计算机科学-汇编与接口首山雄(x86)试卷-汇编期末试卷09秋A-（含答案）

浙江大学2009-20江学年秋冬学期

《汇编与接口》课程期末考试试卷

课程号•：,开课学院：计算机学院

考试试卷：A卷J手卷

考试形式：开卷J闭卷允许带1本书和1本资料入场

考试日期：2010年1月日，考试时间：12()分钟

诚信考试，沉着应考，杜绝违纪。

考生姓名：学号：所属院系：

题序—•二三四五六七总分

得分

评卷人

请把第一至第三题的答案写在本页的答题纸上，第一至第三题的的评分以答题纸上的答案为准。

一.(10points)MarkTforcorrectinstructionordescription,markFforincorrectinstructionordescription.

F.MUL[SI]

T.ROLDWORDPTR[ECX],2

F.MOVES,59A2H

T.JCXZL2

F.IMULWORDPTR[ESP]

F.ADDAX,[SP+2]

F.MOVAX,BX+DI

F.ADD[DI],[BX]

F.INAX,320H

T.POPAD

二.(26points)Pleaseselectthebestchoiceforthefollowingquestions.

1.Indebug,ZRstandsfor“ZEROflagZFis1”.Whichonestandsfor“DirectionflagDFis1"indebug?

A.FWB.DNC.UPD.DO

【答案】:B

2.Inrealmode,SS=01H,DS=00H,BP=7EH,followingmemorydataisshownindebug.Afterinstruction“LES

BXJBP+4]'isexecuted,ESandBXwillbe.

0000:00807210A7007C10A700-4F0380058A038005

0000:0090AD061402A4F000F0-37051402116D00CO

A.ES=0214H,BX=F0A4HB.ES=107CH,BX=OOA7H

C.ES=F0A4H,BX=0214HD.ES=00A7H,BX=107CH

【答案】：C

3.“BUFDW1,2,3,4"isequaltoinmemorycontentsofBUF.

A.BUFDB1,0,2,0,3,0,4,0B.BUFDB(),1,0,2,0,3,0,4

C.BUFDD1000200H,3900400HD.BUFDD20001OOH.4000300H

【答案】：A

4.MOVAX,73E2H

ADDAX,EA3EH,thenOFandCFwillbe

A.OF=1andCF=1B.OF=1andCF=0

C.OF=0andCF=0D.OF=0andCF=1

【答案1D

5.SupposethattheoffsetaddressofvariableDATA!is100H,whichinstructionwilldo"EAXEBX+

2*ESI+70H”?

A：LEAEAX,DATA1[EBX+2*ESI-90H]

B：MOVEAX.OFFSET[EBX+2*ESI+70H]

C：MOVEAX,EBX+2*ESI+70H

D：MOVEAX,OFFSETdatal+EBX+2*ESI-90H

【答案】：A

6.MOVCX,OFFFFH

STC

ADCCX,0

thenCFandZFbe.

A.CF=OandZF=OB.CF=OandZF=1

C.CF=1andZF=OD.CF=1andZF=1

【答案】：D

7.MOVEAX,260

MOVECX,259

MULCLthenEAX=.

A.6B.67340

C.12D.780

【答案】：C

8.WhichICW1of8259Aselectscascadeoperationandedgetriggeredmode?

A：00011(X)1B.B：(MX)10010B.

C：0001000IB.D：000100I0B.

【答案】：c

9.WhichICW2setsIR2of8259AtointerruptvectorFAH?

A：0F8H.B：0EAH.

C：7CH.D：OFOH.

【答案】：A

10.WhichICW4of8259AselectsnormalEOIandnon-bufferedmode?

A：00011(X)1BB：0000001IB

C：00001001BD：0000000IB

【答案】：D

11.WhichOCWIof8259AwillmaskinterruptfromIR2pin?

A：100()01(JOBB：0100001OB

C：00000100BD：0000001OB

【答案1C

12.Whichcontrolwordfor8254setscounter1asacontinuoussquare-wavegenerator?

A：OIDOIOOBB：01110110B

C：101101I0BD：10111000B

【答案1B

13.Whichcontrolwordfor8254setscounter2asacontinuouspulsesgenerator?

A：01110101BB：0ill01(X)B

C：10110010BD：10110100B

【答案工D

三.(6points)Thefollowingfigureshowsthedetailconverting32-bitlinearaddressto32-bitphysicaladdress.

SupposeCR3=3ab82H,32-bitlinearaddrcss=03a28fd4H,pleasefillblanksbelow.

(1).10-bit“dir”;B,10-bit“page”=B,12-bit"offset^H.Here“dir",

“page”and“offset”arc3partsoflinearaddress.

(2).ThepointerAisa30-bitpagedirectoryentrypointer,anditpointstoa32-bitentryOfOeOdOcH.The32-bit

pointerA1isobtainedbyconcatenatepointerAand2-bit00,thenpc-intcrAl=H.

(3).ThepointerBisa30-bitpageentrypointer,anditpointstoa32-bitentry11223344H.The32-bitpointer

B1isobtainedbyconcatenatepointerBand2-bit00,thenpointerB1=H;

(4).32-bitphysicaladdress=H;

lObitWbit12bit

DirPageOffset32-bitlinearaddress

㊉:concatenate

30bit

pointerApointerB

FIGURE2-13Thepagingmechanisminthe80386throughPentium4microprocessors.

【答案】：

Thefollowingfigureshowstheprocesstoconvert32-bitlinearaddressto32-bilphysicaladdress.Suppose

CR3=3ab82H,32-bitlinearaddress=03a28fd4H,pleasefillblanksbelow.

(1).1O-bitdir=OOOOOOH10B.IO-bitpage=IQ0010I000B.12-bitoffset=0fd4H.Here“dir”,“page”and

“offset”are3partsoflinearaddress.

(2).ThepointerAisa30-bitpagedirectoryentrypointer,anditpointstoa32-bitentryOfOcOdOcH.The32-bit

pointerAlisobtainedbyconcatenatepointerAand2-bit00,thenpointerAl=3ab82038H-=0944-4GW

10111000

(3).ThepointerBisa30-bitpageentrypointer,,anditpointstoa32-bitentry11223344H.The32-bitpointerB1

isobtainedbyconcatenatepointerBand2-bit00,thenpointerB1=0ff)c08a0H;

(4).32-bitphysicaladdress=11223m4H:

四.(12points)Thefollowingprogramrunsunder32-bitVisualC++environment,eachintegertakes32bits.

Thefunctioncubc()readsacharacterchi.Ifchiisbetween'O'to'9',itisconvertedtoanumberbetween0to9,

thenthecubeofthenumberisobtainedandreturnedasthereturnvalueofcube();Otherwise,-1ofEAXis

returnedasihereturnvalueofcube().Pleasefilltheblankstofulfilltheabovefunction.

//Integerarraytable![101containscubeofnwherenis0to9.

inttablel[10]={0,1,8,27,64,125,216,343,512,729);

intcube()

{intch1;

chl=_getche();//readacharacterfromkeyboardandreturnittochi

_asm{

(1)____________

⑵____________

jbchrl

⑶

jachrl

subal,30h

(4)_____________

(5)_____________

movbl,al

moveax,tablel[ebx]

jmpcndl

chrl:(6)_____________

jmpendI

)

endl:;

【答案】

⑴moveax,chi；moval,ch1也算对，本行与下行互换也对

⑵cmpal,'0’

jbchrl

⑶cmpal」9'

jachrl

subaL30h

(4)shlal,2:salal,2也对

(5)xorebx,ebx:subebx,ebx也对：movebx.O也对

movbl,al

moveax,table![ebx]

jmpendl

chrl:⑹moveax,-1

五.(10points)Thefollowingpartialprogrammultiplieseach4-byteelementofarraydata1byeach4-byte

elementofarraydahi2,andstorestheproductinto8-by(eelementofarrayresult,i.e.

result[i]=data1[i]*data2[i].Eacharrayshas1()elements,andthemultiplicationrepeatstor1()times.Please

filltheblankstofulfilltheabovetarget.

.data

dataldd10dup(?)

data2dd10dup(?)

resultdq10dup(?)

.code

loop1:

mulda(a2[ebx*4]

movdwordptrresult[ebx*8+4],edx

loopioopl

【答案】

xorcbx.cbx

movex/0

loop1:moveax,datal|cbx*4|

mulda(a2[ebx*4]

movdwordptrresult|ebxk8Leax

movdwordptrresult[ebxf:8+4],edx

incebx

looploop1

六.(16points)A16550chipisusedinax86PC'sI/Oextendedcard.SupposeitsI/Obaseaddressesare

0D0-0D7HanditspinsAO,A1,A2connecttosystemaddressbusAO,A1,A2.Thefollowingprogram

initializesthe16550,Pleasefillappropriatevalueintoeachblankaccordingtothepromptbesideinstruction.

MOVAL,B；enableBauddivisorregisters

OUT0D3H,AL

MOVAL.；setBaudrateto57600

OUT0D0H,AL

MOVAL,___________

OUT0D1H,AL

;(5points,fill0or1ineachblankbelow)

MOVAL,000B；setlinecontrolregister:8-bit-data,evenparity,onestopbit

OUT0D3H,AL

MOVAL,0000011IB；enabletransmitterandreceiver

OUT0D2H,AL

;(4points,fill0or1ineachblankbelow)

MOVAL,0(X)()______B;enabletransmitterinterruptandreceiverinterrupt,thelatter

OUT,AL;isonlycorrectcharacterreceiptinterrupts.

;(2points,fill0or1ineachblankbelow)

MOVAL,000000__B;enable/DTRand/RTSpinof16550

OUT,AL

【答案】

MOVAL,1XXXXXXXB；enableBauddivisorregisiers

OUT0D3H,AL

MOVAL,20；setBaudrateto57600

OUT0D0H,AL

MOVAL,0

OUT0DIH,AL

;(5points,fill0or1ineachblankbelow)

MOVAL,0001101]_B；setlinecontrolregister:8-bit-data,evenparity,onestopbit

OUT0D3H,AL

MOVAL,000()0111B；enabletransmitterandreceiver

OUT0D2H,AL

;(4points,fill0or1ineachblankbelow)

MOVAL.00000X11B;enabletransmitterinterruptandreceiverinterrupt,thelatter

OUT0D1H,AL;isonlycorrectcharacterreceiptinterrupts.

;(2points,fill0or1ineachblankbelow)

MOVAL,000000J___LB;enable/DTRand/RTSpinof16550

OUT0D4H,AL

七.(20points)A82c55parallelcommunicationadapterisdesignedasaPC'sextendedcardwhichisinserted

inPCIbusslot.PC-1uses82C55-1ofitsadaptertoexchange8-bildatawith82C55-2ofPC-2.PC-1and

82C55-1worksymmetricallywith82C55-2andPC-2,andthisisdisplayedinthefollowingfigure.Each

82c55'sportAworksformode0output,whileitsportBworksformode1strobeinput.PortAofeach

82C55sends8-bi(datatoPonBof(heotherside.PinPC0ofeach82C55willgenerateainterruptafterit

receives8-bitdata,andtheinterruptsubroutineRECV_82C55_INTreceivesthe8-bitdata.

Theslave8259AofPCconnectsthePC0of82C55,itspinA0connectstotheA0ofsystemaddressbus

anditsI/Oaddressis0A0~0A1H;TheI/Oaddressesof82c55'sportA,B,Candcommandregisterare

300H,3()1H,302H,303H,respectively;

ProcedureSTORE_BUFFERstoresALintothereceivingbuffer,anddon'taffectanyregister'svalue.

Whenitexits,itsetstheZFto1toindicatethatthebufferisfull,ori(setstheZFto0toindicatethatthe

bufferisnotfull,ThedetailedinstructionsinSTORE_BUFFERisnotprovidedinthisexampaper.

ProcedureSENDhasa8-bitentryparameterinALanditsendsthedatainAL.Itfirstpollsthestatusof

82c55'sPC3whichconnectstotheIBFpinoftheopposite82C55.Onlywhentheopposite82c55'sINPUT

BUFFERisnotFULL,theprocedureSENDwillsendoutthedataandthenoutputsanegativepulseinthis

82c55'sPC4.

Notice:eachcommentusuallypromptsthefunctionofinstructionsnearthecomment.Oneblanktakes

onepointofscoreifscoreisnotmarkedbesidetheblank.

82c55-182C55-2

toIR7ofPC-Ts8259AtoIR7ofPC・2's8259A

PORT_AEQU300H

PORT_BEQU301H

PORT_CEQU302H

PORTCMDEQU303H

PIC1EQU0A0H

PIC2EQU0A1H

SIGNAL_EOIMACRO;signalEOI(EndofInterrupt)toslave8259A

OUTPIC1,AL

ENDM

;SET_STBuses8255'scommandbyteBtosetPC4(/STB)toval(0orI)

SET_STBMACROVAL;Heretheparametervalmustbe0or1

MOVAL,VAL;Constantexpressionmaybeusedhere.

ENDM

;TheProcedureINIT_82C55sets82C55commandbyteA:portA-mode0output,

;portB-modeIinput,PCOtoPC3-input;PC4toPC7—output

INIT.82C55PROCNEAR

MOVAL.B;fill0or1ineachblank.(4points)

SET_STBI;set/STBtoI(inactive)

STI

RET

INIT.82C55ENDP

SENDPROCNEAR

PUSHAX

LOOP1:_________________

INAL,DX

JNZLOOP1;ifIBF=1,gotoLOOP1tocontinuetest

MOVDX,PORT_A;outputALfromportA

;tooutputanegativepulse

MOVCX,8

LOOP2:LOOPLOOP2

SET_STB1;set/STBto1(inactive)

RET

SENDENDP

RECV_82C55JNTPROCFARUSESAXDX

;receivedata

CALLSTOREBUFFER;storeALintothereceivingbuffer

JNZL2;ifthereceivingbufferisfull,theCPUwillmask8259'sIR7

;ThemaskstatusofIRO-IR6willnotbeaffected.

OUTPIC2,AL

L2:________________

IRET

RECV_82C55_INTENDP

【答案】

PORT_AEQU300H

PORT_BEQU301H

PORT_CEQU302H

PORT_CMDEQU303H

PIC1EQU0A0H

PIC2EQUOAIH

.MODELSMALL

.STACK1024

,CODE

.STARTUP

MOVAL41H

CALLSEND

rEXIT

SIGNAL_EOIMACRO;signalEOI(EndofInterrupt)to8259A

MOVAL、20H;20H写成xxIOOxxxB的值也对;

OUTPIC1,AL

ENDM

SET_STBMACROVAL;Heretheparametervalmustbe0or1

;Use8255'scommandbyteiosetPC4(/STB)toval(1or0)

MOVDX,PORTCMD

MOVAL,OXXX1000BORVAL;Constantexpressionmaybeusedhere.

OUTDX,AL;OR改成+、xor也对