ? ?5 . 1 0= x? ? 1 x? 2 x? 3 x? ? 23 xx ? 4 10 2 1 ? ?* x? 3 x? ?axxf n =)(? 1 )( = n nxxf? ? += = + 11 1 ) 1( 1 n k k n k n k kk x a xn nnx ax xx?=k? ? n x a x

18、f=1)(? 1 )( + = n x na xf? += + a x xn n x xf xf xx n k k k k k kk ) 1( )( )( 1 ?=k? ? 13 ? n n a n a 1 )( + =? ?0)(=axxf n ? n k n k n k a n xa xa 2 1 )( lim 2 1 = + ? ?01)(= n x a xf? n k n k n k a n xa xa 2 1 )( lim 2 1 + = + ? ?13)( 3 =xxxf?0) 1 (f? 033)( 2 = xxf?06)( =xxf? ?0)2()2( ff?2 0= x? ?

19、2 0= x? ) 1(3 12 33 13 2 3 2 3 1 + = = + k k k kk kk x x x xx xx? ? 1 x? 2 x? 3 x? ? 23 xx ?x?0)( xf?0)( xf?0 xf?0)( C? 3 0 Cx ?0)()( 0 0 xfxf? k x? 3C ? ?), 0( 3 0 Cx ?0)2( 3 )( 3 2 0 3 2 0 2 0 3 3 2 0 2 03 1 + = + =xC x xC C x Cx Cx? ? 3 1 Cx ? 1 x? k x?3C ? ?0C?0 3 0 xfxf? k x? ? 14 3C ? ?)0 ,(3

20、0 Cx ?0)2( 3 )( 3 2 0 3 2 0 2 0 3 3 2 0 2 03 1 + = + =xC x xC C x Cx Cx? ? 3 1 Cx ? 1 x? k x?3C ? ?0=C? k k k kk x x x xx 3 2 3 2 3 1 = + ? ?Rx 0 ? ?1 0= x? 1 x? 2 x? 3 x? 4 x? 5 x? 6 x? 7 x? ? 67 xx ? 6 10 2 1 ? ?* x? 7 x? ?xxxfsin1)(=?0 0= x?1 1= x? ? ? ? * x? 4 x? ? 15 ? ? ? ? ? ?)()()()()()()( 2

21、211002 xlxfxlxfxlxfxL+=? ? 3 7 2 3 6 5 ) 12)(12( ) 1)(1( 4 )21)(11( )2)(1( ) 3(0 2 += + + + +=xx xxxx ? ?)()()()()()()()()( 332211003 xlxfxlxfxlxfxlxfxL+=? 123 )2)(1( 0 )2() 1( ) 3)(2( 3 )3()2() 1( )3)(2)(1( 2 + + = xxxxxxxxx ? 6 )2)(1( 2 ) 3)(2(3 3 ) 3)(2)(1( + = xxxxxxxxx ? ?)()()()()()()()()( 332

22、211003 xlxfxlxfxlxfxlxfxL+=? ?1214. 0=? ? ?0=k? ? ? k x?)( 0 xlx i n i k i = ? k x? i x ?n? ? ?ax =?bx =?)(xf? 0)()()( 1 + = ab ax bf ba bx afxL? ? )(max)(max 2 1 )()( ! 2 1 )()( 1 bxaxfbxaxfxLxf bxabxa = ? )(max)( 8 1 2 fab bxa ? ? 16 ?4 . 1 0= x?5 . 1 1= x?6 . 1 2= x? )54. 1 ()6 . 1 ()54. 1 ()5 .

23、1 ()54. 1 ()4 . 1 ()54. 1 ( 2102 lflflfL+=? ?+ + = )6 . 15 . 1)(4 . 15 . 1 ( )6 . 154. 1)(4 . 154. 1 ( 837. 1 )6 . 14 . 1)(5 . 14 . 1 ( )6 . 154. 1)(5 . 154. 1 ( 602. 1? ?94472. 1 )5 . 16 . 1)(4 . 16 . 1 ( )5 . 154. 1)(4 . 154. 1 ( 121. 2= +? ?)()()()()()()()()( 332211003 xlxfxlxfxlxfxlxfxL+=? ? 369

24、 )2)(3( 10 )3(36 )6)(3( 20 )9()6()3( )6)(3( + + + + = xxxxxxxxx ? ?)3242346323( 162 1 23 +=xxx? ? ? ?)()()(xgxfxF+=?)()()( 101nn xxxxxxx= + L? ? ? = + = + + = n j jn jj n j jn j n x xgxf x xF xxxF 0 1 0 1 10 )( )()( )( )( , L? ? = + = + += n j jn j n j jn j x xg x xf 0 1 0 1 )( )( )( )( ? ?, 1010nn

25、xxxgxxxfLL+=? ?c=, 0? ?1=? ? ? = + = + = n j njjjjjj j n j jn j n xxxxxxxx xf x xf xxxf 0 110 0 1 10 )()()( )( )( )( , LL L ? ? 17 ? i? i x ? i y ? i y? i y 2 ? i y 3 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?0 0= x?1=h?5 . 0=x?5 . 0 0 = = h xx t? ?5 . 0=t? 875. 018 6 )5 . 1)(5 . 0(5 . 0 14 2 )5 . 0(5

26、. 0 5 . 01)5 . 0( 3 = + +=N? ?5 . 2=x?5 . 0 0 = = h xx t?5 . 0=t? ? 375.3518 6 )5 . 1)(5 . 0(5 . 0 32 2 )5 . 0(5 . 0 5 . 04764)5 . 2( 3 = +=N? ? i? i x ? i y ? i y? i y 2 ? i y 3 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?-1,2? ? 5 . 1=t?5 . 0=x? ? 18 ? ? ? 1i x? i x ? 1+i x? ?)()()( ! 3 1 )( 11 2+ = ii

27、i xxxxxxfxR? ?),( 11+ ii xx?hxx ii = 1 ?hxx ii += +1 ? ? 3 4 34 11 4 2 393 1 3 2 6 1 )()(max 6 1 )( 11 h e hexxxxxxexR iii xxx ii = + + ? ? 53 4 10 39 h e ? 0658. 0h. ? 19 ? ? ? ? = 24 21 53 42 A? = 14 6 3 11 b? = 493 330 AAT? = 29 73 bAT? ?bAAXA TT =? = 4456 . 0 4555 . 2 X? ?xaaxy 1011 )(+=? ?8=n?2

28、6.15 8 1 = =i ix ?1556.30 8 1 2 = =i ix ?227.145 8 1 = =i iy ?93628.286 8 1 = =i iiy x? ? 1556.3026.15 26.158 1 0 a a ? 93628.286 227.145 ? ?916. 3 0= a?464. 7 1= a?916. 3464. 7)( 11 +=xxy? ? ? 2 bxay+=? ?5=n?5327 5 1 2 = =i ix ?7277699 5 1 4 = =i ix ?4 .271 5 1 = =i iy ?5 .369321 5 1 2 = =i iiy x?

29、? 72776995327 53275 b a ? 5 .369321 4 .271 ? ?973. 0=a?050. 0=b? 2 050 . 0 973 . 0 xy+=? ?t?s? ? 20 ? 2 ctbtas+=? 6=n?7 .14 6 1 = =i it ?63.53 6 1 2 = =i it ?= = 6 1 3 i it ?= = 6 1 4 i it ? 280 6 1 = =i is ?1078 6 1 = =i iis t?= = 6 1 2 i iis t? ? 63.53 63.537 .14 63.537 .146 c b a ? 1078 280 ? ?=a

30、?=b?=c? 2 ctbtas+=? ? ? ? at eII = 0 ?eatIIlglglg 0 =? ?Iulg=? 0 lg IA =?eaBlg=?BtAu+=? ?7=n?5 . 3 7 1 = =i it ?03. 2 7 1 2 = =i it ?8638. 0 7 1 = =i i u?08067. 0 7 1 = =i iiu t? ? 03 . 2 5 . 3 5 . 37 B A ? 08067 . 0 8638 . 0 ? ?7509. 0=A?2546. 1=B?635 . 5 0= I?889. 2=a? ? t eI 889. 2 635. 5 =? ? bx

31、 aey =?ebxaylglglg+=? ?yulg=?aAlg=?ebBlg=?BtAu+=? ? 21 ?5=n?5 . 7 5 1 = =i ix ?875.11 5 1 2 = =i ix ?0848. 4 5 1 = =i i y?2645. 6 5 1 = =i iiy x? ? 875.115 . 7 5 . 75 B A ? 2645 . 6 0848 . 4 ? ?4874. 0=A?2197. 0=B?072. 3=a?5057. 0=b? ? x ey 5057. 0 072 . 3 =? ?Xx =ln?bXaxy+=)(? ?4=n?178. 3 4 1 = =i

32、i X?60914. 3 4 1 2 = =i i X?4 .14 4 1 = =i iy ?9605.12 4 1 = =i iiy X? ? 60914 . 3 178 . 3 178 . 3 4 b a ? 9605.12 4 .14 ? ?496. 2=a?402. 1=b?xxyln402. 149. 2)(+=? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? 22 ? ? ? ?68394. 0 2 1 01 1 0 1 =+= eedxeI x ? ?63233. 04 6 1 0 2 1 1 1 0 2 =+= eeedxeI x ? ?: 08333. 0 12 1 )( 12 )( 0 3 1 = =ef ab R. 00035. 0 2 1 90 1 )( 2 )( 90 1 0 5 )4(5 2 = =ef a

温馨提示

  • 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
  • 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
  • 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
  • 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
  • 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
  • 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
  • 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。

评论

0/150

提交评论